Question 28 on electromagnetics from GATE (Graduate Aptitude Test in Engineering) 2012 Electronics and Communication Engineering paper.
Q28. A transmission line with a characteristic impedance of 100 is used to match a 50 section to a 200 section. If the matching is to be done both at 429MHz and 1GHz, the length of the transmission line can be approximately
To answer this question, let us first understand the propagation in a transmission line, termination and the concept of impedance matching. The section 2.1 in Microwave Engineering, David M Pozar (buy from Amazon.com, Buy from Flipkart.com) is used as reference.
Consider a transmission line of very small length having the parameters as show in figure below.
is the resistance per unit length ,
is the inductance per unit length ,
is the conductance per unit length ,
is the capacitance per unit length.
Applying Kirchoff’s voltage law,
Applying Kirchoff’s current law,
Dividing the above equations by and taking the limit ,
If we assume that the inputs are sinusoidal, then the above equation can be re-written as
The solution to the above equations are,
The current on the line can be alternately expressed as,
where the characteristic impedance of the line is defined as,
The wavelength on the line is,
Loss less transmission line case
For a lossless transmission line, we can set .
Then the propagation constant reduces to, the characteristic impedance is and the voltage and current on the line can be written as,
Terminated lossless transmission line
Consider a transmission line terminated with load impedance as shown in figure below.
At the load , the relation between the total voltage and current is related to the load impedance
The reflection coefficient is defined as the amplitude of the reflected voltage to the incident voltage,
For no reflection to happen, i.e , the load impedance should be equal to the characteristic impedance of the transmission line. The above equation captures the impedance seen at the load .
The voltage and current on the line can be represented using as,
When looking from a point from the load, the input impedance seen is,
Substituting for ,
Special case when (and it’s odd multiples)
For the case when the input impedance seen is,
This result can be used to for impedance matching.
Quarter wave transformer
Consider a circuit with load and a line with characteristic impedance connected by a transmission line of characteristic impedance with length .
The input impedance seen is,
So if we choose , then the input impedance seen is which is the condition required for having no reflection i.e. .
One important aspect to note here is that is not guaranteed for all frequencies, but rather only for certain frequencies. The frequency dependence can be found by finding the frequencies for which .
Replacing where is the wave length corresponding to frequency ,
It can be seen that only for , the term resulting in reflection coefficient only for those frequencies.
Solving the GATE question
Applying all this to the problem at hand, we have , and .
Given that , we know that a quarter wave transformer is used to achieve impedance matching.
Now we also know that we need to match for two frequencies and .
The wavelength for each frequencies are,
The least common multiple of these two wavelength is, and the corresponding quarter wave length is .
Given than is not listed in the options, we can go for the next higher odd multiple i.e.
Based on the above, the right choice is (C) 1.58m
 GATE Examination Question Papers [Previous Years] from Indian Institute of Technology, Madras http://gate.iitm.ac.in/gateqps/2012/ec.pdf
D id you like this article? Make sure that you do not miss a new article by subscribing to RSS feed OR subscribing to e-mail newsletter. Note: Subscribing via e-mail entitles you to download the free e-Book on BER of BPSK/QPSK/16QAM/16PSK in AWGN.