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Bit Error Rate (BER) for BPSK modulation

by Krishna Sankar on August 5, 2007

In this post, we will derive the theoretical equation for bit error rate (BER) with Binary Phase Shift Keying (BPSK) modulation scheme in Additive White Gaussian Noise (AWGN) channel. The BER results obtained using Matlab/Octave simulation scripts show good agreement with the derived theoretical results.

With Binary Phase Shift Keying (BPSK), the binary digits 1 and 0 maybe represented by the analog levels and respectively. The system model is as shown in the Figure below.

Figure: Simplified block diagram with BPSK transmitter-receiver

Channel Model

The transmitted waveform gets corrupted by noise , typically referred to as Additive White Gaussian Noise (AWGN).

Additive : As the noise gets ‘added’ (and not multiplied) to the received signal

White : The spectrum of the noise if flat for all frequencies.

Gaussian : The values of the noise follows the Gaussian probability distribution function, with and .

Computing the probability of error

Using the derivation provided in Section 5.2.1 of [COMM-PROAKIS] as reference:

The received signal,

when bit 1 is transmitted and

when bit 0 is transmitted.

The conditional probability distribution function (PDF) of for the two cases are:

.

Figure: Conditional probability density function with BPSK modulation

Assuming that and are equally probable i.e. , the threshold 0 forms the optimal decision boundary.

  • if the received signal is is greater than 0, then the receiver assumes was transmitted.
  • if the received signal is is less than or equal to 0, then the receiver assumes was transmitted.

i.e.

and

.

Probability of error given was transmitted

With this threshold, the probability of error given is transmitted is (the area in blue region):

,

where,

isĀ  the complementary error function.

Probability of error given was transmitted

Similarly the probability of error given is transmitted is (the area in green region):

.

Total probability of bit error

.

Given that we assumed that and are equally probable i.e. , the bit error probability is,

.

Simulation model

Matlab/Octave source code for computing the bit error rate with BPSK modulation from theory and simulation. The code performs the following:

(a) Generation of random BPSK modulated symbols +1′s and -1′s

(b) Passing them through Additive White Gaussian Noise channel

(c) Demodulation of the received symbol based on the location in the constellation

(d) Counting the number of errors

(e) Repeating the same for multiple Eb/No value.

Click here to download Matlab/Octave script for simulating BER for BPSK modulation in AWGN chnanel.

Figure: Bit error rate (BER) curve for BPSK modulation – theory, simulation

Reference

[DIGITAL COMMUNICATION: PROAKIS] Digital Communications by John Proakis

Related posts

  1. Symbol Error Rate (SER) for QPSK (4-QAM) modulation
  2. Symbol Error Rate (SER) for 4-PAM
  3. Bit error rate for 16PSK modulation using Gray mapping
  4. Symbol Error Rate for 16PSK
  5. BPSK BER with OFDM modulation

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{ 371 comments… read them below or add one }

1 Siti naimah August 6, 2007 at 9:14 pm

Hey your BPSK theory and simulation is very useful.Do you have it for FSK modulation too?If you don’t mind please send to me. thanks.

Reply

2 srinivas March 5, 2009 at 7:50 am

close all
clear all
clc

N = 10^6 % number of bits or symbols
rand(‘state’,100); % initializing the rand() function
randn(‘state’,200); % initializing the randn() function

% Transmitter
ip = rand(1,N)>0.5; % generating 0,1 with equal probability
s = 2*ip-1; % BPSK modulation 0 -> -1; 1 -> 0
n = 1/sqrt(2)*[randn(1,N) + j*randn(1,N)]; % white gaussian noise, 0dB variance
Eb_N0_dB = [-3:10]; % multiple Eb/N0 values

for ii = 1:length(Eb_N0_dB)
% Noise addition
y = s + 10^(-Eb_N0_dB(ii)/20)*n; % additive white gaussian noise

% receiver – hard decision decoding
ipHat = real(y)>0;

% counting the errors
nErr(ii) = size(find([ip- ipHat]),2);

end

simBer = nErr/N; % simulated ber
theoryBer = 0.5*erfc(sqrt(10.^(Eb_N0_dB/10))); % theoretical ber
theoryBer1 = 0.5*erfc(sqrt(0.5.*(10.^(Eb_N0_dB/10)))); % theoretical ber

figure
semilogy(Eb_N0_dB,theoryBer,’b.-’);
hold on
axis([-3 10 10^-5 0.5])
grid on
legend(‘theory’);
xlabel(‘Eb/No, dB’);
ylabel(‘Bit Error Rate’);
title(‘Bit error probability curve for BPSK modulation’);

figure
semilogy(Eb_N0_dB,theoryBer1,’b.-’);
hold on
axis([-3 10 10^-5 0.5])
grid on
xlabel(‘Eb/No, dB’);
ylabel(‘Bit Error Rate’);
title(‘Bit error probability curve for BFSK modulation’);

In bfsk need double bit error rate to maintain the same avarage error rate in BPSK.
Feeel the difference..

Reply

3 Krishna Pillai March 5, 2009 at 8:34 am

@srinivas: It is not double the bit error. Infact the BER result with BFSK is 3dB poorer than BPSK. You may look @
http://www.dsplog.com/2007/08/30/bit-error-rate-for-frequency-shift-keying-with-coherent-demodulation/

Reply

4 kk November 7, 2009 at 1:44 am

Hey Krishna,

I need help regarding the simulation for the fig 1 for the IEEE paper:
Xiaodi Zhang and N.C. Beaulieu, “A Closed-Form BER Expression for BPSK Using MRC in Correlated CCI and Rayleigh Fading,” IEEE Trans. Communications, vol. 55, no. 12, pp. 2249-2252, Dec. 2007.

I am getting stuck with the simulation code. Can you please give a possible MATLAB code.

kk

Reply

5 Krishna Sankar November 8, 2009 at 8:58 am

@kk: Sorry, I do not have time to simulate that work. Good luck.

6 RAO March 12, 2010 at 2:08 am

I want to change the spatial resolution in dots per inches of an image.
Do u have any code regarding this problem?
if so plz send me
regards,

Reply

7 Krishna Sankar March 28, 2010 at 3:54 pm

@RAO: Sorry, no

8 pvt April 19, 2009 at 3:25 pm

do you have this program write by c++ ?
upload for me ???

Reply

9 Krishna Pillai April 21, 2009 at 5:45 am

@pvt: Sorry, I do not have the c code version

Reply

10 Researcher August 21, 2011 at 12:59 pm

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Matlab Code as well as the full paper will be sent to the individual after acceptance of paper from the conference.
Fee submission will be through Freelancer and elance. Candidate name will be included in Paper after milestone payment is released by him/her. Milestone payment is one which is in the custody of broker (Freelancer or Elance authority) and not in the custody of either party. After the paper is accepted and the client is conformed about the acheivement, only then he will be allowed to pay. Time is short so the policy of 1st come 1st serve will be entertained.

Reply

11 Krishna August 7, 2007 at 10:21 am

Thanks.
I have not checked for FSK modulation. Once I understand, hopefully will be try put together a post.

Reply

12 Sus September 19, 2007 at 9:32 am

Thanks a lot, your BPSK BER was very useful, i got to know about the errors i made when i did the code

Reply

13 Krishna September 23, 2007 at 9:23 am

@sus: Thanks :)

Reply

14 shareef January 23, 2008 at 7:08 pm

Dear Krishna,
Your simulation and theory prgram is very usefull and helpfull.
Could you please send me the syntax matlab comand of QPSK modulation for OFDM under multipath (i.e 3 path) fading.
Very thanks in advance.
shareef

Reply

15 Krishna January 24, 2008 at 8:09 pm

@shareef:
Thanks. The next post is planned to be on OFDM.

Reply

16 mariam May 9, 2011 at 6:29 am

thanks alot or this article . it really helped me alot .
and I am waiting the ofdm article.

Reply

17 Krishna Sankar May 24, 2011 at 5:20 am

@mariam: The post on BER for BPSK with OFDM modulation
http://www.dsplog.com/2008/06/10/ofdm-bpsk-bit-error/

Reply

18 David April 2, 2008 at 5:45 am

Hey,
I found theBit error curve for BPSK modulation – theory, simulation very useful. How do we demodulate , decode and compare it with the input signal

Reply

19 Krishna April 2, 2008 at 7:54 am

@ David: Thanks :)

Oh… were you unable to find the Matlab/Octave code? The link to the code is under the heading Simulation model.

Anyways, for BPSK it is simple. We observe the real part of the received symbol. If the real part is greater than 0 decode as +1, if the real part is less than 0 decode as -1.

Once we have the decoded symbols available, the number of differing symbols can be obtained by
nErr = size(find([ip- ipHat]),2);
Ofcourse, using find() is only one among the many different ways to compute this.

Thanks,
Krishna

Reply

20 babar April 11, 2008 at 6:42 pm

why are we using this term 10^(-Eb_N0_dB(ii)/20) in the code to get the final signal y. why cant we write y=s+n; ???????????????

Reply

21 babar April 11, 2008 at 6:46 pm

sorry for my previuos question i got it just after posting my previuos mesg…its coz we want to add the noise to the signal so we need to convert it to dB … right? thnx

Reply

22 babar April 11, 2008 at 6:48 pm

nope i didnt get it plz explain it a bit i shal be thankful

Reply

23 babar April 11, 2008 at 7:12 pm

hello! i am unable to understand the FOR loop operation in this code kindly explain a bit
thnaks in advance

Reply

24 Krishna April 12, 2008 at 7:44 pm

@babar:
The term 10^(-Eb_N0_dB(ii)/20) is for scaling the noise power as per the defined bit to noise ratio. The for loop is for computing the bit error rate for each Eb/N0 value.

Reply

25 srinivas March 11, 2009 at 5:31 pm

Hi..
Why you are multiplying ‘n’ with The term 10^(-Eb_N0_dB(ii)/20).
The didnot understans the concept behind this from the previous posts..

Reply

26 Krishna Pillai March 21, 2009 at 7:09 am

@srinivas: This is to scale the noise term ‘n’, so that we can obtain BER for different values of Eb/No. In the simulations, we define Eb/No in dB. To convert dB to define a scaling term for noise voltage, we use 10^(Eb_N0_dB/20).

Hope this helps.

Reply

27 Jhony May 13, 2008 at 5:54 pm

hi
hope you are doing fine…in the matlab program u have given here, why didnt you use the awgn matlab function to introduce the noise? why have we taken this formula? thanks

Reply

28 Krishna Pillai May 13, 2008 at 7:07 pm

@Jhony: Thanks. Am doing good. How are u? Glad to notice that you are not desperate now :)
Typically, to keep the code simple, I tried to avoid in-built functions. The randn() function + scaling the does the job. Thats all.

Reply

29 sitharam March 20, 2010 at 6:29 pm

hi krishna pillai i am doing project on viterbi decoder i want the matlab code for the viterbi decoder if u have the code please send me

Reply

30 Krishna Sankar March 28, 2010 at 2:07 pm

@Sitharam: Plz check out
http://www.dsplog.com/tag/viterbi/

Reply

31 Jhony May 13, 2008 at 7:11 pm

yeah ! trying to get hold of things slowly now… i hope u dnt mind me asking foolish and lots of Qz…
about the formula u uzed for awgn … i didnt get how it produces awgn … :(

Reply

32 Krishna Pillai May 13, 2008 at 7:21 pm

@Jhony: The randn() function generates a random variable having Gaussian distribution and the spectrum of this random variable is same across frequencies. Hence the name White Gaussian Noise (WGN).

This is then Added to the signal, hence the name Additive White Gaussian Noise (AWGN)….

Reply

33 Jhony May 13, 2008 at 7:27 pm

1/sqrt(2)*[randn(1,N) + j*randn(1,N)];

1/sqrt(2) ==> this is the scaling term?
j*randn(1,N) ==> this is to generate complex noise values?
I am thankful to u for helping me

Reply

34 Krishna Pillai May 13, 2008 at 7:34 pm

[randn(1,N) + j*randn(1,N)] generates complex Gaussian noise with mean 0 and variance 2. To make the variance to 1, the scaling factor of 1/sqrt(2) is used.

yes, the j term is for complex noise.

Reply

35 Jhony May 13, 2008 at 7:42 pm

thanks alot … u helped me alot i m very happy to learn all this … thanks once again … and plz keep helping me as i want to learn …

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36 Jhony May 15, 2008 at 6:46 pm

hi i hope you are in good health. Can you please tell me what a fading co-efficient is? and what does it signifies in few lines. I shall be very thankful to you.

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37 Krishna Pillai May 17, 2008 at 3:34 pm

@Jhony: If I may put very briefly, fading is the characteristic of the wireless channel. The channel (read enviornment) will vary with time and will exhibit different behaviour for differnt frequencies.

One of the most simplest and useful model of fading is to visualize it as filter whose coefficients change in time.

Ofcourse, this is a simplistic description. For a detailed overview, may I recommend chapter 2 from the book
Fundamentals of Wireless Communication – David Tse, Pramod Viswanath

Reply

38 marjano May 29, 2008 at 9:52 pm

please send me a source code for bpsk modulation in matlab

Reply

39 Krishna Pillai May 30, 2008 at 5:34 am

@marjano:
The link to the code is provided just above the figure. Anyhow attaching the link again
Please click here to downlod

Reply

40 marjano June 8, 2008 at 2:35 am

thank you but it is not exactly what I’m schearching about :/
I need code for modulation BPSK/PM or only BPSK

Reply

41 rahul June 11, 2008 at 8:57 pm

thanks a lot code is very useful

even i want a code using upsampling and pulse sampling in BPSK mod and downsampling and pulse sampling in BPSK demod

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42 Krishna Pillai June 12, 2008 at 5:39 am

@rahul: Thanks.
I believe you are looking for the code for transmit pulse shaing filter. You can look at the article and the code in the posts with the tag ‘pulse-shaping’
http://www.dsplog.com/tag/pulse-shaping/
That should help you get going.

Btw, what is pulse sampling?

Reply

43 Vinay Kumar July 29, 2008 at 12:43 pm

i m very satisfy to this site, bcause it is very hepful to me to make mmy project. if u have bpsk matlab code then send me .

Reply

44 Krishna Pillai July 30, 2008 at 6:11 am

@Vinay:Thanks.
The code is present in this post. Click here to download
http://www.dsplog.com/2007/08/05/bit-error-probability-for-bpsk-modulation/#Simulation%20Model

Reply

45 khurshid September 7, 2008 at 2:56 am

hi, hope every1 doing well. all the posts are very useful
thanks

Reply

46 antiwina September 8, 2008 at 8:16 pm

Hi,

I do not understand why a complex gaussian noise is required. The source here belongs to a BPSK modulation so I think, in practice we have a real noise, because we do just activate the in phase component and not the quadrature phase component.

Reply

47 Krishna Pillai September 9, 2008 at 9:39 am

@antiwina: You are right, the imaginary component is ignored. Infact if you see the simulation model, for demodulating the symbol, we use only the real part of the received signal.

However, our definition of noise is with a variance of N0/2 on the real arm and N0/2 on the imaginary arm.

Reply

48 ravi kumar September 16, 2008 at 11:06 pm

hi,
I do not understand why the BER curves for both BPSK and BPSK with OFDM are almost same where the BPSK with OFDM get
advantage i.e., decrease in BER in case of BPSK with OFDM.
So please give me the idea by differentiate the two curves and how the BER can be decreased with OFDM as soon as possible. iam waiting for u r response hopefully,thanku

Reply

49 farie September 17, 2008 at 2:07 am

hi,

Is there a demodulation matlab code which i can apply on most modulation methods like 8 psk, QPSK, 16QAM..etc.

Also do you have 8psk and 16 QAM modulation and demodulation codes in matlab?

thank you

Reply

50 Krishna Pillai September 17, 2008 at 4:48 pm

@ravi kumar: In AWGN, there should not be any advantage by using OFDM modulation. OFDM can be thought of as a simple up-conversion scheme where each information gets multiplied on different sub-carrier frequencies.

However, the BER difference should come in multipath simulations.

Reply

51 Krishna Pillai September 17, 2008 at 4:52 pm

@farie: The demodulation approaches for PSK is a different from QAM. For 16-PSK case, you can find two posts:

Symbol Error Rate for 16PSK
http://www.dsplog.com/2008/03/18/symbol-error-rate-for-16psk/

Bit error rate for 16PSK modulation using Gray mapping
http://www.dsplog.com/2008/05/18/bit-error-rate-for-16psk-modulation-using-gray-mapping/

You should be able to modify the code for 16-PSK to 8-PSK case.

For 16-QAM case, there are two posts on error rate computation:

16QAM Bit Error Rate (BER) with Gray mapping
http://www.dsplog.com/2008/06/05/16qam-bit-error-gray-mapping/

Symbol Error Rate (SER) for 16-QAM
http://www.dsplog.com/2007/12/09/symbol-error-rate-for-16-qam/

Hope this helps.

Reply

52 siddhartha September 28, 2008 at 1:22 am

hey krishna,
can you please help me with the case of DPSK

Reply

53 Krishna Pillai September 28, 2008 at 11:28 am

@siddhartha: I have written a post on Coherent deomdulation of DBPSK (Differential Binary Phase Shift Keying).
URI: http://www.dsplog.com/2007/09/30/coherent-demodulation-of-dbpsk/

Please check out. Hope this helps.

Reply

54 Micman October 8, 2008 at 1:02 am

Hello Krishna

Your simulation and theory prgram is very useful. Do you have the matlab code with qpsk symbols ? Would be great !

I want to compare the theoretical bit error curve for qpsk with a simulated bit error curve with a zero force equalizer. Can you please give me an advice of how to implement this.

Thank you in advance

Best regards

Micman

Reply

55 Krishna Pillai October 8, 2008 at 5:51 am

@Micman: Thanks. I have written a post on symbol error rate computation for QPSK in AWGN.
Symbol Error Rate (SER) for QPSK (4-QAM) modulation
URI: http://www.dsplog.com/2007/11/06/symbol-error-rate-for-4-qam/

Maybe that helps.

Reply

56 Hussien October 24, 2008 at 6:24 am

Hi Krishna

thank you very much for Your simulation and theory prgram, really they are very useful. Do you have the matlab code for OFDM with 16-QAM in AWGN and Rayleigh Channels.
Best Regards
Hussien

Reply

57 Krishna Pillai October 24, 2008 at 6:32 pm

@Hussein: Thanks. I do not have the codes, but I would think that it will be reasonable to extend the available simulation models to 16QAM case.
For 16-QAM in AWGN (without OFDM) you may look at the posts,
URI: http://www.dsplog.com/2008/06/05/16qam-bit-error-gray-mapping/
URI: http://www.dsplog.com/2007/12/09/symbol-error-rate-for-16-qam/

For extending them to OFDM, you may use the following posts as reference:
http://www.dsplog.com/2008/06/10/ofdm-bpsk-bit-error/
http://www.dsplog.com/2008/08/26/ofdm-rayleigh-channel-ber-bpsk/

Hope this helps.

Reply

58 poor grad student November 4, 2008 at 10:25 pm

Nice graphics and derivation.

Might want to consider using a separate integration variable for the definition of the erfc function, since the variable x was used for both the erfc argument and integration variable.

Perhaps just use ‘z’ or ‘y’ for the erfc integration variable, i.e., erfc(x) = 2/sqrt(pi) * Integral_x_inf { exp(-z^2/2)*dz } . This will then make it clear that the erfc argument ‘x’ is used to modify the integration limits, as opposed to the actual function being integrated.

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59 Krishna Pillai November 5, 2008 at 5:56 am

@grad student: Yeah, thanks for the suggestion. I agree that your proposal will make the text even more readable.

Anyhow, may I recommend to keep status quo given that the current text is not making it very difficult for the reader.

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60 banovic mladen November 9, 2008 at 1:17 am

exelent!

Reply

61 Sky Stradlin November 14, 2008 at 5:42 pm

for QPSK modulation, the variance is

sigma = 1/sqrt(10.0^(snr/10.0));
sigma=sigma/2;

Do you have any idea why it has to devide by 2?

Thanks alot

Reply

62 Krishna Pillai November 15, 2008 at 8:42 am

@Sky Stradlin: There is noise on the real and imaginary dimension. So, to make the total variance of the complex noise to unity, there is scaling by 1/2.

Reply

63 Ideal November 21, 2008 at 2:15 pm

Dear Krishna,

I have made a program for BER of BPSK in AWGN and Rayleigh fading channel, now I want to combine the both results in one graph, when I combine the results, the curve for rayleigh change but for awgn not change, can you give any idea what should i do, either i make a functions of both separately and call in one program or i should do something else?

anyone have idea about it plz comment

Reply

64 Krishna Pillai November 22, 2008 at 7:51 am

@Ideal: So you are able to plot both the curves using independent functions/scripts, but not able to combine them. Correct? This should be a reasonably easy aspect to resolve.
You can have a main script which generates the transmit symbol, Eb/No values etc. Pass it two function
(a) for awgn channel y = x + n,
(b) for rayleigh channel y = hx+n
Each function will count equalize, count the errors and report the number of errors for each value of Eb/No.

That should address your concern. Hope this helps.

Reply

65 Ideal November 24, 2008 at 4:57 pm

hi
Dear Krishna,

% receiver – hard decision decoding
ipHat = real(y)>0;
here what do you mean by hard decision decoding? plz reply in brief.

Reply

66 Krishna Pillai November 25, 2008 at 5:55 am

@Ideal: It just means that any value of y (real component) greater than 0 is assigned to 1 and if less than 0 is assigned as 0. This is called hard decision decoding.

Soft decisions – where we do not decide on what was transmitted based on the received constellation – are used typically when there is a decoder block (like Viterbi) following the constellation demapping.

Does this help?

Reply

67 Zoe December 22, 2008 at 12:56 am

Hi Krishna,
Thanks for the good information.

Could you shade light on the derivation of Sigma^2 = No/2 from correlation and spectral density of noise stand point?

Thanks,
Zoe

Reply

68 Krishna Pillai December 25, 2008 at 7:29 am

@Zoe: The term N0/2 corresponds to the spectral density of white noise. In typical systems, we experience white noise filtered by an ideal LPF. The variance of this filtered noise contributes to the noise term in the system.
You may look at chapter 9 in Communication Systems – An introduction to Signals and noise in Electrical Communication by A. Bruce Carlson, Paul Crilly, Janet Rutledge for further details.
Hope this helps

Reply

69 mak December 25, 2008 at 6:44 pm

Hi all

hope u all r f9

can any one help me for BER performance of adaptive modulation
(QPSK,4QAM,16QAM)in AWGN only I need to draw them in single graph

thankz in advance

Reply

70 Krishna Pillai December 26, 2008 at 6:17 am

@mak: As I understand from your query, you want to switch from one modulation scheme to another based on a defined error rate constraint. For eg, for lower SNR’ you would want to use BPSK, then move on to QPSK/4QAM for medium SNR’s and then hit 16QAM at high SNR’s.

I do not have any code explicitly doing this, but I would think that it would be reasonably easy to build using the following posts:
(a) Bit Error Rate (BER) for BPSK modulation
(b) Symbol Error Rate (SER) for QPSK (4-QAM) modulation
(c) Symbol Error Rate (SER) for 16-QAM
(d) 16QAM Bit Error Rate (BER) with Gray mapping

Hope this helps.

Reply

71 leth March 4, 2009 at 3:02 pm

dear sir

i want simulation for adaptive modulation

please if have such code send it to me

thanks

Reply

72 Krishna Pillai March 5, 2009 at 5:35 am

@leth; Sorry, I have not discussed adaptive modulation

Reply

73 manju January 26, 2009 at 2:51 pm

hi..how 2 generate -ve rectangular pulse 4 bin sym 0 & +ve rectangular pulse 4 bin sym 1

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74 Krishna Pillai January 27, 2009 at 6:24 am

@manju: You may use the following steps provided in the Matlab code snippet
clear all
N = 7; % number of bits
ipBit = rand(1,N) > 0.5; % random 1′s and 0′s
ipMod = 2*ipBit – 1; % converting 1′s to 1 and 0′s to -1
os = 4; % oversampling factor
ipMod_os = [ipMod; zeros(os-1, length(ipMod))]
ipMod_os = ipMod_os(:).’;
ipMod_filter = conv(ipMod_os,ones(1,os)/os);

Does that help?

Reply

75 wap January 30, 2009 at 12:18 pm

Hi krishna

can any one help me for code SIC (Successive Interference Cancellation).i will tray it for study…..

thanks………………..

Reply

76 Krishna Pillai January 31, 2009 at 6:38 am
77 bullah February 3, 2009 at 9:15 am

who can help me to find the formula bit error rate when coding for bpsk…?

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78 Krishna Pillai February 10, 2009 at 7:18 pm

@bullah: It depends on the coding which is applied. There are couple of posts discussing BPSK in AWGN with rate 1/2 convolutional coding.
Convolutional coding
http://www.dsplog.com/2009/01/04/convolutional-code/
Hard decision Viterbi
http://www.dsplog.com/2009/01/04/viterbi/
Soft input Viterbi
http://www.dsplog.com/2009/01/14/soft-viterbi/

Hope this helps.

Reply

79 invizible soul February 6, 2009 at 1:59 pm

hi hope you are fine. In your code you have scaled the noise with the term 10^(-Eb_N0_dB(ii)/20)
my question is why we do this?I mean why we need to scale the noise power as per the defined bit to noise ratio? Any references will help me a lot
fire back soon plz !!!

Reply

80 Krishna Pillai February 10, 2009 at 7:53 pm

@invizible soul: Sorry for the delayed response. I am traveling with out a reliable access to internet.

In this analysis, our objective is to analyze the impact of noise on the reliable decoding of BPSK modulation. To analyze the impact, we need to find out the performance (bit error rate) for different values of noise. Hence we scale the noise by noise power.

Hope this helps.

Reply

81 invizible soul February 13, 2009 at 6:59 pm

thanx alot krishna … sorry i missed it …

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82 santosh February 21, 2009 at 10:39 pm

@manju I got a better solution for your question.We need to untilmately multiply with standard deviation of noise so we get 20 there.

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83 T-dog March 24, 2010 at 12:55 am

SNRdB = 20 log (Asignal / Anoise)
-SNRdB = 20 log(Anoise / Asignal)
-SNRdB/20 = log(Anoise / Asignal)
10^(-SNRdB/20) = Anoise/Asignal <——— noise amplitude scaling factor.

Reply

84 Krishna Sankar March 28, 2010 at 1:50 pm

@T-dog: Thanks.

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85 wap February 9, 2009 at 5:46 pm

thanks khrishna with your help………..

i late reply n visit your site coz im busy….
how abaut this???
% BER_sic=sim_sic_fn(SNR_dB, P, Nb, code_matrix, chan_type)
% return bit error rate of the sic receiver in AWGN or rayleigh fading
%
% PARAMETER:
% SNR_dB=signal-ti-nopise ratio in dB
% P=power control vector, P(i)=transmitted power of i-th user
% Nb=number of transmitted bit
% code_matrix=matrix of the spreading code used
% chan_type=channel type(1=AWGN, 2=rayleigh fading channel)
%
% output:
% BER_sic=bit error of the sic receiver
%
function BER_sic=sim_sic_fn(SNR_dB, P, Nb, code_matrix, chan_type)

BER_sic=zeros(size(SNR_dB));
K=length(P); %number of user
N=size(code_matrix,2); %spreading factor

G(:,1)=code_matrix(33,:)’;
G(:,2:K)=code_matrix(1:K-1,:)’;

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86 Krishna Pillai February 10, 2009 at 8:12 pm

@Wap: Sorry, I did not get your question

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87 invizible soul February 9, 2009 at 6:06 pm

kindly reply me !!! i am still waiting … from where we get this expression:
10^(-Eb_N0_dB(ii)/20)

thnx

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88 nyna February 11, 2009 at 9:49 am

hello..
who will help me to understand the function of a filter in a block diagram of a basic communication system in BPSK?
What the purpose of finding the value of delay in the program of BPSK?

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89 Krishna Pillai February 12, 2009 at 6:44 am

@nyna: Filter is used for controlling the spectrum of the transmission. However, when doing the filtering we do not want to introduce ISI. Hence we typically go for filters like raised cosine etc. You may find some more details @
http://www.dsplog.com/2008/04/14/transmit-pulse-shape-nyquist-sinc-rectangular/
http://www.dsplog.com/2008/04/22/raised-cosine-filter-for-transmit-pulse-shaping/
http://www.dsplog.com/2008/05/01/eye-diagram-plot-matlab-raised-cosine-filter/

Hope this helps.

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90 invizible soul February 11, 2009 at 5:37 pm

hi … i think my username “invizible soul” has really made me invizible :) … as no one has answered my questions …
waitinn……

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91 Krishna Pillai February 12, 2009 at 6:22 am

@invizible soul:
I thought I replied already. Plz check my response @
http://www.dsplog.com/2007/08/05/bit-error-probability-for-bpsk-modulation/comment-page-2/#comment-5038

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92 nyna February 12, 2009 at 6:37 pm

thanks krishna…i’m really appreciate it..thanks so much

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93 mansi February 21, 2009 at 11:09 am

hi i have plotted the results for some coding
i just want is biterr with no coding

i.e. simply take msg, modulate add noise and demodulate

now find the biterr or symerr for oiginal msg and recovered msg

pls help as early as possible

Reply

94 Krishna Pillai February 22, 2009 at 2:42 pm
95 santosh February 21, 2009 at 10:40 pm

sdadasdad

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96 mohamed March 2, 2009 at 3:21 pm

The term 10^(-Eb_N0_dB(ii)/20) is for scaling the noise power as per the defined bit to noise ratio, why divided it by 20 >>??to convert it to voltage

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97 Krishna Pillai March 5, 2009 at 5:05 am

@mohamed: Yes, divided it by 20 is to convert to voltage.

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98 Einstein March 2, 2009 at 3:38 pm

I want to do a matlab simulation for the the GFSK. Plot the BER vs. EbNo.

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99 Krishna Pillai March 5, 2009 at 5:08 am

@Einstein: Sorry, I do not have Matlab simulations with GFSK. However, you may check up the post on BER for FSK in AWGN @
http://www.dsplog.com/2007/08/30/bit-error-rate-for-frequency-shift-keying-with-coherent-demodulation/

Hope this helps.

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100 pragya August 23, 2009 at 1:28 am

sir,
i want matlab programs for MCCDMA,whtever u hve on dis topic ,plz mail me as soon as possible,since MCCDMA is my thesis topic, but i m facing many prblms regarding matlab programs

thank u,
pragya

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101 Krishna Sankar August 24, 2009 at 4:59 am

@pragya: Sorry, I have not written Matlab models on MC-CDMA.

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102 bullah March 3, 2009 at 10:58 pm

hai..krishna..i want ask you the function of hamming code and bCh code..it because i already simulate the block using that coding…can you give me the formula for i’m calculate theory the bit error rate when using coding for i compare between theory and simulate…..also can you give me the graph ber vs Eb/No when coding..tq

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103 Krishna Pillai March 5, 2009 at 5:35 am

@bullah: Sorry, I have not discussed hamming codes or BCH codes till date. You may look at the posts describing convolutional coding and Viterbi decoding @
http://www.dsplog.com/tag/viterbi

Hope this helps.

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104 nyna March 8, 2009 at 7:08 pm

krishna can u help to understand more about the function of transmitter filter in BPSK and also how the ISI(intersymbol interference)will occur at transmitter filter??

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105 Krishna Pillai March 8, 2009 at 7:52 pm

@nyna: In the transmitter, we will first be converting bits into analog voltage (+1/-1 in the case of BPSK). However, we cannot transmit them as is, as it will occupy lots of spectrum (which is not desirable). Hence we need to do filtering. However, when doing filtering, we introduce ISI (inter symbol inteference) i.e each symbol may interfere with the next symbol and so on.

So, the question is: can we do filtering without introducing ISI? The answer is YES. There are simple filters like rectangular, ideal filter like sinc and practical filters like raised cosine, which can do the job. You may read more about them @
http://www.dsplog.com/2008/04/14/transmit-pulse-shape-nyquist-sinc-rectangular/
http://www.dsplog.com/2008/04/22/raised-cosine-filter-for-transmit-pulse-shaping/
http://www.dsplog.com/2008/05/01/eye-diagram-plot-matlab-raised-cosine-filter/

Hope this helps.

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106 shoumi March 10, 2009 at 1:25 pm

hi

I wanna matlab simulation code for AODV routing protocol. Can you help me ….

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107 Krishna Pillai March 21, 2009 at 7:01 am

@shoumi: Sorry, I have not worked on AODV protocol.

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108 Aditya March 13, 2009 at 11:48 am

Hey krishna,

I am new here. I find this site really very useful. Thanks for everything. I have a question reg BPSK sim. I did it with awgn function and I am not getting theo and sim graphs overlapping. Please answer this as soon as you get time . thanks

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109 Krishna Pillai March 21, 2009 at 7:44 am

@Aditya: You should have got similiar curves with awgn() function too. Is the slope of the graphs matching. Then its quite likely some power normalization issue.

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110 nyna March 13, 2009 at 6:54 pm

tq krishna…i understand it more than before..i really appreciate it..
however can i ask u bout the graph of BPSK between simulation and theoretical in term of BER vs SNR…
how the shape of graph become like that?

Reply

111 Krishna Pillai March 21, 2009 at 7:53 am

@nyna: The shape of the curve is determined by the probability of error which we have defined in the post.

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112 Matt K March 17, 2009 at 7:13 pm

Hi there, very useful site. I have a couple of questions regarding the BPSK:

1) Could you go in to a little more detail why you use complex noise vs. real. Although it doesn’t make a difference for BPSK, I’m assuming it actually will with other modulation methods. I didn’t see this in any of my textbooks.

2) In your code for the BPSK, you divide by 20. Shouldn’t that be 10? Given an SNR in dB, we get S/N0 = 10*log(SNR-dB / 10).
This gives N0 for a given signal power S.
The variance^2 = N0/2 and if we assume 0 mean, this gives us our AWGN, which is a random variable describing the noise amplitude. In my simulation, if I use 10 instead of 20, my results were way off, but 10 gives a perfect match with theory.

Thanks much,
Matt

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113 Krishna Pillai March 21, 2009 at 9:04 am

@ Matt K: My replies
1). Yes, for BPSK the noise component on the imaginary arm is ignored. To make the noise model same as with other modulation schemes, I kept it as complex.
2). The division by 20 is to convert the dB to scale the voltage signal. In my simulation model, the noise term n is a Gaussian random variable with mean 0 and variance 1. Therefore, I am scaling the noise voltage by 10^(-Eb_N0_dB(ii)/20)*n. Thats why I used 20.
In general, it depends on how one creates the model. Different people have different coding style. However, its the end result which matters. :)

Hope this helps.

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114 Nafis March 18, 2009 at 4:09 am

Thanks for your codes.It’s helped me a lot.But I want to replace Eb/N0 as SNR how can I do it.Could you pls help me urgently.

Thanking you

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115 Krishna Pillai March 21, 2009 at 9:07 am

@Nafis: For BPSK. Eb/N0 is same as SNR. Agree?

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116 shoumi March 18, 2009 at 2:47 pm

hi
How can i calculate throughtput for a multi-hop wireless network using matlab. please give me some suggestion ragarding this….

thanks

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117 Krishna Pillai March 21, 2009 at 9:10 am

@shoumi: Sorry, am not familiar with modelng multi-hop networks.

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118 Krishna Pillai March 21, 2009 at 9:11 am

@shoumi: Sory, I have not worked on modeling multihop wireless networks.

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119 Krishna Pillai March 21, 2009 at 9:12 am

@shoumi: Sorry, I have not worked on modeling multihop wireless networks.

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120 Shahrukh March 30, 2009 at 10:53 pm

Can someone pls provide me the matlab code for the below mentioned project work:

A randomly generated bit stream should be transmitted through an AWGN channel using BPSK. THe received symbols should then be converted again to a bit stream. The received bit stream should be compared with the original one to determine the total number of errors and hence the bit error probability. The probability of error should be calculated for several values of EB/No.
Once the above system is succesfully simulated an additional block of channel coding should be incorporated in the system. A (15,11) Hamming code should be used for this purpose. Simulation of this should be performed to increase the performance of the system.

RESULT to be DISPLAYED:

1. Bit error probability versus EB/No graph of BPSK
2. Bit error probability versus Eb/No graph of BPSK using equation
3.Bit error probability versus Eb/No graph of BPSK system with channel coding/decoding

The written code shuld allow the user to perform simulation for any number of bits and for any range of Eb/No.

THANKS..

Looking forward for your assitance.

Reply

121 Krishna Pillai April 4, 2009 at 4:26 pm

@Shahrukh: My replies:
1. Example Matlab code is provided in this post
2. The equation for BER for BPSK for a given value of Eb/N0 is provided in this post
3. I have not tried simulating with Hamming code. However, you may check the article on convolutional coding
with Viterbi decoding
http://www.dsplog.com/2009/01/04/viterbi/

Hope this helps.

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122 Shahrukh April 1, 2009 at 8:35 pm

pls sumbody help me out!!!…………:(….

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123 Murali Kris April 8, 2009 at 7:26 am

Hi Krishna,

All your posts have been very helpful and easily understandable. I was looking for a code that has all the modulations(bpsk,qpsk,mpsk,ask,bfsk,msk etc…) in a single program and to compare their BER, PSD curves. please let me know if you have any.

Thanks

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124 Krishna Pillai April 11, 2009 at 6:48 am

@Murali: No, I have not posted a single code putting all the BER curves in a single plot. However, I have discussed about multiple modulation schemes in dspdesignline.com
http://www.dsplog.com/2008/07/08/compare-bpsk-qpsk-4pam-16qam-16psk-64qam-32psk/
Hope this helps.

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125 R@y April 12, 2009 at 12:49 am

Hi, can you help with this issue,consider QPSK transmission over flat fading Rayleigh channels and a 1×2 system.The channels on the different diversity branches are assumed to have the same variance and the noise samples are assumed to be uncorrelated and circularly symmetric Gaussian variables with the same variance.
Consider three combining schemes: MRC, EGC and SC, for plot the BER versus the average signal-to-noise ratio (SNR).
I hope you can help me

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126 Krishna Pillai April 16, 2009 at 5:27 am

@R@y: Using BPSK modulation, I have written articles for a 1 transmit, 2receive system in a flat fading uncorrelated Rayleigh channel.
http://www.dsplog.com/2008/09/06/receiver-diversity-selection-diversity/
http://www.dsplog.com/2008/09/19/equal-gain-combining/
http://www.dsplog.com/2008/09/28/maximal-ratio-combining/
Hope this helps.

Reply

127 Einsein April 12, 2009 at 8:29 pm

Hello,

Do you know how you can build a zero-crossing detector or delay-and-multiply detector for the FSK.

Thanks.

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128 Krishna Pillai April 16, 2009 at 5:35 am

@Einsein: I have written a post on BER computation for FSK using coherent demodulation. That may provide some pointers
http://www.dsplog.com/2007/08/30/bit-error-rate-for-frequency-shift-keying-with-coherent-demodulation/
Hope this helps.

Reply

129 Student April 13, 2009 at 12:30 pm

Dear Krishna Pillai :
How can I change Amplitude Modulation to BPSK(y1 = ammod(x1,Fc1,Fs) to bpsk . I hope for a positive response.
clc
close all
clear all

t = 0:0.00001:0.001;

Fc1 = 1000;

Fs = 12000;
y1 = 1;
x1 = cos(2*pi*1000*t);

in_p = input(‘\nDo you want to enter user Y/N: ‘,’s');

if(in_p == ‘Y’ | in_p == ‘y’)
y1 = ammod(x1,Fc1,Fs);
end

Reply

130 Krishna Pillai April 16, 2009 at 5:40 am

@Student: Sorry, I do not have the functions ammod(). Maybe the post on symbol error rate computation using 4-PAM be of help.
http://www.dsplog.com/2007/10/07/symbol-error-rate-for-pam/

Reply

131 Oluwafemi April 16, 2009 at 9:05 pm

Please i dont know how i can acess the e book.
I am working on super orthogonal space time turbo codes in OFDM systems and will need this e book .Thank u

Reply

132 Krishna Pillai April 18, 2009 at 8:11 am

@ Oluwafemi: I had mailed you the instructions. Please check your inbox.

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133 Student April 29, 2009 at 5:30 pm

Dear Krishna Pillai
How can I correlate demodulated signal and binary code in BPSK ?I mean reteriving back of binary code.

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134 Krishna Pillai April 30, 2009 at 5:44 am

@Student: At the receiver, using hard decision decoding you can find out whether the received symbol is +1 or -1. Then we can easily map to +1 to bit1 and -1 to bit0 respectively.

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135 bwk April 29, 2009 at 6:46 pm

Hi,
I would need equations of bit error probability for this modulation technique: MSK, GMSK, QPSK, ASK. Do you know it?
Thank for answer

Reply

136 Krishna Pillai April 30, 2009 at 5:46 am

@bwk: I have not tried simulating MSK/GMSK. Something to do in future. However, you may look at the posts:
a/. Symbol error rate for QPSK
http://www.dsplog.com/2007/11/06/symbol-error-rate-for-4-qam/
b/. Symbol error rate for 4-PAM
http://www.dsplog.com/2007/10/07/symbol-error-rate-for-pam/

Reply

137 Student April 30, 2009 at 9:37 am

Dear Krishna Pillai
Thanks a lot for ur suggestion.When I domodulate following code it gives a simple sine wave.How can I demodulate it?
close all
b=[0 1 1 0 1 0 1 0 0 1];
fc=10;
n=1;
while n<=length(b)
if b(n)==0 %0 is -1
tx=(n-1)*0.1:0.1/100:n*0.1;
m=(-1)*sin(2*pi*fc*tx);
plot(tx,m,’LineWidth’,1.5);grid on;
else
tx=(n-1)*0.1:0.1/100:n*0.1;
m=(1)*sin(2*pi*fc*tx);
subplot(2,1,1)
plot(tx,m,’LineWidth’,1.5);grid on;
hold on;
end
n=n+1;
end
title(‘BPSK modulated Signal’)

How coherent detection can be applied on it?
Thanks in advance.

Regards,

Reply

138 Krishna Pillai May 12, 2009 at 4:39 am

@Student: hmm..let me try to understand. For bit0 you are sending -ve sine wave, and for bit1 you are sending +ve sinewave right. At the receiver you cmay undo the effect of the sine wave by multiplying the received signal with the sine wave and taking the mean. Then perform hard decision decoding on that signal.
Does that help?

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139 Elias April 30, 2009 at 1:42 pm

Bonjour
Je cherche des programmes MATLAB pour la gƩnƩration des codes LDPC Quasi Ciclique
Alors si vous avez des programmes ou des liens utiles priĆØre de me les envoyer a ce mail
eliasknopfler@hotmail.com
Je vous remercie

Reply

140 Krishna Pillai May 12, 2009 at 4:42 am

@Elias: Sorry, I have not discussed LDPC coding till date. Hopefully in the near future.

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141 bowang May 5, 2009 at 7:07 pm

wah ini dia data yang aku cari-cari akhirnya menemukan yang namanya BPSK
thanks yaaaaaaaaaaaaaaaa…
sip sip sip sip

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142 Krishna Pillai May 12, 2009 at 5:10 am

@bowang: good

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143 Student May 6, 2009 at 8:17 am

Dear Krishna Pillai :
Please reply my question dated April 30, 2009 at 9:37 am.

Regards,

Reply

144 Krishna Pillai May 12, 2009 at 5:16 am

@Student: I just did. Hope you are happy with the response. Sorry for the delay in my reply. Good luck.

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145 Student May 12, 2009 at 6:04 pm

Dear Krishna Pillai

Thank u. I am really happy and trying to do what u have suggested.

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146 kanchana May 15, 2009 at 1:09 pm

hello sir

i am doing my project in cdma can u tell me the purpose of rake receiver and details about maximum ratio combining

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147 Krishna Pillai May 20, 2009 at 5:24 am

@kanchana: Well, I have not quite discussed about cdma in the blog till date. Hope to do so in future.
I beleive the intent of the rake receiver is to coherently combine information from all the multipath taps such that the bit-error rate is reduced. I have posted about maximal ratio combining for a 1 transmit 2 receive receive diversity case.
http://www.dsplog.com/2008/09/28/maximal-ratio-combining/
Though the context is different, I think you should be able to adapt that to suit your needs.

Good luck.

Reply

148 Ideal May 27, 2009 at 12:57 pm

Dear Krishna
how can we simulat the angular delay profile. can you just give me simple example plz?

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149 Krishna Pillai May 31, 2009 at 8:31 pm

@Ideal: Sorry, am not familiar with modeling angular profile.

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150 aam_log May 28, 2009 at 7:26 pm

Dear krishna
I hope you are fine. I am in 5th semister of my bachelors of telecommunications. So I am new to this field and facing lots of difficulties. I find your site very impressive and have joined it recently. Can you kindly tell me why we normalize things? thnx

Reply

151 Krishna Pillai May 31, 2009 at 8:36 pm

@aam_log: Good luck for your studies. We normalize, because we want to have a fair comparison when trying out different approaches….

For eg, if we are comparing 100apples with 100grapes, we would want to know the price per kilogram, no?

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152 maya May 29, 2009 at 5:38 pm

HEY sir can u plzz help me in getting the main concept of vblast detection scheme,,i am not geting how it estimates the data…

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153 Krishna Pillai May 31, 2009 at 8:43 pm

@maya: Well, understanding V-BLAST with Zero Forcing equalization is the most simplest way. From our linear algebra days, we know that if we have two unknowns, we need atleast two equations to solve them.

Adapting them to MIMO V-BLAST, the two unknowns are the unknown transmitted data, and the two equations are provided by the two receive antennas. Just putting a simple example,
y1 = a*x1 +b*x2
y2 = c*x1 + d*x2
where
y1, y2 are received symbols
a,b,c,d are channel taps (which are known) and
x1, x2 are unknown transmit symbols.

The following post might be of bit more help.
http://www.dsplog.com/2008/10/24/mimo-zero-forcing/

Hope this helps.

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154 maya May 31, 2009 at 10:26 pm

thnx for ur response,,it means dat u need to have atleast 2 no of rcvd bits at da reciever 2 be compared..but my confusion is that how to use vblast when i am considering diversity mimo,where i have to use combing technique first?? can i implement vblast in dat case or not???

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155 Krishna Pillai June 1, 2009 at 5:22 am

@maya: Well, try to write the equation in matrix form. For eg, consider a simple case where we have two transmit antennas and 3 receive antennas. The matrix dimensions will be of:
y = Hx + n, where
y – received symbols of dimension [nrx x 1]
H – channel matrix of dimension [nrx x ntx]
x – transmit symbols of dimension [ntx x 1]
n – noise of dimension [nrx x 1]

If we write the zero forcing equalizer for this equation, then we can find that
W = (H^H*H)-1*H^H

This equalization also performs the diversity combining via Maximal Ratio Combining way. Does this help?

Reply

156 M S Sasidhar June 2, 2009 at 1:15 pm

hi every body can any one tell me the code for “signal to noise ratio using autocorrelation in time domain” using MATLAB

thanks in advance…..

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157 Krishna Pillai June 7, 2009 at 1:57 pm

@sasidhar: The question is not clear to me. Can you please provide some more details….

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158 Eduardo Solano June 4, 2009 at 1:55 am

i have a question..
i have a program wich makes bpsk modulation and i need to show Bit error curve for BPSK modulation – theory, simulation (both) as you do here in this page at top.

ok but there is something that happens with simulation curve that appears a little bit more to the right side of teoric curve.

i wanna know a reason why does it happens.

Reply

159 Krishna Pillai June 7, 2009 at 2:11 pm

@Eduardo Solano: If the simulation curve is happening to the right of the theoretical curve, it typically means that you are adding more noise than what is required. Also make sure that you simulate for atleast 10^6 bits, such that you get statistically accurate results.

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160 Assad Abbasi June 6, 2009 at 1:03 am

Dear Krishna, thanks for your codes. I am plotting BER for BPSK and QPSK but i am not getting same BER curve. As it should be same for both. I know that the plot should be BER vs EbN0. But how to get EbN0 from SNR? In your codes you have written Eb_N0_dB, is this EbN0?? I think it is SNR. If this is EbN0, why am i not getting same curve for BPSK and QPSK… Please Help

Reply

161 Krishna Pillai June 7, 2009 at 2:31 pm

@Assad Abbasi: Well, as you said BER vs EB/N0 curve for both BPSK and QPSK should be comparable. In general,
Es/N0 = kEb/N0, where k = log2(M) and M is the constellation size.

I have discussed a post comparing BPSK, QPSK, QAM etc @ http://www.dsplog.com/2008/07/08/compare-bpsk-qpsk-4pam-16qam-16psk-64qam-32psk/
Hope this helps.

Reply

162 Mathew June 8, 2009 at 2:37 am

Have you got any code to 16-apsk?

Reply

163 Krishna Pillai June 8, 2009 at 6:02 am
164 Mathew June 9, 2009 at 6:21 pm

I mean 16-apsk modulation sth like that http://commons.wikimedia.org/wiki/File:Const_16APSK.gif

Reply

165 Krishna Pillai June 10, 2009 at 5:25 am

@Mathew: Sorry, I have not tried simulating 16-APSK. Thanks to you, I just realized that it is used in DVB-S2. I will try to do a write up in future.

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166 RAO June 9, 2009 at 8:12 pm

Hello.

I need matlab code for DPSK and also its BER.

regards,

Reply

167 Krishna Pillai June 10, 2009 at 5:26 am

@RAO: I have a post on Coherent Demodulation of DBPSK
http://www.dsplog.com/2007/09/30/coherent-demodulation-of-dbpsk/
Hope this helps.

Reply

168 RAO June 10, 2009 at 3:58 pm

thanks Krishna.

Actually i need matlab code for non-coherent detection of either bpsk or dpsk and also corresponding BER vs Eb/No plots.

regards,

Reply

169 RAO June 10, 2009 at 4:00 pm

sorry. in addition, i want noncoherent detection of bpsk or dpsk for both AWGN AND RAYLEIGH channel.

regards,

Reply

170 Krishna Pillai June 11, 2009 at 4:50 am

@RAO: Sorry, I have not tried simulating non-coherent detection dpsk.

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171 RAO June 12, 2009 at 5:12 pm

Thanks Krishna for reply.

I want to plot BER vs Eb/No for MPSK and MDPSK. Can u help me in this regard ?

Also do u have code for FSK coherent and non-coherent with corresponding BER vs Eb/No plot?

172 Olguin June 10, 2009 at 2:55 pm

first of all, thanks a lot for ur job, it“s really useful for all the DSP internet communty.

here my question, I“m carrying out some simulations on simulink. modulating BPSK, spreading w/ gold code, going through awgn, despreading and demodulating BPSK, and at the end I measure the BER.

using simple BPSK mod/demod provided in the communications block set, IĀ“ve got a relative high BER (.5), then I found the so-called “Real BPSK mod/demod” which basically a “real-imag to complex”/”complex to real-imag” block is added to the BPSK mod/demod, and the resulting BER is around .1.

I“ve tried to find unsuccessfully an explanation to this on technical literature.

maybe you know something about that.

Thanks in advance.

Reply

173 Krishna Pillai June 11, 2009 at 4:49 am

@Olguin: Well, having BER of 0.5 means there is some error in the simulation code. If you wish you refer the post on
(a) BPSK BER with matched filtering
http://www.dsplog.com/2009/05/08/ber-with-matched-filtering/

Hope that helps you to debug the code.

Reply

174 RAO June 13, 2009 at 12:30 am

Thanks Krishna for reply.

I want to plot BER vs Eb/No for MPSK and MDPSK. Can u help me in this regard ?

Also do u have code for FSK coherent and non-coherent with corresponding BER vs Eb/No plot?

Your early response will b highly appreciated.

Reply

175 Swetha June 18, 2009 at 10:24 am

Hi All,

Can any one guide me to good source…
How to calculate Bit error probability for given SNR, any modulation technique with error correcting codes(convolution coding).

Please give some information on this.

-Thanks
Swetha

Reply

176 Krishna Pillai June 21, 2009 at 12:48 pm

@Sweta: The book Digital Communications by John Proakis is a good reference

Reply

177 komari June 22, 2009 at 11:20 pm

please can you tell me what does this instruction do exactly

ipHat = real(y)>0;

is it equivalent to
if (real(y)>0)
ipHat = 1
else
ipHat = 0
end

Thanks

Reply

178 Krishna Pillai June 23, 2009 at 4:40 am

@komari: Your explanation is correct.
As you may be aware, Matlab provides lots of ‘quick one liner’ ways to do things. :)

Reply

179 Ali June 23, 2009 at 8:36 pm

Ok Thanks very much krishna :)

Reply

180 ahmed June 23, 2009 at 8:41 pm

Hello
i just want to ask about this statement in the code
ipHat = real(y)>0;
what exactly it do
is it equivalent to
if real(y)>0
real(y)=1
else
real(y)=1
end

Thx

Reply

181 Krishna Pillai June 25, 2009 at 5:47 am

@ahmed: No, your explanation is not correct. As komari mentioned, it is equivalent to
if (real(y)>0)
ipHat = 1
else
ipHat = 0
end

Reply

182 jo June 23, 2009 at 9:14 pm

i wanna know what does this statement exactly do
ipHat = real(y)>0;

is it equivalent to
if real(y)>0
real(y)=1
else
real(y)=0
end

thanks

Reply

183 Krishna Pillai June 25, 2009 at 5:48 am

@jo: Plz refer the reply provided to ahmed

Reply

184 Srinivas June 27, 2009 at 10:13 pm

Can anyone help me out with a matlab code for this.
For ISI channel with L real coeffnts and BPSK modulation write a Viterbi algo decoder with decoding delay >0

Reply

185 Krishna Pillai June 30, 2009 at 5:10 am

@Srinivas: I have not done MLSE equalization in multipath channel, but plan to do that in near future.

Reply

186 Srinivas June 27, 2009 at 10:25 pm

Can someone help me out with a Matlab code for this.
For ISI chanell with real coeffnts and BPSK modulation write a Viterbi algo decoder with decoding delay >0 (say ‘delta’)

plot BER vs SNR for varying ‘delta’s

Reply

187 Moon June 29, 2009 at 5:39 pm

Thank you for your effort…
i have some question
1. y = s + 10^(-Eb_N0_dB(ii)/20)*n;
2. theoryBer = 0.5*erfc(sqrt(10.^(Eb_N0_dB/10)))
i don`t know why Eb_N0_dB(ii) has minus value…
and
At first term,^(-Eb_N0_dB(ii) is divided by 20 but, at second term Eb_N0_dB is divided by 10.
Why Eb_N0_dB is divided by diferrent value??
My question is very poor, nevertheless i will wait for your comment
Have a nice day

Reply

188 Krishna Pillai June 30, 2009 at 5:14 am

@Moon: My replies
1/ Before this scaling, the signal term s and the noise term n has the same variance of 1. The term -Eb_N0_dB reduces the noise variance
2/ The scaling is happening on the noise voltage signal, hence the factor of 1/20. In the theoretical equation, note that there is a square root term outside the 1/10 factor. This is equivalent to having 1/20 factor. Agree?

Reply

189 BOUHAFS July 1, 2009 at 10:18 pm

please simulation for BER MIMO (2,2)

Reply

190 Krishna Pillai July 2, 2009 at 5:24 am

@BOUHAFS: Please refer to the post
http://www.dsplog.com/2008/10/24/mimo-zero-forcing/

Reply

191 Vijay July 7, 2009 at 11:05 am

Hi, I am want to plot the pdf for various SNR(Symbol Error) for various modulation schemes. Do you have matlab code for it.

The derivation in this link is SER Vs SNR, How to change the SER to PDF(of SNR)?

Thanks in advance

Reply

192 Krishna Pillai July 15, 2009 at 4:42 am

@Vijay: I have written an article on error rate for various modulation schemes in dspdesignline.com @
http://www.dspdesignline.com/howto/208801783;jsessionid=3ISGUXHINOVIAQSNDLRSKHSCJUNN2JVN?pgno=1

Further, you may also check out the post
http://www.dsplog.com/2008/10/01/download-free-e-book/

Reply

193 leth July 18, 2009 at 9:04 am

hi
i need matlab code for adaptive modulation from BPSK,QPSK,16QAM,64QAM

so if you have not such code, i hope to guide me how to make it , as you know for low SNR we use like BPSK and for high SNR use like 64QAM

so how to make this via matlab?

regards

Reply

194 Krishna Pillai July 19, 2009 at 8:58 am

@leth: I do not have a code combining BPSK/QPSK/QAM etc to do adaptive modulation. However, you may find individual posts describing these modulation schemes @ http://www.dsplog.com/2008/10/01/download-free-e-book/
As you said, one way to make an adaptive modulation scheme is to define a BER threshold (lets say 10^04) to switch from one modulation scheme to another.

Reply

195 leth July 18, 2009 at 10:07 am

hi can you tell me how to make adaptive modulation ?

thanks

Reply

196 gdkorde July 25, 2009 at 6:01 pm

plz help me for changing code rate and delay spread in bpsk modulation used in hiperlan/2

Reply

197 Krishna Pillai July 28, 2009 at 4:29 am

@gdkorde: Quick questions:
1/ What is the coding technique used ? Convolutional coding?
2/ What is the model of the multipath channel? Exponential model?

Reply

198 sam July 30, 2009 at 2:29 pm

hi kirishna pillai
i need simulink’s (matlab) block for accunting BPSK BER
thanks

Reply

199 Krishna Sankar July 31, 2009 at 4:53 am

@sam: Sorry, I do not have Simulink.

Reply

200 Diego July 31, 2009 at 5:54 am

Hi, my english is not very good looking, but…what is the noise variance for 16QAM and 64QAM?, AWGN channel.

Reply

201 Krishna Sankar August 5, 2009 at 5:39 am

@Diego: The noise variance is independent of the modulation scheme. However, I think you might be looking for error rate for different modulation schemes for a given value of noise variance. You may refer posts:
http://www.dsplog.com/2008/06/05/16qam-bit-error-gray-mapping/
http://www.dsplog.com/2008/03/29/comparing-16psk-vs-16qam-for-symbol-error-rate/
http://www.dsplog.com/2007/12/09/symbol-error-rate-for-16-qam/
http://www.dsplog.com/2008/07/08/compare-bpsk-qpsk-4pam-16qam-16psk-64qam-32psk/

Reply

202 sam August 1, 2009 at 1:51 pm

hi everybody
i need simulink’s (matlab) block for accunting BPSK BER

Reply

203 Alex August 14, 2009 at 5:00 am

Hi Pillai

I would like to ask you a simple question. I am trying to make a simple simulation using a matlab. It is about that one node using SF(spreading factor)=2, and another node using SF = 8 (orthogonal to each) are encoding the data and sending to one node (asynchronous network) with same power but from different distance at the same time. how can i simulate it? when decoding at the receiver, it uses same ovsf code as the node using SF = 8.

Thanks in advance.

Reply

204 Krishna Sankar August 14, 2009 at 5:15 am

@Alex: Well, let me try to write the pseudo code for this case
y1 = x1*code1; % code with SF=2
y2 = x2*code2; % code with SF=8
n = noise; % AWGN noise, lets take mean=0, variance = 1
r1 = y1*scaling1; % scaling factor for first signal
r2 = y2*scaling2; % scaling factor for second signal
r = r1+r2+n; % receiver collects both signals corrupted by noise
x2Hat = r*code2 % receiver tries to correlate r with code2 to recover x2.

Makes sense?

Reply

205 I.Selvadenniz August 17, 2009 at 5:51 pm

hi,can any one help me to derive BER for physical layer network coding(PNC) modulation scheme…:-)

Reply

206 Krishna Sankar August 18, 2009 at 3:53 am

@Selvadenniz: Sorry, have not studied PNC coding.

Reply

207 tommy October 16, 2009 at 5:19 pm

hiii… you have BER for physical layer network coding(PNC) modulation scheme….

Reply

208 Krishna Sankar October 17, 2009 at 4:15 am

@tommy: Sorry, no

Reply

209 Tito August 27, 2009 at 5:28 pm

Hi Krishna,

I am working on Forward error correction codes. I have plotted the BER performance curve for Reed solomon codes using BPSK modulation over an AWGN channel from EbNo 0 – 1 . However, the curves are overlapping at the begining between EbNo values 0 and 1 and also in the middle.

Also the curves for convolutional codes overlap at the begining between 0 and 1. and also in the concatenated codes.

Could you please give me a detailed explanationc on the reason why the overlapping occurs and the significance.

The RS codes used were RS(255,191), RS(255,223), RS(255,239) and RS(255,247).
Thanks, hope to hear from you soon.

Reply

210 Krishna Sankar September 7, 2009 at 5:13 am

@Tito: Firstly, a clarification. When you mentioned about “curve-overlapping”, I guess you meant that – “with coding, the BER becomes poorer than no coding for very low values of Eb/N0″. Agree?

At-least with respect to convolutional codes, I think it can be attributed to the large number of errors in received coded bits, which makes the Viterbi algorithm go haywire.

Reply

211 Tito September 8, 2009 at 7:28 pm

Thanks that is exactly what i mean. Why does this occur.
And i also have an curve RS curve with and without an interleaver, these curves are overlapping at two points. Why does this occur.

Reply

212 thenmozhi September 5, 2009 at 9:30 pm

can you send me the matlab coding for physical layer network coding modulation

Reply

213 Krishna Sankar September 9, 2009 at 5:43 am

@thenmozhi: Sorry, I do not have matlab code for physical layer network coding modulation

Reply

214 Anvesh September 13, 2009 at 11:37 am

Thanks a lot, man.
Was very useful.

Reply

215 Hung October 7, 2009 at 8:00 am

hello Krishna Pillai!
I’m a student in Ho Chi Minh City, Viet Nam. I’m searching about “the impact of real channel over MiMo system”. your code is useful. So, we assume that receiver is unknown h matrix and we must explore channel by channel estimation. Do you help me?
Hope you will response me!

Reply

216 Krishna Sankar October 8, 2009 at 5:35 am

@Hung: Yes, the receiver is trained to estimate the MIMO channel by sending known preamble.

Reply

217 ahmed October 8, 2009 at 12:42 am

I knew that OFDM technique, improve the BER performance in frequency selective fading channel, Can you help me in writing code using matlab program show that , I have probem in how write code for frequence selective fading.
Thank you .

Reply

218 Krishna Sankar October 8, 2009 at 5:41 am

@ahmed: In OFDM, though the channel is frequency selective, channel as seen by each subcarrier is flat. Hence the expression for flat fading holds good. Please refer to the post http://www.dsplog.com/2008/08/26/ofdm-rayleigh-channel-ber-bpsk/

Reply

219 najat October 8, 2009 at 12:44 am

Dear Krishna:
I knew that OFDM technique, improve the BER performance in frequency selective fading channel, Can you help me in writing code using matlab program show that , I have probem in how write code for frequence selective fading.
Thank you .

Reply

220 Ajay Pratap Singh October 8, 2009 at 2:07 pm

This Krishna Pillai guy is a great help and his website undoubtedly very good resource on communication system topic. I got necessary informations about Vitervi Algorithm, Hard and soft decision.

Ajay Pratap Singh apts

Reply

221 Krishna Sankar October 12, 2009 at 5:27 am

@Ajay: Thanks for the nice words.

Reply

222 christine October 13, 2009 at 11:21 am

Thank you for this website ,it is awesome
could you help me to know what is the role of the following

rand(‘state’,100); % initializing the rand() function
randn(‘state’,200); % initializing the randn() function
thank you

Reply

223 Krishna Sankar October 15, 2009 at 5:22 am

@christine: The random numbers generated by the program can be initialized to enable us to run multiple simulations with the ‘exact same’ random numbers ;) . Setting the state of the rand() or randn() enables one to do so.
Use >>help rand or >> help randn to get more information.

Reply

224 3mor October 25, 2009 at 2:59 pm

Hi Krishna,

thanx a lot for your website

i have a simple question:

what about the unequally probable, e.g. when P(s0)=0.25 & P(s1)=0.75 ??

Reply

225 Krishna Sankar October 27, 2009 at 5:45 am

@3mor: If the probabilities are un equal, we would want to shift the threshold for making the decision. The chapter 5.1.3 Digital Communications by John Proakis discuss that case.

Reply

226 Egerue Nnamdi November 2, 2009 at 10:26 pm

Hi krishna, I have actually read the answers given to you by the concerns generated by the formula below
10^(-Eb_N0_dB(ii)/20)*n
for further clarification, i have actually divided by 18,16,14,12——3 to get different plots that actually decreases down the graph . Want to know if is how one can plot for BER with variable noise in the channel. I will appreciate if you reply me soon. Thanks

Reply

227 Krishna Sankar November 8, 2009 at 8:39 am

@Egerue: Do not change the division factor. Rather change the value of Eb_N0_dB. The division by 20 is required to convert dB into voltage.

Reply

228 Egerue Nnamdi November 4, 2009 at 2:19 pm

Hi krishna, I have actually read the answers given to you by the concerns generated by the formula below
10^(-Eb_N0_dB(ii)/20)*n
for further clarification, i have actually divided by 18,16,14,12——3 to get different plots that actually decreases down the graph . Want to know if is how one can plot for BER with variable noise in the channel. I will appreciate if you reply me soon. Thanks

Reply

229 Egerue Nnamdi November 8, 2009 at 8:00 pm

Hi Krishna.
Thank you very much. God will bless you. Below is the answer you gave me for my concern on this formular 10^(-Eb_N0_dB(ii)/20)*n
“Do not change the division factor. Rather change the value of Eb_N0_dB. The division by 20 is required to convert dB into voltage”.
Please give me more direction, by giving me an example of what you mean by changing the VALUE of Eb_No_dB.
Am thinking is Eb_No_dB =[0:10], [0:20], [0:30] and so on, but am not very sure. Pls, you are indeed a very good teacher, help me out

Thanks, you are really very helpful, you must really reap the fruit of your efforts.
NNAMDI

Reply

230 Krishna Sankar November 12, 2009 at 5:33 am

@Egerue:
You are right.
Eb_No_dB =[0:10], –> 0 to 10dB in steps of 1dB
Eb_No_dB =[0:20], –> 0 to 20dB in steps of 1dB
Eb_No_dB =[0:30], –> 0 to 30dB in steps of 1dB

Reply

231 Egerue Nnamdi November 9, 2009 at 2:29 am

Hi Krishna.
Thank you very much. God will bless you. Below is the answer you gave me for my concern on this formular 10^(-Eb_N0_dB(ii)/20)*n
ā€œDo not change the division factor. Rather change the value of Eb_N0_dB. The division by 20 is required to convert dB into voltageā€.
Please give me more direction, by giving me an example of what you mean by changing the VALUE of Eb_No_dB. or how do we get the value
Am thinking is Eb_No_dB =[0:10], [0:20], [0:30] and so on, but am not very sure. Pls, you are indeed a very good teacher, help me out

Thanks, you are really very helpful, you must really reap the fruit of your efforts.
NNAMDI

Reply

232 Egerue Nnamdi November 9, 2009 at 3:09 am

Hi krishna
Pls in essence how and where do we set the different values for EbNo/ or S/N or SNR to achieve different BER plots using your simulation example. Pls i will appreciate ur reply.

Thanks

Reply

233 Krishna Sankar November 12, 2009 at 5:39 am

@Egerue: Change Eb_N0_dB

Reply

234 Egerue Nnamdi November 10, 2009 at 3:42 pm

Hi krishna
Pls in essence how and where do we set the different values for EbNo/ or S/N or SNR to achieve different BER plots using your simulation example. Pls i will appreciate ur reply.

Thanks

Reply

235 student November 10, 2009 at 9:03 pm

Hi Krishna,

I was working on a IEEE paper titled”Xiaodi Zhang and N.C. Beaulieu, “A Closed-Form BER Expression for BPSK Using MRC in Correlated CCI and Rayleigh Fading,” IEEE Trans. Communications, vol. 55, no. 12, pp. 2249-2252, Dec. 2007.”.
Since you have also worked on similar field, I hope u can help me..

I was stuck with re creating the 1st fig in the paper.
SO, can you please look into it and help me out..

Thanks,
Student

Reply

236 Krishna Sankar November 13, 2009 at 5:29 am

@student: Sorry, due to time constraints, may I pass that opportunity. Good luck.

Reply

237 Jatin Chakravarti November 10, 2009 at 11:18 pm

Hi…
I need to Simulink Probability of error for PSK, 16QAM & MFSK. but don’t know how to simulink the equation: Pe=0.5*erfc(sqrt(snr)).
I tried to call the fuction from Matlab using Embedded Function Block in Simulink. But, the program din’t work. Can u suggest me a Block for finding Pe or a Program to call from .m file..?

Reply

238 Krishna Sankar November 13, 2009 at 5:31 am

@Jatin: Does this help?
Eb_N0_dB = [-3:10];
theoryBer = 0.5*erfc(sqrt(10.^(Eb_N0_dB/10))); % theoretical ber
close all; figure;
semilogy(Eb_N0_dB,theoryBer,’b.-’);

Reply

239 Faisal November 11, 2009 at 2:20 am

I am working on an adaptive modulation model on Simulink. For that first I am trying to get probability of error rate vs snr of different modulation techniques. On modelling 16 QAM modem I have problem plotting its graph by getting bit err rate from simulink model and performing graph plotting on matlab. following is the code im using in matlab..

clear; clf;
M=16; % for simulink
snr=0:10;
err_vec=[];

for i=1:length(snr)
EbNo=snr(i);
sim(‘QAM_16′);
err_vec(i)=bit_err_rate(1);
end;
semilogy(EbNo,err_vec,’b-*’);
grid on

please guide what is the error in this code… thanks

Reply

240 Krishna Sankar November 13, 2009 at 5:34 am

@Faisal: For BPSK,
Eb_N0_dB = [-3:10];
theoryBer = 0.5*erfc(sqrt(10.^(Eb_N0_dB/10))); % theoretical ber
close all; figure;
semilogy(Eb_N0_dB,theoryBer,’b.-’);

Reply

241 Hamid November 25, 2009 at 4:37 pm

hi

Why you are using 10^(-Eb_No_db(ii)/20) the minus sign in this formula because for voltage scaling it should be 10^(Eb_No_db(ii)/20).

Reply

242 Krishna Sankar December 7, 2009 at 4:34 am

@Hamid: The negative sign came as I am scaling the noise voltage. I am keeping the signal swing the same and reducing the swing of noise voltage to simulate various Eb/N0 values.

Reply

243 Obinna O November 26, 2009 at 1:09 am

Please guys I am having trouble writing a code for non coherent detection, I am required as part of my project to Assume Rayleigh fading channel with BPSK modulation. Using MAT-LAB plot bit error probability (BEP) under non-coherent de-tection. Your ĀÆgures should include plots from both analysis and simulation.Use average SNR (complex) from -5 to 20 dB.

Thanks a lot, i will be very grate ful to get help from you guys.

Reply

244 Krishna Sankar December 7, 2009 at 4:38 am

@Obinna O: Hope you have finished the project by now. Hope this post might be of help
http://www.dsplog.com/2008/08/10/ber-bpsk-rayleigh-channel/

Reply

245 alok joshi November 27, 2009 at 7:48 pm

hi sir
i have problem in BPSK with RS codes…..when i/p is given to pskmod function it says that “does not support complex airthmatic”.however i/p given is in 1 0 form

Reply

246 Krishna Sankar December 7, 2009 at 4:42 am

@alok joshi: Sorry, I do not have the pskmod() function.

Reply

247 rai December 3, 2009 at 9:10 am

is erfc equal Q function?

Reply

248 Krishna Sankar December 7, 2009 at 5:09 am

@rai: No, erfc is not equal to Q function, but both are related.
http://en.wikipedia.org/wiki/Q-function

Reply

249 shadat December 6, 2009 at 2:09 pm

hi krisna,
i hope you are fine.plz could you send me BPSK,QPSK,16QAM,64QAM modulation and demodulation simulation in matlab and simulation of adaptive modulation of convolutionaly coded for BPSK,QPSK,16QAM,64QAM?please help me.

Reply

250 Krishna Sankar December 7, 2009 at 5:27 am
251 Krishna Sankar December 7, 2009 at 5:27 am
252 fatima December 7, 2009 at 1:20 am

Hi Krishna
I need to Simulink Probability of error for binary symmetric channel if you don’t mind.

Reply

253 Krishna Sankar December 7, 2009 at 5:33 am

@fatima: I believe it should be reasonably straightforward to modify the gaussian channel used in this post to a binary symmetric channel. good luck.

Reply

254 adah December 10, 2009 at 5:41 am

Hi Krishna,

Actually, im studying about your coding for BER vs SNR for BPSK modulation. For simulation, when i changed the value for EbNodB = [-3:10] to [1:10], i cant get the result. why this problem happened?

Reply

255 Krishna Sankar December 10, 2009 at 10:12 am

@adah: What is the error which you are getting?

Reply

256 rama krishna December 14, 2009 at 11:29 am

i am doing simualtion to find the ber of bpsk modulation in pass band case.could you help me.

Reply

257 Krishna Sankar December 22, 2009 at 5:39 am

@rama: Please ask queries. I will try to answer to the best of my knowledge.

Reply

258 mouhamed December 16, 2009 at 10:04 pm

i want matlab programs for ‘BER MIMO’,thank u,please help me

Reply

259 Krishna Sankar December 23, 2009 at 5:25 am

@mouhamed: Please look at http://www.dsplog.com/tag/mimo

Reply

260 waheed December 17, 2009 at 6:23 pm

Hello friends: i am working on MAP , ML decoding for convolutional codes..is there any one who too work on similar field ..?

Reply

261 Krishna Sankar December 23, 2009 at 5:29 am

@waheed: For the Viterbi way of ML decoding, you may look at
http://www.dsplog.com/tag/viterbi

Reply

262 adah December 21, 2009 at 4:36 am

dear krishna…

From my past question, actually i got my result and understand..but..i have a problem with my coding…can you help me please…
My coding…
%directional antenna
d=100;
Pt=100:100:1000;
theta10=10*pi/180;
v=int(‘cos(x)*sin(x)’,0,pi/2);
x=int(v,’x',0,2*pi);
gt10=(4*pi)*cos(theta10)/double(x);
grd=180*pi/180;
c=3e8;
f=2.4e9;
L=1;
lamda=c/f;
Pr10=(Pt.*gt10.*grd)./(((4.*pi.*d)./lamda).^2)*L;

%power noise
k=1.38e-23; %k=Boltzman’s constant
t=300; %t=noise temperature in Kelvin
b=5e6; %b=bandwidth
Pn=k*t*b;

%directional antenna
snr10=Pr10/Pn;

Rb=54e6;
ebno10=snr10/Rb;

ebno101=10.*log10(ebno10);

N = 10^6; % number of bits or symbols
rand(‘state’,100); % initializing the rand() function
randn(‘state’,200); % initializing the randn() function

% Transmitter
ip = rand(1,N)>0.5; % generating 0,1 with equal probability
s = 2*ip-1; % BPSK modulation 0 -> -1; 1 -> 0
n = 1/sqrt(2)*[randn(1,N) + j*randn(1,N)]; % white gaussian noise, 0dB variance
% Eb_N0_dB = [-3:10]; % multiple Eb/N0 values
% k=1:1:10;
%
% for ii = 1:length(k)
% % Noise addition
% yomni = s + 10.^(-k(ii)./20)*n; % additive white gaussian noise
%
% % receiver – hard decision decoding
% ipHatomni = real(yomni)>0;
%
% % counting the errors
% nErromni(ii) = size(find([ip- ipHatomni]),2);
%
% end

for ii = 1:length(ebno101)
% Noise addition
y10 = s + 10.^(-ebno101(ii)./20)*n; % additive white gaussian noise

% receiver – hard decision decoding
ipHat10 = real(y10)>0;

% counting the errors
nErr10(ii) = size(find([ip- ipHat10]),2);

end

simBer10 = nErr10./N;
k1=1:1:10

figure
%semilogy(k,simBeromni,k1,simBer10)
semilogy(k1,simBer10)
grid on
legend(‘theta=10′)
xlabel(‘Eb/No, dB’);
ylabel(‘Bit Error Rate’);
title(‘Bit error probability curve for BPSK modulation in simulation’);

when i changed the Pt=10:10:100; actually i got the result..can you help me pliz….

thanks a lot…

Reply

263 Krishna Sankar December 23, 2009 at 5:47 am

@adah: what is the problem which you are seeing?

Reply

264 adah December 30, 2009 at 7:12 am

dear krishna…

In theory, when i applied my SNR into your coding, i got the result.
But, when i applied my SNR into your coding for simulation, i got the problem. I think that problem occurred at SNR or BER. But i dont know where my coding is problem? Can you help me pliz…
Thanks a lot..

Reply

265 Mitoo2007 December 27, 2009 at 3:10 am

please can u help me in this project ::::–

2) final report(OFDM):

* genearte large no of bits using randint

* modulate the data once with bpsk & then 16-QAM

* bpsk mod is 2*data-1

* after modulation u should loop on the data with step of 64′s

each time calculating their ifft

* add the noise to each 64

* if u remeber how to add noise then do it as u know,
else use awgn

sigandnoise=awgn(signal, SNR in dB , ‘measured’ )

* do fft with steps of 64′s , the same groups of symbols that were ifft’ed

* demodulate the data ( if bpsk then bits= recdata > 0)

*calculate ber using
ber=sum(xor( transmitted bits , received bits ) )

* the whole program should be done in a large loop that loops over

SNR -5 -> 15

* in case of fading
multiply with channel before ifft then divide after ifft

* multiplication is done using (.*) not just (*)

Reply

266 Winnie December 31, 2009 at 8:42 am

Hi Krishna,
I know the BER of BPSK is 0.5*erfc(sqrt(10.^(Eb_N0_dB/10))),
if I put channel coding before the modulation,and the code rate is R,
then if the BER equals 0.5*erfc(sqrt(R*10.^(Eb_N0_dB/10)))?
then BER with code rate 1/2 is higher than 3/4,but acturally ,it should be
lower. where is my mistake ?

Hoping for your help, thank you

Student

Reply

267 abhishek January 4, 2010 at 8:00 pm

please give help about matlab code in optimization for co channel and adjacent channel interference using ANN

Reply

268 Anvesh January 6, 2010 at 7:49 pm

haiiiiiii
i need Matlab code for digital modulation techniques.
plz give reply to me….plz

Reply

269 Amjad January 10, 2010 at 7:06 am

Dear Krishna,

Can you little bit tell me how to simulate the Uncoded BER and ergodic capacity for webb channel using QPPM modulation.

Reply

270 Amjad January 10, 2010 at 12:47 pm

Dear Krishna,

I already ask this question please. reply
Can you little bit tell me how to simulate the Uncoded BER and ergodic capacity for webb channel using QPPM modulation.

Reply

271 kishore January 25, 2010 at 9:07 pm

Hi krishna!

I need matlab code to obtain BER vs SNR curve for binary on-off keying.
also ,code for generating SER vs SNR curve for 3ASK modulation

Reply

272 anis January 28, 2010 at 4:04 pm

Hi there,
i just wondering why we need to initialize the rand and randn function?

Reply

273 Krishna Sankar April 4, 2010 at 4:50 am

@anis: If we initialize, we can ensure that the same random numbers are generated in any run

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274 anne na February 4, 2010 at 2:24 pm

hi,

I would like to demodulate QPSK but using soft decision. can you help me or guide me how I want to do this? I try the matlab function using

demodh= modem.pskdemod(ht, ‘outputType’, ‘bit’,'DecisionType’, ‘LLR’, ‘NoiseVariance’, sigma);
dec_inputt=demodulate(demodh,rt);

but the bit that I’m receive sort like it have inverse sign.
for example: if I transmit bit : 1; 0; 1 ,
I received : -10.8; +9.7; -11.2.
I’m expecting that : +10.8;-9.7;+11.2.

Or is it LLR gives this inverse sign? TQ so much if you can help me.

Reply

275 Krishna Sankar April 4, 2010 at 4:24 am

@anne na: Why are you using soft decision, unless you have some decoder like Viterbi following your demapper. Anyhow, I have discussed about softbit for 16QAM @ http://www.dsplog.com/2009/07/05/softbit-16qam/

Reply

276 gurinder February 27, 2010 at 11:28 am

respected sir
please can u help me in providing matlab code for rs codes using interleaver &qam in awgn channel
i will be thankful to u

Reply

277 Krishna Sankar March 30, 2010 at 5:19 am

@gurinder: I have not discussed ReedSolomon codes in dsplog.com yet. Hope to do so

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278 DaMarco February 27, 2010 at 3:35 pm

Hi There,

I need to design and develop a simulation platform in C/C++ to simulate the performance for BPSK- and 8PSK modulation through an AWGN channel and evaluate the biterror rate (BER) performance for BPSK and 8PSK in the range Eb/N0 2 [āˆ’4, 8] dB.Can you help me with any suggestion or source code.

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279 Krishna Sankar March 30, 2010 at 5:00 am

@DaMarco: You can use the Matlab model provided in this post as a reference for the C code

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280 rekha March 4, 2010 at 6:34 pm

hello sir,
please give us an idea how to analyse matlab code for ofdm-awgn channel with that of theory. what are the pilots and why are they used?

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281 Krishna Sankar March 30, 2010 at 4:33 am

@rekha: The BER performance of OFDM in AWGN is comparable to the no OFDM case. http://www.dsplog.com/2008/06/10/ofdm-bpsk-bit-error/

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282 Ananya March 21, 2010 at 6:28 pm

hello sir,
m doing ma project on ber calculation using matlab simulation for ofdm transmission for multipath wireless communication so please if u cud help me out in knowing which book wud b d best 2 go through….where i wud b getting much of d information regarding d basics of ofdm , transmission n reception of signls using ofdm, n n… ber calculation n its various graphs hw 2 plot dm n al….
please do help me out sir in dis ……m very confused abt dis…..

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283 Krishna Sankar March 28, 2010 at 1:55 pm
284 amit March 23, 2010 at 11:43 pm

Hi,
Can anyone help me in my project!!!
i Have read here that there is no difference between BER vs SNR in case of BPSK and OFDM using BPSK.
But my project guide has told me to mathematically prove that BER vs SNR is better for OFDM using BPSK than simple BPSK.
Suppose there is N no. of subcarrier.Then for each subcarrier there will be BER.But if i want to calculate the total BER for n no. of sub carrier then how the BER of indivisual subcarriers are related???

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285 Krishna Sankar March 28, 2010 at 1:51 pm

@amit: In AWGN there is no difference between using BER for BPSK and BER for BPSK using OFDM.

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286 vj1892 March 29, 2010 at 9:31 pm

your kind guidance on MATLAB has been really a great help for MATLAB starters. hope u will continue in future too.

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287 Krishna Sankar March 30, 2010 at 4:12 am

@vj1892: Thanks

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288 fizzle April 8, 2010 at 2:03 pm

pls i need a matlab program for signal to noise ratio in a wireless communications system.. how do i do the write up for the matlab program??

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289 Krishna Sankar April 13, 2010 at 6:18 am

@fizzle: Well, if you divide signal power by noise power, the resultant is signal to noise ratio :)

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290 eca April 13, 2010 at 9:08 pm

dear sir Krishna Sankar
I am very happy to find your blog … and found what I was looking for … I am a student majoring in telecommunications engineering and was doing the final tasks of rain attenuation, said supervisors told to discover how much value other than tresshold BER for MQAM rmodulasi … I want to ask how can I download the book John Proakis as an accurate reference book saya.Mohon bantuanya final … and also how the graph of the BER curve modulation 16…………

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291 Krishna Sankar April 14, 2010 at 5:01 am

@eca: You can try purchasing Digital Communications by Proakis

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292 STIVE CHLEF April 24, 2010 at 12:37 am

Hi Krishna Pillai ..
I whant to simulate BER for BPSK but for 5 or 6 user not for 1 user
what is the changement applicated in this programme.

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293 Krishna Sankar April 27, 2010 at 5:22 am

@STIVE CHLEF: Well, if you have 5/6 users, how are you planning to distinguish them at the receiver?

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294 chandra April 27, 2010 at 6:02 pm

Hi sir,
I want some programmes on DAPSK(differential amplitude phase shift keying) in OFDM systems.Is there any matlab codes in DAPSK.Please reply me as soon as possible.
Thanks,
regards,
chandra

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295 Krishna Sankar April 28, 2010 at 5:49 am

@chandra: Sorry, no posts on DAPSK. The closest which I have discussed for ASK is the 4-PAM case
http://www.dsplog.com/2007/10/07/symbol-error-rate-for-pam/
Hope this helps

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296 rama krishna June 25, 2010 at 3:43 pm

hello sir …
in BPSK constallation we map bit 1 to sqrt(Eb) and 0 to -sqrt(Eb). these are real points then why to add complex noise …we can directly add real noise of unit variance as follows…
N = 10^6 % number of bits or symbols
rand(‘state’,100); % initializing the rand() function
randn(‘state’,200); % initializing the randn() function

% Transmitter
ip = rand(1,N)>0.5; % generating 0,1 with equal probability
s = 2*ip-1; % BPSK modulation 0 -> -1; 1 -> 0
n = randn(1,N) ; % white gaussian noise, 0dB variance
Eb_N0_dB = [-3:10]; % multiple Eb/N0 values

for ii = 1:length(Eb_N0_dB)
% Noise addition
y = s + 10^(-Eb_N0_dB(ii)/20)*n; % additive white gaussian noise

% receiver – hard decision decoding
ipHat = real(y)>0;

% counting the errors
nErr(ii) = size(find([ip- ipHat]),2);

end

or we can use awgn function to pass through awgn channel which will add real noise if data is real and will add complex noise if data is complex… if i proceed in that way the performance is not matching with the theoritical analasys… can u explain me clearly why should we add complex noise…
expecting early reply….
Thanking u sir

Reply

297 Krishna Sankar June 28, 2010 at 6:13 am

@rama krishna: Adding complex noise does not affect the end result (as we are ignoring the imaginary part at the receiver). However, just make sure that scaling is correct. You should multiply factor of 1/sqrt(2) to the noise term which you have defined.

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298 Ayesha313 July 18, 2010 at 3:47 pm

hello sir
can you please guide me,how can i plot BER error rate of uncoded and coded BPSK
i know the formula of BER for Uncoded BPSK ,i have plotted it,but I am really cunfused about the Coded Bpsk,I am using BCH codes which are block codes
Waiting for your reply

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299 Krishna Sankar July 23, 2010 at 7:07 am
300 Ayesha313 July 27, 2010 at 8:58 pm

Thanks alot sir for your precious time and guidance

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301 prashant goad July 20, 2010 at 3:00 pm

hey krushna
That really helpful for me.
but i need it’s paper too. can u send it to me plzzz

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302 Krishna Sankar July 21, 2010 at 6:00 am

@prashant: I referred the text book Digital Communication by Proakis

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303 Ajith July 24, 2010 at 4:46 pm

Oops i am sorry if this is a total blunder.. In digital modulation techniques we modulate a sine or a cos wave using bits and transmit them as sine or cos waves.. But in this code for BPSK modulation I never found the usage of such things.. could you please clarify my doubts in simple words… Regards Ajith

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304 Krishna Sankar July 25, 2010 at 4:32 am

@Ajith: No, its not a blunder at all, tt’s a genuine query. There are two aspects to the reply.
a) In the case of baseband transmissions, we send the information on pulses and in the most simplest case, we send out rectangular pulses of varying amplitude to convey the information (or we can do some better pulse shaping to reduce the out of band emissions, while not introducing ISI)
b) In the case of pass band transmissions, we do the pulse shaping, then upconvert to a carrier and then transmit.

In both (a) and (b), for computing BER, the results which we get even if we do not simulate pulse shaping + up conversion is same as the one without it (assuming, we undo the operations optimally). Hence did not put those in place.

Further, I have written a post doing BER computation with rectangular pulse shaping with matched filtering
http://www.dsplog.com/2009/05/08/ber-with-matched-filtering/

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305 weather July 30, 2010 at 8:52 am

Thanks for your detailed post!
But I have question about the comment of this line in your codes
s = 2*m-1; % BPSK modulation 0 -> -1; 1 -> 0
I think maybe you want to change original 0 to -1, but 1 should be no change, is it?

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306 Krishna Sankar August 2, 2010 at 5:46 am

@weather: Thanks for noticing the typo in the comment. I corrected it.

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307 avdhut August 26, 2010 at 9:06 pm

hey…
will u plz giv code for gmsk…

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308 Krishna Sankar September 1, 2010 at 7:04 am
309 jansi September 3, 2010 at 6:47 pm

dear krishna,
i need to simulate BPSK modulation to analyse the bit error rate in AWGN channel and reyleigh fading channel for different SNR.the carrier frequency should be 20MHz.if u hav matlab codes for dis,help me.m running out of time.
xpecting fruitful reply.

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310 Krishna Sankar September 6, 2010 at 5:15 am
311 hamdirajeh October 14, 2010 at 12:03 am

its very useful thanx , do u know how can i get the simulink for this code ,please?

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312 Krishna Sankar November 17, 2010 at 5:32 am

@hamdirajeh: Sorry, I do not have simulink code

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313 ahmed November 1, 2010 at 12:37 pm

hi
i m doing graduation we have a project in which we have to design the communication sysem in which data+modulation(bpsk and 8-psk)+awgn then threshold detector and then we had to compute bit error rate.. can you help me in this…..

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314 Krishna Sankar November 15, 2010 at 2:14 am

@Ahmed:
For 8 PSK case, you may use the article on 16PSK as a reference
[symbol error rate] http://www.dsplog.com/2008/03/18/symbol-error-rate-for-16psk/
[bit error rate] http://www.dsplog.com/2008/05/18/bit-error-rate-for-16psk-modulation-using-gray-mapping/

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315 Elayan November 2, 2010 at 8:18 pm

Hi Krishna,

what about 8-PSK ?
is it the same to 16-PSK and just change M=8 only?
or there is other things that i should to change ?
becouse when i changed M to 8 i got an output and no errors
pls answer me it’s very importanat
thanks alot man

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316 Krishna Sankar November 15, 2010 at 2:12 am

@Elayan: Yes, I guess changing M to 8 should suffice.

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317 Sara December 3, 2010 at 9:12 pm

Hello Krishna,
I have a question.. I am hoping to design a OFDM communication system…
If you were to design an OFDM communication system.. what and where would u start from?
Regards
Sara

Reply

318 Krishna Sankar May 26, 2011 at 6:04 am

@Sara: You should know your available bandwidth, then chose your subcarrier spacing and so on

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319 Moyeen May 5, 2011 at 10:03 am

Dear krishna
impressive works! hay, can you provide me simulation codes for BPSK, QPSK, 16QAM & 64QAM with AWGN channel in OFDMA modulation? these would be very much helpful for my thesis. thank you.
Moyeen

Reply

320 Krishna Sankar May 24, 2011 at 5:34 am
321 moyeen May 6, 2011 at 1:48 pm

Hi Krishna,

I am working on different modulation technique. I am badly needed BER code of QPSK, (QAM 16,64)with AWGN channel.I have to submit my paper on 30may2011.

please send me code , this very helpful for me.

moyeen

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322 Krishna Sankar May 24, 2011 at 5:32 am

@moyeen: You can refer to the post on BER for 16QAM with Gray coding
http://www.dsplog.com/2008/06/05/16qam-bit-error-gray-mapping/

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323 Nikhil May 14, 2011 at 2:16 am

hi krishna,
please send the matlab codes(whatever u have about that paper) for below linked paper, I am doing my project on that paper. Please help me. This is very urgent., Please click on below mentioned web address.
http://dspace.mit.edu/openaccess-disseminate/1721.1/52384

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324 Krishna Sankar May 24, 2011 at 5:16 am

@Nikhil: Sorry, I have not looked into that paper.

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325 Marcos Amaral May 17, 2011 at 2:51 am

Hello Krishna Sankar,

I am doing some research on chaotic carriers and I was planing to make this BER for comparison.
Your post save me a lot of time to focus on the real subject of my work.
Thank you very much for the help!

Regards from Brazil
Marcos Amaral

Reply

326 Krishna Sankar May 23, 2011 at 3:05 am

@Marcos: Thanks.

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327 Guhan May 19, 2011 at 6:44 pm

Hi krishna,

Could i have codings with different modulations with different subcarriers for any one user in MIMO OFDM system .output shouild be throughput versus time or ber and time.please help me sir.Thank you in advance

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328 Krishna Sankar May 23, 2011 at 2:34 am

@Guhan: Yes, you can have independent modulation on different subcarriers.

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329 Emmanuel December 7, 2011 at 12:32 pm

Do you have code on how to generate a NRZ signal?

And do you have code on how to generate the eye diagram. Thanks.

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330 Krishna Sankar December 8, 2011 at 5:49 am
331 Talib December 20, 2011 at 11:06 pm

1.10^(-Eb_N0_dB(ii)/20)*n
2.10^(-Eb_N0_dB(ii)/10)

i want to answer the confusion of /20 why not by /10?

In fact sir Krishna Pillai want to make noise variance equal to 1 or 0dB.
you can check by command max((10^(-Eb_N0_dB(ii)/20)*n))= 1.01 where as
max((10^(-Eb_N0_dB(ii)/10)*n))= 0.3251 so its clear scaling…..remember before these commands i just removed the complex part i.e n = 1/sqrt(2)*[randn(1,N)]; for my easyness.

I also noticed that this scaling change for system to system e.g for non coherent 4FSK -it becomes like (10^(-sqrt(2)*Es_2N0_dB(ii)/20))*n becoz in 4FSK i need variance 0.5.so i scaled it to 0.5 by just multiplying by sqrt(2)

Reply

332 Krishna Sankar January 3, 2012 at 4:48 am

@Talib: Replies:
1. The /20 is to scale the noise voltage signal. Using max is not a good idea :)
2. I think for FSK coherent demodulation, which uses 0/1 modulation has 3dB poorer BERwhen compared to BPSK
http://www.dsplog.com/2007/08/30/bit-error-rate-for-frequency-shift-keying-with-coherent-demodulation/

Reply

333 sarah December 21, 2011 at 2:12 am

hai,
i would like to know why in y = s + 10^(-Eb_N0_dB(ii)/20) we use a negative sign her e for eb no.
Thanks in advance

Reply

334 Krishna Sankar January 3, 2012 at 4:44 am

@sarah: The -ve sign is to scale down the noise signal with respect to desired signal

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335 Thiyagi December 25, 2011 at 9:50 pm

Hello Mr.Krishna Pillai I tried to plot the BER for BPSK using the following code but didn’t get correctly..Could you please kindly correct me what went wrong..
clc
clear all
close all
ber=[];
x= randint(1,200);
y= [2];
k= log2(y);
z= reshape(x,length(x)/k,k);
d=bi2de(z);
M=[2];
s=pskmod(d,M);%Psk modulation

scatterplot(s);
snr=[-3:35];
ber1=[];
for i=snr;
p=awgn(s,i);
q=pskdemod(p,M);%psk demodulation
z1=de2bi(q);
d1=reshape(z1,1,length(x));
[r,b3]=biterr(x,d1);
ber1=[ber1,b3];
end

p;
ber=[ber;ber1];
scatterplot(p);
figure()
plot(snr,ber)

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336 Krishna Sankar December 28, 2011 at 5:41 am

@Thiyagi: If you dont add noise, are you getting zero bit error rate?

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337 Thiyagi December 29, 2011 at 11:50 am

Yes mr.Krishna i’m getting bit error rate as zero without adding noise i.e not used ‘awgn’ function to add noise

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338 Thiyagi December 29, 2011 at 11:59 am

Mr.Krishna for the below code i’m achieving same BER at less SNR comparing to the theoretical value, since i used AWGN inbuilt function to add noise..Whether this approach is correct? With the program given in this website it works good, from this program I tried with my logic just want to know whether the below logic is correct..Thank u
clc
close all;
clear all;
ber2=[];
N = 10^6; % number of bits or symbols
x = randint(1,N);

for i=1:length(x)
y1(i)=1; y11(i)=-1;

if x(i)==1
s(i)=y1(i);
else
if x(i)==0
s(i)=y11(i);
end
end
end
s;
scatterplot(s);
n = 1/sqrt(2)*[randn(1,N) + j*randn(1,N)];%AWGN
ber=[];
SNR_dB = [-3:35];
snr=10.^((SNR_dB)/10);
for i = 1:length(SNR_dB)
y = awgn(s,i);
y_hat = real(y)>0;
[n,b]=biterr(x,y_hat);
ber=[ber,b];
end
ber2=[ber2;ber];
figure()
form_ber = 0.5*erfc(sqrt(snr)); % theoretical ber
semilogy(SNR_dB,form_ber,’g.-’);
hold on
semilogy(SNR_dB,ber2,’bs-’)
legend(‘theoretical BER’,'practical BER’)
axis([-3 10 10^-5 1])
grid on

Reply

339 Krishna Sankar December 30, 2011 at 4:53 am

@Thiyagi: The code looks ok. You can check couple of points:
a) awgn : whether the noise power is as expected. Maybe you can try with ‘measured’ option.
From Mathworks http://www.mathworks.in/help/toolbox/comm/ref/awgn.html
“y = awgn(x,snr,’measured’) is the same as y = awgn(x,snr), except that awgn measures the power of x before adding noise.”

b) Counting the number of error. That piece of code looks funny. Did not understand the need for ber and ber2.
Should be easy for you to figure out.

340 Krishna Sankar December 30, 2011 at 4:53 am

@Thiyagi : ok, good

Reply

341 vidhya December 28, 2011 at 11:37 am

hai,
i am new in working with OFDM , so can anyone help me with simulink model of OFDM, please

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342 Krishna Sankar December 29, 2011 at 5:27 am

@vidhya: I don’t have the simulink model, but hopefully the post on BER for BPSK over OFDM helps
http://www.dsplog.com/2008/06/10/ofdm-bpsk-bit-error/

Reply

343 Thiyagi December 30, 2011 at 11:25 am

Gud morning Mr.Krishna thank u for posting ur valuable comments..

for i = 1:length(SNR_dB)
y = awgn(s,i);
y_hat = real(y)>0;
[n,b]=biterr(x,y_hat);
ber=[ber,b];
end
ber2=[ber2;ber];

I checked this one no need for ‘ber2′.. I used ‘ber’ as an array to store the values of bit error ratio since biterr is an inbuilt fuction and [n,b] where ‘b’ bit error ratio for a particular snr value and we need Bit Error Ratios for all differen SNR values, for that I used variable ‘ber’ to store the values of ‘b’

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344 Krishna Sankar January 3, 2012 at 4:38 am

@Thiyagi: Ok. So, all your issues are resolved?

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345 Thiyagi January 22, 2012 at 6:44 pm

Yes Mr.Krishna…
I’m currently pursuing my M.Tech(Communication Engineering) in VIT.. I’m willing to work in wireless field.. I need ur guidelines to work in communication field or in signal processing so that I can prepare for my future… Pls do reply waiting for ur precious reply.. Thank You

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346 Krishna Sankar January 23, 2012 at 5:13 am

@Thiyagi: All the best for your studies. With out being specific, I believe having the following knowledge will help you in good stead when trying to chart out a career in wireless communication/signal processing :
a) Understanding of RF architecture, RF impairments and it’s effect on the system performance
b) Phase/frequency syncrhronization
c) Channel effects – channel estimation/tracking
d) Channel coding
e) Multi user communication … to name a few…

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347 Kabir December 31, 2011 at 6:14 pm

Dear Mr. Krishna

I’d be grateful to you if it’s possible to provide single carrier and OFDM code (Matlab) for both timing and frequency offsets with and without cyclic prefix (both for single carrier and OFDM).

Reply

348 Krishna Sankar January 3, 2012 at 4:37 am

@Kabir: Sorry, I do not have all those codes handy

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349 Greg January 16, 2012 at 12:30 am

I am having problems simulating the BER vs SNR curve for the binary on-off keying modulation. My plot looks backwards. Do you have any suggests.
Here is my code
% EE474 Lab 1

clc;
clear all;
close all;

Es =1;
n=0:7;
count0 = 0;
%Simulated BER
for snr =0:7
count0 = count0+1;
error =0;
right = 0;

snr_number = 10^(snr/10);
N0 = Es/snr_number;
count = 0;
while(error0.5)
d=1;
else d=0;
end
S = d*sqrt(Es);
noise = randn*sqrt(N0/2);
D =S+noise;
if D>0
d_hat = 1;
else
d_hat =0;
end
if d == d_hat
right = right+1;
else
error = error+1;
end
end

ber_sim(count0) = error/count
end

semilogy(n,ber_sim,’o-’);
hold on;
xlabel(‘SNR’);
ylabel(‘BER (dB)’);
title(‘BER vs SNR BPSK’)

Your help is appreciated.
Greg

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350 Krishna Sankar January 22, 2012 at 8:50 am

@Greg: Are you getting zero BER when no noise is present in the simulation?

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351 abhay January 16, 2012 at 11:46 am

the above graph shows the theoritical and simulated values for bpsk from where this theoritical values comes.thnx

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352 Krishna Sankar January 22, 2012 at 8:53 am

@abhay: The computation of the theoretical BER is discussed in this post. Idea is to find the area under the tail of the Gaussian curve.

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353 Thiyagi January 22, 2012 at 10:53 pm

Hello Mr.Krishna

How to get rotated Pi/4 QPSK constellation? I got QPSK constellation how to get Pi/4 rotated constellation for QPSK

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354 Krishna Sankar January 23, 2012 at 5:08 am

@Thiygai: I do not think I ‘ve discussed pi/4 QPSK. But discussion of a close cousin MSK is kept @
http://www.dsplog.com/2009/06/16/msk-transmitter-receiver/
For QPSK you can refer to
http://www.dsplog.com/2007/11/06/symbol-error-rate-for-4-qam/

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355 Thiyagi January 23, 2012 at 7:31 am

Thank u very much Mr.Krishna.. Could you please name a few companies recruiting in this field… I knew only the IT companies no idea about this type of companies and what will the requirements to get into those companies……

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356 Krishna Sankar January 26, 2012 at 6:34 am

@Thiyagi: Trust that doing cursory search using google/linkedin will give you lots of pointers.
Requirement to get into any company is good knowledge of basics :)

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357 Thiyagi January 27, 2012 at 8:41 pm

Thank You

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358 stud1 February 3, 2012 at 1:31 pm

hi, this was very helpful 4 me, do you have the code for bit error rate(BER) of OOK

thanks.

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359 Krishna Sankar February 4, 2012 at 11:16 am

@stud1: Thanks. The OOK case is very close to BFSK, you can take look at
http://www.dsplog.com/2007/08/30/bit-error-rate-for-frequency-shift-keying-with-coherent-demodulation/

Reply

360 Krishna Pillai June 20, 2009 at 8:48 am

@RAO: My replies;

1/ I have written a post on symbol error rate and bit error rate for 16-PSK.
http://www.dsplog.com/2008/03/18/symbol-error-rate-for-16psk/
http://www.dsplog.com/2008/05/18/bit-error-rate-for-16psk-modulation-using-gray-mapping/
The equation and code should be easily adapted to M-PSK case.

2/ I have not tried modeling MDPSK.

3/ I have written a post on coherent demodulation of FSK
http://www.dsplog.com/2007/08/30/bit-error-rate-for-frequency-shift-keying-with-coherent-demodulation/

Hope this helps.

Reply

361 Ali June 21, 2009 at 9:58 pm

please can you tell the differences in the code if we made it such that the noise is only Gaussian noise with 0 mean and No/2 variance

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362 Krishna Pillai June 22, 2009 at 5:45 am

@Ali: We are discussing this case, no?

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363 Ali June 22, 2009 at 6:44 pm

please can you tell me how that is discussed if you write this statement 0db variance
in this line of code

n = 1/sqrt(2)*[randn(1,N)] %+ j*randn(1,N)]; % white gaussian noise, 0dB variance

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364 Ali June 22, 2009 at 11:31 pm

really , please can you illustrate me which part exactly in the code do this thing as the part the i see in the code is

n = 1/sqrt(2)*[randn(1,N)]; %+ j*randn(1,N)]; % white gaussian noise, 0dB variance

and you write as comment that the noise is 0 db variance

thanks for your great efforts

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365 hemant July 19, 2009 at 9:24 am

Hi Pillai..my Mtech project is Cs-OFDMa ,here we are using LAS (smart codes),pls let me know if hav any matlab simulation for the subject mentioned.

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366 Krishna Pillai June 23, 2009 at 4:39 am

@Ali: The 0dB variance is for complex noise (on both real and imaginary part). For BPSK we use only real part and the variance is 1/2. Agree?

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367 Krishna Pillai July 20, 2009 at 7:11 pm

@hemant: Sorry, I have not worked on LAS. Infact, I was unaware of the acronym till I googled and found Large Area Synchronous.

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368 anil November 7, 2009 at 1:23 pm

Hi Krishna,
I just read your answers in this website.
I am working in convolutional codes with 8psk and AWGN. I have some doubts in Iterative decoding. Can you help me.
Anil

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369 Krishna Sankar November 8, 2009 at 9:00 am

@anil: You may ask. I will reply to the best of my knowledge

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370 student November 10, 2009 at 9:05 pm

Hi Krishna,

I am working on a IEEE paper titled”Xiaodi Zhang and N.C. Beaulieu, “A Closed-Form BER Expression for BPSK Using MRC in Correlated CCI and Rayleigh Fading,” IEEE Trans. Communications, vol. 55, no. 12, pp. 2249-2252, Dec. 2007.”.

Since you have worked on similar field, I was hoping you can help me.

I was stuck with re creating the 1st fig from the paper.
Can you please look into it and help me.

Student

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371 Pieter January 18, 2011 at 7:38 pm

Never mind, already found out what I did wrong… forgot to convert to dB scale :(

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