(64 votes, average: 4.19 out of 5)

# Bit Error Rate (BER) for BPSK modulation

by on August 5, 2007

In this post, we will derive the theoretical equation for bit error rate (BER) with Binary Phase Shift Keying (BPSK) modulation scheme in Additive White Gaussian Noise (AWGN) channel. The BER results obtained using Matlab/Octave simulation scripts show good agreement with the derived theoretical results.

With Binary Phase Shift Keying (BPSK), the binary digits 1 and 0 maybe represented by the analog levels $+\sqrt{E_b}$ and$-\sqrt{E_b}$ respectively. The system model is as shown in the Figure below.

Figure: Simplified block diagram with BPSK transmitter-receiver

## Channel Model

The transmitted waveform gets corrupted by noise $n$, typically referred to as Additive White Gaussian Noise (AWGN).

White : The spectrum of the noise if flat for all frequencies.

Gaussian : The values of the noise $n$ follows the Gaussian probability distribution function, $p(x) = \frac{1}{\sqrt{2\pi\sigma^2}}e^{\frac{-(x-\mu)^2}{2\sigma^2}$ with $\mu=0$ and $\sigma^2 = \frac{N_0}{2}$.

## Computing the probability of error

Using the derivation provided in Section 5.2.1 of [COMM-PROAKIS] as reference:

$y=s_1 + n$ when bit 1 is transmitted and

$y=s_0 + n$when bit 0 is transmitted.

The conditional probability distribution function (PDF) of $y$for the two cases are:

$p(y|s_0) = \frac{1}{\sqrt{\pi N_0}}e^{\frac{-(y+\sqrt{E_b})^2}{N_0}$

$p(y|s_1) = \frac{1}{\sqrt{\pi N_0}}e^{\frac{-(y-\sqrt{E_b})^2}{N_0}$ .

Figure: Conditional probability density function with BPSK modulation

Assuming that $s_1$ and $s_0$ are equally probable i.e. $p(s_1) = p(s_0)=1/2$, the threshold 0 forms the optimal decision boundary.

• if the received signal is $y$ is greater than 0, then the receiver assumes $s_1$ was transmitted.
• if the received signal is $y$ is less than or equal to 0, then the receiver assumes $s_0$ was transmitted.

i.e.

$y>0 \Rightarrow s_1$ and

$y\le 0 \Rightarrow s_0$ .

### Probability of error given $s_1$ was transmitted

With this threshold, the probability of error given $s_1$ is transmitted is (the area in blue region):

$p(e|s_1) = \frac{1}{\sqrt{\pi N_0}}\int_{-\infty}^0e^{\frac{-(y-\sqrt{E_b})^2}{N_0}}dy=\frac{1}{\sqrt{\pi}}\int_{\sqrt{\frac{E_b}{N_0}}}^\infty e^{-z^2}dz=\frac{1}{2}erfc\left({\sqrt{\frac{E_b}{N_0}}}\right)$,

where,

$erfc(x) = \frac{2}{\sqrt{\pi}}\int_x^\infty e^{-x^2}dx$ is  the complementary error function.

### Probability of error given $s_0$ was transmitted

Similarly the probability of error given $s_0$ is transmitted is (the area in green region):

$p(e|s_0) = \frac{1}{\sqrt{\pi N_0}}\int^{\infty}_0e^{\frac{-(y+\sqrt{E_b})^2}{N_0}}dy=\frac{1}{\sqrt{\pi}}\int_{\sqrt{\frac{E_b}{N_0}}}^\infty e^{-z^2}dz=\frac{1}{2}erfc\left({\sqrt{\frac{E_b}{N_0}}}\right)$.

### Total probability of bit error

$P_b=p(s_1)p(e|s_1)+p(s_0)p(e|s_0)$.

Given that we assumed that $s_1$ and $s_0$ are equally probable i.e. $p(s_1) = p(s_0)=1/2$, the bit error probability is,

$P_b=\frac{1}{2}erfc\left({\sqrt{\frac{E_b}{N_0}}}\right)$.

## Simulation model

Matlab/Octave source code for computing the bit error rate with BPSK modulation from theory and simulation. The code performs the following:

(a) Generation of random BPSK modulated symbols +1′s and -1′s

(b) Passing them through Additive White Gaussian Noise channel

(c) Demodulation of the received symbol based on the location in the constellation

(d) Counting the number of errors

(e) Repeating the same for multiple Eb/No value.

Figure: Bit error rate (BER) curve for BPSK modulation – theory, simulation

## Reference

D id you like this article? Make sure that you do not miss a new article by subscribing to RSS feed OR subscribing to e-mail newsletter. Note: Subscribing via e-mail entitles you to download the free e-Book on BER of BPSK/QPSK/16QAM/16PSK in AWGN.

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i will compare between to sinecures
Tx Rx
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Gogol Saha April 5, 2014 at 10:49 pm

I want the matlab code for probability of symbol error for BFSK modulation

karthiksharma July 4, 2013 at 11:23 pm

hai krishna

This is Karthik sharma. doing my Masters in communication..
in my final year project i implemented a MIMO-OFDM WiMAX system using matlab simulink. The SNR vs BER graph for the model is showing a straight line instead of a waterfall graph.. kindly help me .

Regards

Krishna Sankar July 15, 2013 at 4:18 am

@karthiksharma: are you getting a zero ber in the no-noise case?

supas March 14, 2013 at 6:07 pm

Hi Krishna,
Thank you for this website

1- Why the WGN (n) is outside the statement (for) while in other your program (script_ber_bpsk_rayleigh_channel) is inside (for).

2- Please can you give me the equation of WGN or give me the name of reference

Krishna Sankar March 15, 2013 at 5:31 am

@supas: Replies
1/ ideally, one would want to give different noise realization for each snr point. with that in mind, having the wgn statement inside the for loop is better
2/ wgn is created using randn function

kavitha March 5, 2013 at 11:08 am

hello sir,

Krishna Sankar March 13, 2013 at 6:20 am

@kavitha: SOVA is soft output viterbi alogrithm – used in turbo coding. i have not discussed turbo codes yet in the blog.

marvellous March 2, 2013 at 11:55 am

I have a doubt regarding the scaling of noise power you have put in the code..
clearly, variance= sigma^2= No/2;

hence, while writing y= x+ n
since MATLAB generates unit variance noise, we should multiply it by sigma to get our scaled noise ,
y= x+ sigma*N
i.e. y= x+ sqrt(No/2)*n,
where n is randn(1,1) or 1/sqrt(2)*[randn(1,N) + j*randn(1,N)] doesn’t matter both are unit variance,

but in your code you have multiplied n with sqrt(No) rather than sqrt(No/2) so an extra divide by sqrt(2) is needed.

taking signal energy as unity,
No= 10^(-Eb_N0_dB(ii)/10)
sqrt(No)= 10^(-Eb_N0_dB(ii)/20);

y = s + 10^(-Eb_N0_dB(ii)/20)*n;

Please correct me if I am wrong and clear the doubt.

Krishna Sankar March 21, 2013 at 6:28 am

@marvellous: Hmm.. isn’t the code doing 1/sqrt(2) first and then sqrt(N0)? The term sqrt(N0/2) is for real and imaginary arm
http://www.dsplog.com/2012/03/25/thermal-noise-awgn/

Ravinder February 1, 2013 at 9:05 pm

Hi Krishna

I have a question regrading “sigma” the standard deviation of noise:
We know that sigma = sqrt(No/2), for complex noise. right?
But how about real noise? Is sigma = sqrt(No)?
where No is noise power spectral density.
I look forward to hear from you soon.
Many Thanks

Krishna Sankar February 5, 2013 at 5:41 am

@Ravinder: The term 1/2 comes because the noise is symmetric across +ve and -ve frequencies. Hope the post on thermal noise and awgn gives additional pointers
http://www.dsplog.com/2012/03/25/thermal-noise-awgn/

Ravinder February 5, 2013 at 1:35 pm

ruby January 27, 2013 at 4:10 am

pls can you help solve this question; Given a stationary transmitter is sending at a center frequency of 900 MHz, the receiver is
travelling at speeds of (a) 1 km/hr; (b) 10 km/hr; (c) 100 km/hr; or (d) 500 km/hr. Draw
a graph of four curves that show deviation of spectral frequencies from the center frequency
for the above four scenarios. Use a legend properly to distinguish different scenarios.
5. Suppose that a mobile node is moving at a speed of 150 km/hr in a typical urban environment
(e.g., highway). It transmits a signal to the base station at a center frequency of fc = 1 GHz
using a binary modulation at a data rate R. It is known that the typical RMS delay spread
 of multipath propagation in this scenario is around 5 s. For each of the following cases,
decide if the received signal is best described as undergoing fast/slow fading, frequency
(a) The mobile node is sending at a data rate of R = 1 Mbps.
(b) The mobile node is sending at a data rate of R = 500 kbps.
(c) The mobile node is sending at a data rate of R = 50 kbps.

Krishna Sankar February 1, 2013 at 5:25 am

@ruby: wont be able to help directly, but can point you to the following wikipedia links:
http://en.wikipedia.org/wiki/Doppler_effect

Ozgeee December 26, 2012 at 3:47 am

Why is my comment not appeared

Krishna Sankar December 26, 2012 at 7:08 am

@Ozgee: There is moderation enabled.

Ozgeee December 26, 2012 at 3:37 am

First of all, congratulations for this helpful and nice explanation. I’m dealing with the similar task (maybe the same) these days. I determine two waveforms, Tb and BW, then I’m trying to draw the plot of Pe versus BW. Is yours exactly the same thing that I want to do? However, in my design, there are two integrators. I couldn’t get the point that whether you used integrator in your matlab code or not. Also, if we use lowpass filter, instead of AWGN is there a change? I’m very new at digital communication, so I’m sorry for these bad questions

Krishna Sankar December 26, 2012 at 7:06 am

@Ozgee: Replies:
1/ This simulation is doing bit error rate vs SNR (not vs Bandwidth)
2/ This code does not have any integrator – but a typical implementation will need a matched filter
see the following example : http://www.dsplog.com/2009/05/08/ber-with-matched-filtering/
3/ Loop filter and awgn two independent aspects.

Vishnavi December 24, 2012 at 7:16 am

Hi ,I need program for BER reduction using SSPA(solid state power amplifer ) model .or else BER reduction using PTS scheme.

Krishna Sankar December 25, 2012 at 5:46 am

@Vishnavi: Sorry, I do not know the topic.

karim December 8, 2012 at 3:39 am

could u send me the matlab code .plz

Krishna Sankar December 8, 2012 at 3:49 am

@karim: the link is provided in this post.

Yamsha December 4, 2012 at 2:30 am

Hi!

You’ve calculated the BER with a message of 1exp6 bits, and the curve obtained is perfectly over the reference, but if you take less than 1exp6 (e.g. 1exp4) apears irregulats peaks on the curve.

My question is……that’s something that I have to worry? Or it’s correct the response of the curve?

Thank you very much!

Yamsha

Krishna Sankar December 4, 2012 at 6:15 am

@Yamsha: To get confidence in the simulated results, one need to get sufficient number of errors. For eg, to get a bit error rate of the order of 10^-6, one needs to send atleast 10^7 bits.

Yamsha December 5, 2012 at 1:53 am

Thanks a lot!

Thats the information that i need!

Yamsha

trung tong December 1, 2012 at 4:23 pm

Hi Krishna,
Can we use importance sampling to measure the BER very small (below 10^-10) ?

Krishna Sankar December 4, 2012 at 6:21 am

@trung tong: To get a BER of 10^-10, need to send atleast 10^11 bits. Do not use this code, use C model to do the simulation (will be faster)

phani November 23, 2012 at 1:51 pm

Hi Sir…
Can you Provide the matlab code for Analysis and design of OFDM-IDMA systems
it’s very urgent….!

Krishna Sankar November 27, 2012 at 5:47 am

@phani: sorry, do not know about ofdm-idma topic

Tony November 22, 2012 at 7:51 pm

Dear Mr Krishna.

Im trying to draw the same function, BPSK with AWGN, in excel.
I get a completely different graph, so i must be doing something wrong.

May i contact you by mail to send you my table?.

Thanks very much.

Krishna Sankar November 27, 2012 at 5:49 am

@Tony: In excel, make sure that you are selecting log-scale for the y-axis.

BALA MURTHY October 31, 2012 at 4:29 pm

Can you please provide the code for 2×2 MIMO with spatial diversity and different reciever combining schemes for a system using m-PPM modulation. Using gamma-gamma channel model.

Krishna Sankar November 2, 2012 at 7:03 am

@BALA MURTHY: Please check out post @
http://www.dsplog.com/category/mimo

Manoj October 31, 2012 at 3:21 am

I need this in matlab with expalnation.
Compute the error probability of a BPSK as a function of Es/NodB (in decibel)
{1; 2; 3; 4; 5; 6; 7; 8; 9; 10}.
1.What is the energy of a BPSK symbol (Es)? And the Energy per bit (Eb)?
Comment.
2.The noise variance is
sigma^2 =N0/2
hence for each value of Es/NodB you can derive the associated sigma^2 that you
3.Generate a vector x representing N=1000000 BPSK equiprobable symbols.
4.Estimate the transmitted symbol x based on the received signal y = x + n.
Show the histogram of y for Es/NodB = 1 and Es/NodB = 10 (comment the
fi gures)
5.Compute the average error probability as the number of errors over the total
number of transmitted symbols N.
6.Repeat the steps for each value of Es/NodB and plot the corresponding P(e) in
a log scale (use the function semilogy with “blue” line). Comment the results.
What is the minimum Es/NodB to guarantee a P(e) < 10^-5? In the same
gure plot ("red" line) the theoretical P(e) of a BPSK (see slides). Comment

Manoj November 1, 2012 at 5:57 pm

Dear krishna sankar sir,

Krishna Sankar November 2, 2012 at 7:07 am

Krishna Sankar November 2, 2012 at 6:43 am

@Manoj: This post (and the matlab code) on BER of BPSK in AWGN is addressing most of your queries. Good luck!

Manoj November 6, 2012 at 4:25 pm

thankyou very much sir

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Nada October 15, 2012 at 1:04 pm

could you please explain the relationship between the BER and the Eb/No and why we get this graph shape

Krishna Sankar October 17, 2012 at 6:31 am

@Nada: The derivation is explained in this post

pawan September 16, 2012 at 5:24 pm

hey

How do you calculate the SNR if given bit error rate of 10^-3.

Secondly if now i am given a symbol like P which when converted to binary is equal 011. How do i calculate the snr if i need a symbol error rate of less than 10 ^-4 ??

thanks

Krishna Sankar September 18, 2012 at 5:45 am

@pawan: you can either use the visual information from the ber plot to find the minimum snr required to hit a given bit error rate. for eg, bpsk in awgn requires around 7dB of Eb/N0 to hit 10^-3 ber. One can also use the erfinv() function.

ebtesam jumma September 15, 2012 at 9:18 pm

can you exaplan about curve of error performance of BPSK over AWGN and Rayleigh channel?

Krishna Sankar September 18, 2012 at 5:38 am
vanness August 27, 2012 at 9:31 am

Hi, Krishna

Would like to ask how to add attenuation to the transmitted signal?
which line of code should i edit? is it from ”y = s + 10^(-Eb_N0_dB(ii)/20)*n;”
In case if attenuation = 0.3

Krishna Sankar August 29, 2012 at 5:19 am

@vanness: Well, shouldn’t it be straightforward

attn = 0.3;
y = attn*s + 10^(-Eb_N0_dB(ii)/20)*n;

phucmv August 25, 2012 at 12:12 pm

Hi Krishna,
I want to demo about DSSS spread spectrum systems by MATLAB. it’s my project
it uses modBPSK and PN
but i’m not good at matlab programming
can you help me about it ?
thankyou very very much !!
my email : phuc0605bk@gmail.com

Krishna Sankar August 29, 2012 at 5:29 am

@phucmv: sorry, wont be able to help you with the matlab programming. good luck

candy July 23, 2012 at 10:59 am

Hi Krishna,

In this post, it is very useful that you show the relationship between BER and SNR. Actually, I want to describe the relationship between BER and transmission distance for BPSK in AWGN channel. Please give some advices for this.

Thank you so much!!

Krishna Sankar July 24, 2012 at 5:40 am

@candy: To convert to a distance, one needs to know – Transmit power, Path loss, Receive noise power
The SNR, dB at the receiver is = Tx Power, dBm – Path Loss, dB – Rx Noise Power, dBm

The transmit power is chosen by the designer. The path loss depends on the square of the carrier frequency and square of the distance in free space. Check out http://en.wikipedia.org/wiki/Free-space_path_loss.
The receiver noise power depends on the bandwidth of the receiver. For eg, a receiver with a 20MHz bandwidth will have a thermal noise power of -174dBm/Hz + 10*log10(20e6) = -101dBm.
http://www.dsplog.com/2012/03/25/thermal-noise-awgn/

Hope this helps.

candy July 24, 2012 at 11:17 am

Dear Krishnan,
Thank you so much for your help!
I have another problem that I can not understand as:
I used the formula: BER = 0.5*erfc(SNR) for BPSK in AWGN channel to plot the picture which show relationship between BER and propagation distance through the relationship between SNR and distance based on free space path loss model. But I can not explain why BER can not be greater than 0.5 even the distance is increased up top very large value. I think that this result is not suitable with the fact that when BER will be increased to 1 when distance increased from 0 to infinite.

I hope you give me some advices for this.
Thanks.

Krishna Sankar July 26, 2012 at 5:27 am

@candy: well, when we flip a coin we have a 50% chance of getting the call correct.

candy July 26, 2012 at 5:32 am

Thank you so much!

ANIL KUMAR July 23, 2012 at 8:08 am

Dear Krishnan,
Could you help me writing the code for this question.

Simulate 4-PAM (k = 2,M = 4). Pairs of bits are mapped into symbols s, where s belongs to the alphabet S = (3A, A,-A,-3A). Note that the input symbols are equiprobable, and there is no need to generate individual bits. Additive noise n is real AWGN process (same as in (1)). The input into the detector is r =s + n. The
detector finds the closest point in S to r. The average symbol SNR s = 5A square / 2. The bit SNR b = SNR s / 2. Simulate performance of this system for SNR b = 7, 8, 9, 10, 11 dB and find the symbol and bit error rates.

Your cooperation in this regard will highly be appreciated

Thanks
Anil

Krishna Sankar July 24, 2012 at 5:33 am

@Anil: Long back, I have written a post on symbol error rate for 4-PAM.
http://www.dsplog.com/2007/10/07/symbol-error-rate-for-pam/
Hope this helps.

megha July 19, 2012 at 3:06 pm

I want the code for IEEE project of “Error correction between convolutional codes using Chaotic switching.

Krishna Sankar July 23, 2012 at 4:41 am

@megha: what is chaotic switching? the regular convolutional code with viterbi decoder is discussed in
http://www.dsplog.com/tag/viterbi

khushi July 17, 2012 at 4:04 pm

Hello Sir
I am new here and i need your help.Please give me answers of my few questions. I will be thankful to you.:
1. ip = rand(1,N)>0.5
how it generate only +1 and -1
what is the concept of using the term>0.5

2. Eb_N0_dB = [-3:10]
how the range of Eb/No is chosen and what is the need of this?

3. for ii = 1:length(Eb_N0_dB)
what is the concept of this function?

Krishna Sankar July 18, 2012 at 6:41 am

@khushi: my replies
1. rand() generates a uniformly distributed number in the range from [0 to 1). The >0.5 allows to generate a input sequence with approximately equal probabilities for 0 and 1.
Then 2*0 – 1 = -1 and 2*1 – 1 = +1

2. This is the region where the BER for BPSK modulation changes from from very high ber (>0.1) to very low ber (<10^-4)

3. To find the ber for different Eb/N0 values

khushi July 18, 2012 at 11:41 am

Thank you very much Sir for solving my problems
One more thing I want to know that how do we know that in which range BER changes from from very high ber to very low ber.

Krishna Sankar July 20, 2012 at 6:28 am

@khushi: From the theoretical bit error rate equation

khushi July 20, 2012 at 1:51 pm

sir will u please tell me that from where I can see that equation

Zoe July 3, 2012 at 10:16 am

Hi Krishna,
Could you answer the following q’s please if you have the time? Thanks. Zoe

1. I don’t know how the following counts. Is nErr(ii) an array?
And I don’t precisely know what ‘size’ and ‘find’ functions do?
(I know ip-ipHat = 0 is no error)

nErr(ii) = size(find([ip- ipHat]),2);

2. In the following is the decimal version of EbNo getting multiplied with n, mean of the Gaussian noise? (of course then added with s, -1 or 1, depending on what was sent)
y = s + 10^(-Eb_N0_dB(ii)/20)*n

3. The following is confusing. Why two real and imaginary component Gausian functions added and normalized by inverse of “sqrt(2)”
Could you write the formula or equation it is derived from?

n=1/sqrt(2)*[randn(1,N) + j*randn(1,N)]

Krishna Sankar July 5, 2012 at 5:12 am

@Zoe:
1. nErr is the count of errors.
find() finds the index of elements which are different between ip and ipHat
size() counts the number of elements which are reported by find()

2. it is the Eb/N0 in linear scale applied to the noise voltage to produce the desired Eb/N0 ration

3. one can possibly send information on the two dimensions together. Hence we model as two randn() variables each with variance 1/2. Hence the normalization by 1/sqrt(2) on the voltage signal.

ebtesam June 14, 2012 at 8:07 pm

hi , iam new here i need disscision about ber performance of bpsk over awgn and rayliegh channel

Krishna Sankar June 26, 2012 at 5:55 am
Aisha June 4, 2012 at 7:11 pm

Hi dear,

how are you.I need a help from you because I have a project and there some points i dont understand it.

It is about the square root raised cosine pulse ,we need to plot it with different roll-off factor(B=0.25,B=0.5,B=1.
After that consider a binary antipodal signaling over an ideal AWGN channel at the normalized bit rate of 1 bit second where TB =1
x(t)=+or-p(t) +w(t)
where w(t) is an additive white gausian noise ,simulate model for this system and plot the resulting BER (B=0.5)

Krishna Sankar June 11, 2012 at 5:21 am
Arinze Nwodogwu May 17, 2012 at 9:08 am

Hello Krishna Pillai,
thanks alot for the wonderful work you did here.please can i have d privilege to have your personal email address. I have something personal to email to you with respect to my undergraduate project work.Thanks.

Krishna Sankar July 2, 2012 at 5:23 am

@Arinze : Please use the email listed in http://www.dsplog.com/contact-us/

Justin April 20, 2012 at 12:50 am

hi,
how can I plot the bpsk waveform for the sequence [1 0 1 1 0 1 0] please .
Thanks.

Krishna Sankar April 23, 2012 at 5:24 am

@Justin: If you want to pulse shape with a rectangular filter,
>>os = 4
>>x = [1 0 1 1 0 1 0];
>>xp = kron(x,ones(1,os));
>>plot(xp)

Asia April 16, 2012 at 3:46 pm

Please help me with simulating BPSK with direct-sequence spreading using m-sequence .I have tried doing the spreading and the despreading as well as noise addition but the BER vs. EbN0 curve is higher!!!! than the theoretical one ,which is the same as BPSK without spreading .
the problem could be with the addition of the noise ; I did multiply the transmitted chips by 1/sqrt(N) ,where N is spreading factor ,in order to make sure that the bit power is 1 .

Here is my code:
clear
b = 10000; % number of bits or symbols

%—————– Transmitter————–
%Message signal
ip = rand(1,b)>0.5; % generating 0,1 with equal probability

%generating m-sequence
polynomial=[6 1 0];
[pnSequence,chipIndex,N]=genPNSequence(polynomial);

signal = 2*ip-1; % BPSK modulation 0 -> -1; 1 -> 1 (polar)
mseq=2*pnSequence-1; % PN sequence in polar form

%spreading message signal ‘signal’ using pn sequence ‘mseq’,the processing gain
%’N';length of the PN sequence.

w=mseq’*signal;

n = randn(1,N*b) ; % white gaussian noise, 0dB variance
Eb_N0_dB = [-3:10]; % multiple Eb/N0 values

for ii = 1:length(Eb_N0_dB)

q=reshape(y,N,b);

% receiver – hard decision decoding

% counting the errors
nErr(ii) = size(find([ip- ipHat]),2);

end

simBer = nErr/N; % simulated ber
theoryBer = 0.5*erfc(sqrt(10.^(Eb_N0_dB/10))); % theoretical ber

% plot
close all
figure
semilogy(Eb_N0_dB,theoryBer,’b.-’);
hold on
semilogy(Eb_N0_dB,simBer,’mx-’);
%axis([-3 10 10^-5 0.5])
grid on
legend(‘theory’, ‘simulation’);
xlabel(‘Eb/No, dB’);
ylabel(‘Bit Error Rate’);
title(‘Bit error probability curve for BPSK modulation’);

end of code

So please can you check what is wrong with my code??

Krishna Sankar April 17, 2012 at 4:27 am

@Asia: I couldn’t play with the code. However, if you are getting zero BER for no noise case, it points to a scaling error.

Asia April 17, 2012 at 2:23 pm

@Krishna: Hello Krishna
I have tried the no noise case and gave me zero BER . I couldn’t figure out what is the problem with the scaling ??!! Do you have any code for spreading and despreading ?
I need the correct coe for my final project on my Bachelor degree. So I should be very grateful if you can help me with this.

yahya April 12, 2012 at 4:52 pm

pleas Mr I would like to help me to find calculation BER vs SNR when using 64DAPSK modulation with DWT-OFDM in simulation MATLAB, thanks.

Krishna Sankar April 16, 2012 at 5:23 am

@yahya: Sorry, I have not tried 64DAPSK modulation

Fargo March 20, 2012 at 9:11 pm

Your article really open my eyes.
Is there anyone about calculate theory BER value of frequency selective channel in your BLOG?
Thanks,
Yushi Chen

Krishna Sankar March 21, 2012 at 4:52 am
medo March 20, 2012 at 11:56 am

i want code on CDMA transimeter and reciver with AWGN for multi user by LLR log like ratio in receiver iterative decoding ,…….i make it but without LLR can u help me plz also i put spreader but not coded as block thx

Krishna Sankar March 21, 2012 at 5:02 am

@medo: Good luck with the assignment

megha February 3, 2012 at 6:06 pm

I want the code for error correction between convolution codes using chaotic switching

Krishna Sankar February 6, 2012 at 5:12 am

@megha: Sorry, nothing handy

megha July 19, 2012 at 3:08 pm

why

stud1 February 3, 2012 at 1:31 pm

hi, this was very helpful 4 me, do you have the code for bit error rate(BER) of OOK

thanks.

Krishna Sankar February 4, 2012 at 11:16 am

@stud1: Thanks. The OOK case is very close to BFSK, you can take look at
http://www.dsplog.com/2007/08/30/bit-error-rate-for-frequency-shift-keying-with-coherent-demodulation/

Zahra January 31, 2012 at 4:04 pm

Dear Mr. Krishna
Would you help me in my project!!!
I study this paper in IEEE for satrting my thesis in master degree. “Cross-Layer combining of adaptive Modulation and coding with truncated ARQ over wireless links” .1343909 abstract
This paper appears in: Wireless Communications, IEEE Transactions on
Issue Date: Sept. 2004
Volume: 3 Issue:5
On page(s): 1746 – 1755
but I have som misunderstand whith this paper and manye other papers like this .
The first problem is finding average SNR in mode(n).
I don’t know how can I select the average SNR in (7), (8),(15) ,…
and the second problem is ,if we select the SNR whit gama distribution in matlab for example:
gamrand(a,b)
then gama average is: ab (in gama distribution).
In fig 4, 5 ,… we have average SNR in horizontal axis and I don’t know how select from 0 to 30 db
best regards

Krishna Sankar February 8, 2012 at 5:22 am

@Zahra: Sorry, due to lack of time I wont be able to help in your project. Good luck.

Sivaganesh January 30, 2012 at 11:14 pm

Hi Krishna,
your coding’s were very useful for my simulation lab works..could you please send me the comparison of various error correcting codes for a particular modulation scheme..

Krishna Sankar February 6, 2012 at 5:15 am

@Sivaganesh: I have discussed only two error correcting codes:
a) Hamming code and decoder
http://www.dsplog.com/2009/09/29/hamming-74-code-with-hard-decision-decoding/
b) Viterbi decoder (hard and soft)
http://www.dsplog.com/tag/viterbi/

Thiyagi January 23, 2012 at 7:31 am

Thank u very much Mr.Krishna.. Could you please name a few companies recruiting in this field… I knew only the IT companies no idea about this type of companies and what will the requirements to get into those companies……

Krishna Sankar January 26, 2012 at 6:34 am

@Thiyagi: Trust that doing cursory search using google/linkedin will give you lots of pointers.
Requirement to get into any company is good knowledge of basics

Thiyagi January 27, 2012 at 8:41 pm

Thank You

Thiyagi January 22, 2012 at 10:53 pm

Hello Mr.Krishna

How to get rotated Pi/4 QPSK constellation? I got QPSK constellation how to get Pi/4 rotated constellation for QPSK

Krishna Sankar January 23, 2012 at 5:08 am

@Thiygai: I do not think I ‘ve discussed pi/4 QPSK. But discussion of a close cousin MSK is kept @
For QPSK you can refer to
http://www.dsplog.com/2007/11/06/symbol-error-rate-for-4-qam/

abhay January 16, 2012 at 11:46 am

the above graph shows the theoritical and simulated values for bpsk from where this theoritical values comes.thnx

Krishna Sankar January 22, 2012 at 8:53 am

@abhay: The computation of the theoretical BER is discussed in this post. Idea is to find the area under the tail of the Gaussian curve.

Greg January 16, 2012 at 12:30 am

I am having problems simulating the BER vs SNR curve for the binary on-off keying modulation. My plot looks backwards. Do you have any suggests.
Here is my code
% EE474 Lab 1

clc;
clear all;
close all;

Es =1;
n=0:7;
count0 = 0;
%Simulated BER
for snr =0:7
count0 = count0+1;
error =0;
right = 0;

snr_number = 10^(snr/10);
N0 = Es/snr_number;
count = 0;
while(error0.5)
d=1;
else d=0;
end
S = d*sqrt(Es);
noise = randn*sqrt(N0/2);
D =S+noise;
if D>0
d_hat = 1;
else
d_hat =0;
end
if d == d_hat
right = right+1;
else
error = error+1;
end
end

ber_sim(count0) = error/count
end

semilogy(n,ber_sim,’o-’);
hold on;
xlabel(‘SNR’);
ylabel(‘BER (dB)’);
title(‘BER vs SNR BPSK’)

Greg

Krishna Sankar January 22, 2012 at 8:50 am

@Greg: Are you getting zero BER when no noise is present in the simulation?

Kabir December 31, 2011 at 6:14 pm

Dear Mr. Krishna

I’d be grateful to you if it’s possible to provide single carrier and OFDM code (Matlab) for both timing and frequency offsets with and without cyclic prefix (both for single carrier and OFDM).

Krishna Sankar January 3, 2012 at 4:37 am

@Kabir: Sorry, I do not have all those codes handy

Thiyagi December 30, 2011 at 11:25 am

Gud morning Mr.Krishna thank u for posting ur valuable comments..

for i = 1:length(SNR_dB)
y = awgn(s,i);
y_hat = real(y)>0;
[n,b]=biterr(x,y_hat);
ber=[ber,b];
end
ber2=[ber2;ber];

I checked this one no need for ‘ber2′.. I used ‘ber’ as an array to store the values of bit error ratio since biterr is an inbuilt fuction and [n,b] where ‘b’ bit error ratio for a particular snr value and we need Bit Error Ratios for all differen SNR values, for that I used variable ‘ber’ to store the values of ‘b’

Krishna Sankar January 3, 2012 at 4:38 am

@Thiyagi: Ok. So, all your issues are resolved?

Thiyagi January 22, 2012 at 6:44 pm

Yes Mr.Krishna…
I’m currently pursuing my M.Tech(Communication Engineering) in VIT.. I’m willing to work in wireless field.. I need ur guidelines to work in communication field or in signal processing so that I can prepare for my future… Pls do reply waiting for ur precious reply.. Thank You

Krishna Sankar January 23, 2012 at 5:13 am

@Thiyagi: All the best for your studies. With out being specific, I believe having the following knowledge will help you in good stead when trying to chart out a career in wireless communication/signal processing :
a) Understanding of RF architecture, RF impairments and it’s effect on the system performance
b) Phase/frequency syncrhronization
c) Channel effects – channel estimation/tracking
d) Channel coding
e) Multi user communication … to name a few…

fateme May 13, 2012 at 8:35 pm

hi,i need to have m file of each modulation and the figures of error in matalb without using the order of modulation that are in matlab.
can you help me?
thankyou

Krishna Sankar May 15, 2012 at 5:49 am
vidhya December 28, 2011 at 11:37 am

hai,
i am new in working with OFDM , so can anyone help me with simulink model of OFDM, please

Krishna Sankar December 29, 2011 at 5:27 am

@vidhya: I don’t have the simulink model, but hopefully the post on BER for BPSK over OFDM helps
http://www.dsplog.com/2008/06/10/ofdm-bpsk-bit-error/

Thiyagi December 25, 2011 at 9:50 pm

Hello Mr.Krishna Pillai I tried to plot the BER for BPSK using the following code but didn’t get correctly..Could you please kindly correct me what went wrong..
clc
clear all
close all
ber=[];
x= randint(1,200);
y= [2];
k= log2(y);
z= reshape(x,length(x)/k,k);
d=bi2de(z);
M=[2];
s=pskmod(d,M);%Psk modulation

scatterplot(s);
snr=[-3:35];
ber1=[];
for i=snr;
p=awgn(s,i);
q=pskdemod(p,M);%psk demodulation
z1=de2bi(q);
d1=reshape(z1,1,length(x));
[r,b3]=biterr(x,d1);
ber1=[ber1,b3];
end

p;
ber=[ber;ber1];
scatterplot(p);
figure()
plot(snr,ber)

Krishna Sankar December 28, 2011 at 5:41 am

@Thiyagi: If you dont add noise, are you getting zero bit error rate?

Thiyagi December 29, 2011 at 11:50 am

Yes mr.Krishna i’m getting bit error rate as zero without adding noise i.e not used ‘awgn’ function to add noise

Thiyagi December 29, 2011 at 11:59 am

Mr.Krishna for the below code i’m achieving same BER at less SNR comparing to the theoretical value, since i used AWGN inbuilt function to add noise..Whether this approach is correct? With the program given in this website it works good, from this program I tried with my logic just want to know whether the below logic is correct..Thank u
clc
close all;
clear all;
ber2=[];
N = 10^6; % number of bits or symbols
x = randint(1,N);

for i=1:length(x)
y1(i)=1; y11(i)=-1;

if x(i)==1
s(i)=y1(i);
else
if x(i)==0
s(i)=y11(i);
end
end
end
s;
scatterplot(s);
n = 1/sqrt(2)*[randn(1,N) + j*randn(1,N)];%AWGN
ber=[];
SNR_dB = [-3:35];
snr=10.^((SNR_dB)/10);
for i = 1:length(SNR_dB)
y = awgn(s,i);
y_hat = real(y)>0;
[n,b]=biterr(x,y_hat);
ber=[ber,b];
end
ber2=[ber2;ber];
figure()
form_ber = 0.5*erfc(sqrt(snr)); % theoretical ber
semilogy(SNR_dB,form_ber,’g.-’);
hold on
semilogy(SNR_dB,ber2,’bs-’)
legend(‘theoretical BER’,'practical BER’)
axis([-3 10 10^-5 1])
grid on

Krishna Sankar December 30, 2011 at 4:53 am

@Thiyagi: The code looks ok. You can check couple of points:
a) awgn : whether the noise power is as expected. Maybe you can try with ‘measured’ option.
From Mathworks http://www.mathworks.in/help/toolbox/comm/ref/awgn.html
“y = awgn(x,snr,’measured’) is the same as y = awgn(x,snr), except that awgn measures the power of x before adding noise.”

b) Counting the number of error. That piece of code looks funny. Did not understand the need for ber and ber2.
Should be easy for you to figure out.

Krishna Sankar December 30, 2011 at 4:53 am

@Thiyagi : ok, good

sarah December 21, 2011 at 2:12 am

hai,
i would like to know why in y = s + 10^(-Eb_N0_dB(ii)/20) we use a negative sign her e for eb no.

Krishna Sankar January 3, 2012 at 4:44 am

@sarah: The -ve sign is to scale down the noise signal with respect to desired signal

Talib December 20, 2011 at 11:06 pm

1.10^(-Eb_N0_dB(ii)/20)*n
2.10^(-Eb_N0_dB(ii)/10)

i want to answer the confusion of /20 why not by /10?

In fact sir Krishna Pillai want to make noise variance equal to 1 or 0dB.
you can check by command max((10^(-Eb_N0_dB(ii)/20)*n))= 1.01 where as
max((10^(-Eb_N0_dB(ii)/10)*n))= 0.3251 so its clear scaling…..remember before these commands i just removed the complex part i.e n = 1/sqrt(2)*[randn(1,N)]; for my easyness.

I also noticed that this scaling change for system to system e.g for non coherent 4FSK -it becomes like (10^(-sqrt(2)*Es_2N0_dB(ii)/20))*n becoz in 4FSK i need variance 0.5.so i scaled it to 0.5 by just multiplying by sqrt(2)

Krishna Sankar January 3, 2012 at 4:48 am

@Talib: Replies:
1. The /20 is to scale the noise voltage signal. Using max is not a good idea
2. I think for FSK coherent demodulation, which uses 0/1 modulation has 3dB poorer BERwhen compared to BPSK
http://www.dsplog.com/2007/08/30/bit-error-rate-for-frequency-shift-keying-with-coherent-demodulation/

Emmanuel December 7, 2011 at 12:32 pm

Do you have code on how to generate a NRZ signal?

And do you have code on how to generate the eye diagram. Thanks.

Krishna Sankar December 8, 2011 at 5:49 am
Guhan May 19, 2011 at 6:44 pm

Hi krishna,

Could i have codings with different modulations with different subcarriers for any one user in MIMO OFDM system .output shouild be throughput versus time or ber and time.please help me sir.Thank you in advance

Krishna Sankar May 23, 2011 at 2:34 am

@Guhan: Yes, you can have independent modulation on different subcarriers.

Marcos Amaral May 17, 2011 at 2:51 am

Hello Krishna Sankar,

I am doing some research on chaotic carriers and I was planing to make this BER for comparison.
Your post save me a lot of time to focus on the real subject of my work.
Thank you very much for the help!

Regards from Brazil
Marcos Amaral

Krishna Sankar May 23, 2011 at 3:05 am

@Marcos: Thanks.

Nikhil May 14, 2011 at 2:16 am

hi krishna,
http://dspace.mit.edu/openaccess-disseminate/1721.1/52384

Krishna Sankar May 24, 2011 at 5:16 am

@Nikhil: Sorry, I have not looked into that paper.

moyeen May 6, 2011 at 1:48 pm

Hi Krishna,

I am working on different modulation technique. I am badly needed BER code of QPSK, (QAM 16,64)with AWGN channel.I have to submit my paper on 30may2011.

moyeen

Krishna Sankar May 24, 2011 at 5:32 am

@moyeen: You can refer to the post on BER for 16QAM with Gray coding
http://www.dsplog.com/2008/06/05/16qam-bit-error-gray-mapping/

Moyeen May 5, 2011 at 10:03 am

Dear krishna
impressive works! hay, can you provide me simulation codes for BPSK, QPSK, 16QAM & 64QAM with AWGN channel in OFDMA modulation? these would be very much helpful for my thesis. thank you.
Moyeen

Krishna Sankar May 24, 2011 at 5:34 am
Sara December 3, 2010 at 9:12 pm

Hello Krishna,
I have a question.. I am hoping to design a OFDM communication system…
If you were to design an OFDM communication system.. what and where would u start from?
Regards
Sara

Krishna Sankar May 26, 2011 at 6:04 am

@Sara: You should know your available bandwidth, then chose your subcarrier spacing and so on

Elayan November 2, 2010 at 8:18 pm

Hi Krishna,

is it the same to 16-PSK and just change M=8 only?
or there is other things that i should to change ?
becouse when i changed M to 8 i got an output and no errors
pls answer me it’s very importanat
thanks alot man

Krishna Sankar November 15, 2010 at 2:12 am

@Elayan: Yes, I guess changing M to 8 should suffice.

ahmed November 1, 2010 at 12:37 pm

hi
i m doing graduation we have a project in which we have to design the communication sysem in which data+modulation(bpsk and 8-psk)+awgn then threshold detector and then we had to compute bit error rate.. can you help me in this…..

Krishna Sankar November 15, 2010 at 2:14 am

@Ahmed:
For 8 PSK case, you may use the article on 16PSK as a reference
[symbol error rate] http://www.dsplog.com/2008/03/18/symbol-error-rate-for-16psk/
[bit error rate] http://www.dsplog.com/2008/05/18/bit-error-rate-for-16psk-modulation-using-gray-mapping/

hamdirajeh October 14, 2010 at 12:03 am

its very useful thanx , do u know how can i get the simulink for this code ,please?

Krishna Sankar November 17, 2010 at 5:32 am

@hamdirajeh: Sorry, I do not have simulink code

jansi September 3, 2010 at 6:47 pm

dear krishna,
i need to simulate BPSK modulation to analyse the bit error rate in AWGN channel and reyleigh fading channel for different SNR.the carrier frequency should be 20MHz.if u hav matlab codes for dis,help me.m running out of time.

Krishna Sankar September 6, 2010 at 5:15 am
avdhut August 26, 2010 at 9:06 pm

hey…
will u plz giv code for gmsk…

Krishna Sankar September 1, 2010 at 7:04 am
weather July 30, 2010 at 8:52 am

But I have question about the comment of this line in your codes
s = 2*m-1; % BPSK modulation 0 -> -1; 1 -> 0
I think maybe you want to change original 0 to -1, but 1 should be no change, is it?

Krishna Sankar August 2, 2010 at 5:46 am

@weather: Thanks for noticing the typo in the comment. I corrected it.

Ajith July 24, 2010 at 4:46 pm

Oops i am sorry if this is a total blunder.. In digital modulation techniques we modulate a sine or a cos wave using bits and transmit them as sine or cos waves.. But in this code for BPSK modulation I never found the usage of such things.. could you please clarify my doubts in simple words… Regards Ajith

Krishna Sankar July 25, 2010 at 4:32 am

@Ajith: No, its not a blunder at all, tt’s a genuine query. There are two aspects to the reply.
a) In the case of baseband transmissions, we send the information on pulses and in the most simplest case, we send out rectangular pulses of varying amplitude to convey the information (or we can do some better pulse shaping to reduce the out of band emissions, while not introducing ISI)
b) In the case of pass band transmissions, we do the pulse shaping, then upconvert to a carrier and then transmit.

In both (a) and (b), for computing BER, the results which we get even if we do not simulate pulse shaping + up conversion is same as the one without it (assuming, we undo the operations optimally). Hence did not put those in place.

Further, I have written a post doing BER computation with rectangular pulse shaping with matched filtering
http://www.dsplog.com/2009/05/08/ber-with-matched-filtering/

prashant goad July 20, 2010 at 3:00 pm

hey krushna
but i need it’s paper too. can u send it to me plzzz

Krishna Sankar July 21, 2010 at 6:00 am

@prashant: I referred the text book Digital Communication by Proakis

Ayesha313 July 18, 2010 at 3:47 pm

hello sir
can you please guide me,how can i plot BER error rate of uncoded and coded BPSK
i know the formula of BER for Uncoded BPSK ,i have plotted it,but I am really cunfused about the Coded Bpsk,I am using BCH codes which are block codes

Krishna Sankar July 23, 2010 at 7:07 am
Ayesha313 July 27, 2010 at 8:58 pm

Thanks alot sir for your precious time and guidance

rama krishna June 25, 2010 at 3:43 pm

hello sir …
in BPSK constallation we map bit 1 to sqrt(Eb) and 0 to -sqrt(Eb). these are real points then why to add complex noise …we can directly add real noise of unit variance as follows…
N = 10^6 % number of bits or symbols
rand(‘state’,100); % initializing the rand() function
randn(‘state’,200); % initializing the randn() function

% Transmitter
ip = rand(1,N)>0.5; % generating 0,1 with equal probability
s = 2*ip-1; % BPSK modulation 0 -> -1; 1 -> 0
n = randn(1,N) ; % white gaussian noise, 0dB variance
Eb_N0_dB = [-3:10]; % multiple Eb/N0 values

for ii = 1:length(Eb_N0_dB)
y = s + 10^(-Eb_N0_dB(ii)/20)*n; % additive white gaussian noise

% receiver – hard decision decoding
ipHat = real(y)>0;

% counting the errors
nErr(ii) = size(find([ip- ipHat]),2);

end

or we can use awgn function to pass through awgn channel which will add real noise if data is real and will add complex noise if data is complex… if i proceed in that way the performance is not matching with the theoritical analasys… can u explain me clearly why should we add complex noise…
Thanking u sir

Krishna Sankar June 28, 2010 at 6:13 am

@rama krishna: Adding complex noise does not affect the end result (as we are ignoring the imaginary part at the receiver). However, just make sure that scaling is correct. You should multiply factor of 1/sqrt(2) to the noise term which you have defined.

Ny Sokunthea September 26, 2014 at 3:43 pm

The same to code of rama krishna wrote, could I modify it from BPSK to ASK. How?

chandra April 27, 2010 at 6:02 pm

Hi sir,
I want some programmes on DAPSK(differential amplitude phase shift keying) in OFDM systems.Is there any matlab codes in DAPSK.Please reply me as soon as possible.
Thanks,
regards,
chandra

Krishna Sankar April 28, 2010 at 5:49 am

@chandra: Sorry, no posts on DAPSK. The closest which I have discussed for ASK is the 4-PAM case
http://www.dsplog.com/2007/10/07/symbol-error-rate-for-pam/
Hope this helps

STIVE CHLEF April 24, 2010 at 12:37 am

Hi Krishna Pillai ..
I whant to simulate BER for BPSK but for 5 or 6 user not for 1 user
what is the changement applicated in this programme.

Krishna Sankar April 27, 2010 at 5:22 am

@STIVE CHLEF: Well, if you have 5/6 users, how are you planning to distinguish them at the receiver?

hakar April 18, 2010 at 6:52 pm

beatiful work krishna, i wonder if you have the same simulation for QPSK in matlab…thanks

eca April 13, 2010 at 9:08 pm

dear sir Krishna Sankar
I am very happy to find your blog … and found what I was looking for … I am a student majoring in telecommunications engineering and was doing the final tasks of rain attenuation, said supervisors told to discover how much value other than tresshold BER for MQAM rmodulasi … I want to ask how can I download the book John Proakis as an accurate reference book saya.Mohon bantuanya final … and also how the graph of the BER curve modulation 16…………

Krishna Sankar April 14, 2010 at 5:01 am

@eca: You can try purchasing Digital Communications by Proakis

fizzle April 8, 2010 at 2:03 pm

pls i need a matlab program for signal to noise ratio in a wireless communications system.. how do i do the write up for the matlab program??

Krishna Sankar April 13, 2010 at 6:18 am

@fizzle: Well, if you divide signal power by noise power, the resultant is signal to noise ratio

vj1892 March 29, 2010 at 9:31 pm

your kind guidance on MATLAB has been really a great help for MATLAB starters. hope u will continue in future too.

Krishna Sankar March 30, 2010 at 4:12 am

@vj1892: Thanks

amit March 23, 2010 at 11:43 pm

Hi,
Can anyone help me in my project!!!
i Have read here that there is no difference between BER vs SNR in case of BPSK and OFDM using BPSK.
But my project guide has told me to mathematically prove that BER vs SNR is better for OFDM using BPSK than simple BPSK.
Suppose there is N no. of subcarrier.Then for each subcarrier there will be BER.But if i want to calculate the total BER for n no. of sub carrier then how the BER of indivisual subcarriers are related???

Krishna Sankar March 28, 2010 at 1:51 pm

@amit: In AWGN there is no difference between using BER for BPSK and BER for BPSK using OFDM.

Ananya March 21, 2010 at 6:28 pm

hello sir,
m doing ma project on ber calculation using matlab simulation for ofdm transmission for multipath wireless communication so please if u cud help me out in knowing which book wud b d best 2 go through….where i wud b getting much of d information regarding d basics of ofdm , transmission n reception of signls using ofdm, n n… ber calculation n its various graphs hw 2 plot dm n al….
please do help me out sir in dis ……m very confused abt dis…..

Krishna Sankar March 28, 2010 at 1:55 pm
rekha March 4, 2010 at 6:34 pm

hello sir,
please give us an idea how to analyse matlab code for ofdm-awgn channel with that of theory. what are the pilots and why are they used?

Krishna Sankar March 30, 2010 at 4:33 am

@rekha: The BER performance of OFDM in AWGN is comparable to the no OFDM case. http://www.dsplog.com/2008/06/10/ofdm-bpsk-bit-error/

DaMarco February 27, 2010 at 3:35 pm

Hi There,

I need to design and develop a simulation platform in C/C++ to simulate the performance for BPSK- and 8PSK modulation through an AWGN channel and evaluate the biterror rate (BER) performance for BPSK and 8PSK in the range Eb/N0 2 [−4, 8] dB.Can you help me with any suggestion or source code.

Krishna Sankar March 30, 2010 at 5:00 am

@DaMarco: You can use the Matlab model provided in this post as a reference for the C code

gurinder February 27, 2010 at 11:28 am

respected sir
please can u help me in providing matlab code for rs codes using interleaver &qam in awgn channel
i will be thankful to u

Krishna Sankar March 30, 2010 at 5:19 am

@gurinder: I have not discussed ReedSolomon codes in dsplog.com yet. Hope to do so

anne na February 4, 2010 at 2:24 pm

hi,

I would like to demodulate QPSK but using soft decision. can you help me or guide me how I want to do this? I try the matlab function using

demodh= modem.pskdemod(ht, ‘outputType’, ‘bit’,'DecisionType’, ‘LLR’, ‘NoiseVariance’, sigma);
dec_inputt=demodulate(demodh,rt);

but the bit that I’m receive sort like it have inverse sign.
for example: if I transmit bit : 1; 0; 1 ,
I received : -10.8; +9.7; -11.2.
I’m expecting that : +10.8;-9.7;+11.2.

Or is it LLR gives this inverse sign? TQ so much if you can help me.

Krishna Sankar April 4, 2010 at 4:24 am

@anne na: Why are you using soft decision, unless you have some decoder like Viterbi following your demapper. Anyhow, I have discussed about softbit for 16QAM @ http://www.dsplog.com/2009/07/05/softbit-16qam/

anis January 28, 2010 at 4:04 pm

Hi there,
i just wondering why we need to initialize the rand and randn function?

Krishna Sankar April 4, 2010 at 4:50 am

@anis: If we initialize, we can ensure that the same random numbers are generated in any run

kishore January 25, 2010 at 9:07 pm

Hi krishna!

I need matlab code to obtain BER vs SNR curve for binary on-off keying.
also ,code for generating SER vs SNR curve for 3ASK modulation

Amjad January 10, 2010 at 12:47 pm

Dear Krishna,

Can you little bit tell me how to simulate the Uncoded BER and ergodic capacity for webb channel using QPPM modulation.

Amjad January 10, 2010 at 7:06 am

Dear Krishna,

Can you little bit tell me how to simulate the Uncoded BER and ergodic capacity for webb channel using QPPM modulation.

Anvesh January 6, 2010 at 7:49 pm

haiiiiiii
i need Matlab code for digital modulation techniques.

abhishek January 4, 2010 at 8:00 pm

please give help about matlab code in optimization for co channel and adjacent channel interference using ANN

Winnie December 31, 2009 at 8:42 am

Hi Krishna,
I know the BER of BPSK is 0.5*erfc(sqrt(10.^(Eb_N0_dB/10))),
if I put channel coding before the modulation,and the code rate is R,
then if the BER equals 0.5*erfc(sqrt(R*10.^(Eb_N0_dB/10)))?
then BER with code rate 1/2 is higher than 3/4,but acturally ,it should be
lower. where is my mistake ?

Hoping for your help, thank you

Student

Mitoo2007 December 27, 2009 at 3:10 am

please can u help me in this project ::::–

2) final report(OFDM):

* genearte large no of bits using randint

* modulate the data once with bpsk & then 16-QAM

* bpsk mod is 2*data-1

* after modulation u should loop on the data with step of 64′s

each time calculating their ifft

* add the noise to each 64

* if u remeber how to add noise then do it as u know,
else use awgn

sigandnoise=awgn(signal, SNR in dB , ‘measured’ )

* do fft with steps of 64′s , the same groups of symbols that were ifft’ed

* demodulate the data ( if bpsk then bits= recdata > 0)

*calculate ber using
ber=sum(xor( transmitted bits , received bits ) )

* the whole program should be done in a large loop that loops over

SNR -5 -> 15

multiply with channel before ifft then divide after ifft

* multiplication is done using (.*) not just (*)

adah December 21, 2009 at 4:36 am

dear krishna…

From my past question, actually i got my result and understand..but..i have a problem with my coding…can you help me please…
My coding…
%directional antenna
d=100;
Pt=100:100:1000;
theta10=10*pi/180;
v=int(‘cos(x)*sin(x)’,0,pi/2);
x=int(v,’x',0,2*pi);
gt10=(4*pi)*cos(theta10)/double(x);
grd=180*pi/180;
c=3e8;
f=2.4e9;
L=1;
lamda=c/f;
Pr10=(Pt.*gt10.*grd)./(((4.*pi.*d)./lamda).^2)*L;

%power noise
k=1.38e-23; %k=Boltzman’s constant
t=300; %t=noise temperature in Kelvin
b=5e6; %b=bandwidth
Pn=k*t*b;

%directional antenna
snr10=Pr10/Pn;

Rb=54e6;
ebno10=snr10/Rb;

ebno101=10.*log10(ebno10);

N = 10^6; % number of bits or symbols
rand(‘state’,100); % initializing the rand() function
randn(‘state’,200); % initializing the randn() function

% Transmitter
ip = rand(1,N)>0.5; % generating 0,1 with equal probability
s = 2*ip-1; % BPSK modulation 0 -> -1; 1 -> 0
n = 1/sqrt(2)*[randn(1,N) + j*randn(1,N)]; % white gaussian noise, 0dB variance
% Eb_N0_dB = [-3:10]; % multiple Eb/N0 values
% k=1:1:10;
%
% for ii = 1:length(k)
% yomni = s + 10.^(-k(ii)./20)*n; % additive white gaussian noise
%
% % receiver – hard decision decoding
% ipHatomni = real(yomni)>0;
%
% % counting the errors
% nErromni(ii) = size(find([ip- ipHatomni]),2);
%
% end

for ii = 1:length(ebno101)
y10 = s + 10.^(-ebno101(ii)./20)*n; % additive white gaussian noise

% receiver – hard decision decoding
ipHat10 = real(y10)>0;

% counting the errors
nErr10(ii) = size(find([ip- ipHat10]),2);

end

simBer10 = nErr10./N;
k1=1:1:10

figure
%semilogy(k,simBeromni,k1,simBer10)
semilogy(k1,simBer10)
grid on
legend(‘theta=10′)
xlabel(‘Eb/No, dB’);
ylabel(‘Bit Error Rate’);
title(‘Bit error probability curve for BPSK modulation in simulation’);

when i changed the Pt=10:10:100; actually i got the result..can you help me pliz….

thanks a lot…

Krishna Sankar December 23, 2009 at 5:47 am

@adah: what is the problem which you are seeing?

adah December 30, 2009 at 7:12 am

dear krishna…

In theory, when i applied my SNR into your coding, i got the result.
But, when i applied my SNR into your coding for simulation, i got the problem. I think that problem occurred at SNR or BER. But i dont know where my coding is problem? Can you help me pliz…
Thanks a lot..

waheed December 17, 2009 at 6:23 pm

Hello friends: i am working on MAP , ML decoding for convolutional codes..is there any one who too work on similar field ..?

Krishna Sankar December 23, 2009 at 5:29 am

@waheed: For the Viterbi way of ML decoding, you may look at
http://www.dsplog.com/tag/viterbi

mouhamed December 16, 2009 at 10:04 pm

Krishna Sankar December 23, 2009 at 5:25 am

rama krishna December 14, 2009 at 11:29 am

i am doing simualtion to find the ber of bpsk modulation in pass band case.could you help me.

Krishna Sankar December 22, 2009 at 5:39 am

adah December 10, 2009 at 5:41 am

Hi Krishna,

Actually, im studying about your coding for BER vs SNR for BPSK modulation. For simulation, when i changed the value for EbNodB = [-3:10] to [1:10], i cant get the result. why this problem happened?

Krishna Sankar December 10, 2009 at 10:12 am

@adah: What is the error which you are getting?

fatima December 7, 2009 at 1:20 am

Hi Krishna
I need to Simulink Probability of error for binary symmetric channel if you don’t mind.

Krishna Sankar December 7, 2009 at 5:33 am

@fatima: I believe it should be reasonably straightforward to modify the gaussian channel used in this post to a binary symmetric channel. good luck.

shadat December 6, 2009 at 2:09 pm

hi krisna,
i hope you are fine.plz could you send me BPSK,QPSK,16QAM,64QAM modulation and demodulation simulation in matlab and simulation of adaptive modulation of convolutionaly coded for BPSK,QPSK,16QAM,64QAM?please help me.

Krishna Sankar December 7, 2009 at 5:27 am
Krishna Sankar December 7, 2009 at 5:27 am
rai December 3, 2009 at 9:10 am

is erfc equal Q function?

Krishna Sankar December 7, 2009 at 5:09 am

@rai: No, erfc is not equal to Q function, but both are related.
http://en.wikipedia.org/wiki/Q-function

alok joshi November 27, 2009 at 7:48 pm

hi sir
i have problem in BPSK with RS codes…..when i/p is given to pskmod function it says that “does not support complex airthmatic”.however i/p given is in 1 0 form

Krishna Sankar December 7, 2009 at 4:42 am

@alok joshi: Sorry, I do not have the pskmod() function.

Obinna O November 26, 2009 at 1:09 am

Please guys I am having trouble writing a code for non coherent detection, I am required as part of my project to Assume Rayleigh fading channel with BPSK modulation. Using MAT-LAB plot bit error probability (BEP) under non-coherent de-tection. Your ¯gures should include plots from both analysis and simulation.Use average SNR (complex) from -5 to 20 dB.

Thanks a lot, i will be very grate ful to get help from you guys.

Krishna Sankar December 7, 2009 at 4:38 am

@Obinna O: Hope you have finished the project by now. Hope this post might be of help
http://www.dsplog.com/2008/08/10/ber-bpsk-rayleigh-channel/

Hamid November 25, 2009 at 4:37 pm

hi

Why you are using 10^(-Eb_No_db(ii)/20) the minus sign in this formula because for voltage scaling it should be 10^(Eb_No_db(ii)/20).

Krishna Sankar December 7, 2009 at 4:34 am

@Hamid: The negative sign came as I am scaling the noise voltage. I am keeping the signal swing the same and reducing the swing of noise voltage to simulate various Eb/N0 values.

Faisal November 11, 2009 at 2:20 am

I am working on an adaptive modulation model on Simulink. For that first I am trying to get probability of error rate vs snr of different modulation techniques. On modelling 16 QAM modem I have problem plotting its graph by getting bit err rate from simulink model and performing graph plotting on matlab. following is the code im using in matlab..

clear; clf;
snr=0:10;
err_vec=[];

for i=1:length(snr)
EbNo=snr(i);
sim(‘QAM_16′);
err_vec(i)=bit_err_rate(1);
end;
semilogy(EbNo,err_vec,’b-*’);
grid on

please guide what is the error in this code… thanks

Krishna Sankar November 13, 2009 at 5:34 am

@Faisal: For BPSK,
Eb_N0_dB = [-3:10];
theoryBer = 0.5*erfc(sqrt(10.^(Eb_N0_dB/10))); % theoretical ber
close all; figure;
semilogy(Eb_N0_dB,theoryBer,’b.-’);

Jatin Chakravarti November 10, 2009 at 11:18 pm

Hi…
I need to Simulink Probability of error for PSK, 16QAM & MFSK. but don’t know how to simulink the equation: Pe=0.5*erfc(sqrt(snr)).
I tried to call the fuction from Matlab using Embedded Function Block in Simulink. But, the program din’t work. Can u suggest me a Block for finding Pe or a Program to call from .m file..?

Krishna Sankar November 13, 2009 at 5:31 am

@Jatin: Does this help?
Eb_N0_dB = [-3:10];
theoryBer = 0.5*erfc(sqrt(10.^(Eb_N0_dB/10))); % theoretical ber
close all; figure;
semilogy(Eb_N0_dB,theoryBer,’b.-’);

student November 10, 2009 at 9:03 pm

Hi Krishna,

I was working on a IEEE paper titled”Xiaodi Zhang and N.C. Beaulieu, “A Closed-Form BER Expression for BPSK Using MRC in Correlated CCI and Rayleigh Fading,” IEEE Trans. Communications, vol. 55, no. 12, pp. 2249-2252, Dec. 2007.”.
Since you have also worked on similar field, I hope u can help me..

I was stuck with re creating the 1st fig in the paper.
SO, can you please look into it and help me out..

Thanks,
Student

Krishna Sankar November 13, 2009 at 5:29 am

@student: Sorry, due to time constraints, may I pass that opportunity. Good luck.

Egerue Nnamdi November 10, 2009 at 3:42 pm

Hi krishna
Pls in essence how and where do we set the different values for EbNo/ or S/N or SNR to achieve different BER plots using your simulation example. Pls i will appreciate ur reply.

Thanks

Egerue Nnamdi November 9, 2009 at 3:09 am

Hi krishna
Pls in essence how and where do we set the different values for EbNo/ or S/N or SNR to achieve different BER plots using your simulation example. Pls i will appreciate ur reply.

Thanks

Krishna Sankar November 12, 2009 at 5:39 am

@Egerue: Change Eb_N0_dB

Egerue Nnamdi November 9, 2009 at 2:29 am

Hi Krishna.
Thank you very much. God will bless you. Below is the answer you gave me for my concern on this formular 10^(-Eb_N0_dB(ii)/20)*n
“Do not change the division factor. Rather change the value of Eb_N0_dB. The division by 20 is required to convert dB into voltage”.
Please give me more direction, by giving me an example of what you mean by changing the VALUE of Eb_No_dB. or how do we get the value
Am thinking is Eb_No_dB =[0:10], [0:20], [0:30] and so on, but am not very sure. Pls, you are indeed a very good teacher, help me out

Thanks, you are really very helpful, you must really reap the fruit of your efforts.
NNAMDI

Egerue Nnamdi November 8, 2009 at 8:00 pm

Hi Krishna.
Thank you very much. God will bless you. Below is the answer you gave me for my concern on this formular 10^(-Eb_N0_dB(ii)/20)*n
“Do not change the division factor. Rather change the value of Eb_N0_dB. The division by 20 is required to convert dB into voltage”.
Please give me more direction, by giving me an example of what you mean by changing the VALUE of Eb_No_dB.
Am thinking is Eb_No_dB =[0:10], [0:20], [0:30] and so on, but am not very sure. Pls, you are indeed a very good teacher, help me out

Thanks, you are really very helpful, you must really reap the fruit of your efforts.
NNAMDI

Krishna Sankar November 12, 2009 at 5:33 am

@Egerue:
You are right.
Eb_No_dB =[0:10], –> 0 to 10dB in steps of 1dB
Eb_No_dB =[0:20], –> 0 to 20dB in steps of 1dB
Eb_No_dB =[0:30], –> 0 to 30dB in steps of 1dB

Egerue Nnamdi November 4, 2009 at 2:19 pm

Hi krishna, I have actually read the answers given to you by the concerns generated by the formula below
10^(-Eb_N0_dB(ii)/20)*n
for further clarification, i have actually divided by 18,16,14,12——3 to get different plots that actually decreases down the graph . Want to know if is how one can plot for BER with variable noise in the channel. I will appreciate if you reply me soon. Thanks

Egerue Nnamdi November 2, 2009 at 10:26 pm

Hi krishna, I have actually read the answers given to you by the concerns generated by the formula below
10^(-Eb_N0_dB(ii)/20)*n
for further clarification, i have actually divided by 18,16,14,12——3 to get different plots that actually decreases down the graph . Want to know if is how one can plot for BER with variable noise in the channel. I will appreciate if you reply me soon. Thanks

Krishna Sankar November 8, 2009 at 8:39 am

@Egerue: Do not change the division factor. Rather change the value of Eb_N0_dB. The division by 20 is required to convert dB into voltage.

3mor October 25, 2009 at 2:59 pm

Hi Krishna,

thanx a lot for your website

i have a simple question:

what about the unequally probable, e.g. when P(s0)=0.25 & P(s1)=0.75 ??

Krishna Sankar October 27, 2009 at 5:45 am

@3mor: If the probabilities are un equal, we would want to shift the threshold for making the decision. The chapter 5.1.3 Digital Communications by John Proakis discuss that case.

christine October 13, 2009 at 11:21 am

Thank you for this website ,it is awesome
could you help me to know what is the role of the following

rand(‘state’,100); % initializing the rand() function
randn(‘state’,200); % initializing the randn() function
thank you

Krishna Sankar October 15, 2009 at 5:22 am

@christine: The random numbers generated by the program can be initialized to enable us to run multiple simulations with the ‘exact same’ random numbers . Setting the state of the rand() or randn() enables one to do so.

Ajay Pratap Singh October 8, 2009 at 2:07 pm

This Krishna Pillai guy is a great help and his website undoubtedly very good resource on communication system topic. I got necessary informations about Vitervi Algorithm, Hard and soft decision.

Ajay Pratap Singh apts

Krishna Sankar October 12, 2009 at 5:27 am

@Ajay: Thanks for the nice words.

najat October 8, 2009 at 12:44 am

Dear Krishna:
I knew that OFDM technique, improve the BER performance in frequency selective fading channel, Can you help me in writing code using matlab program show that , I have probem in how write code for frequence selective fading.
Thank you .

ahmed October 8, 2009 at 12:42 am

I knew that OFDM technique, improve the BER performance in frequency selective fading channel, Can you help me in writing code using matlab program show that , I have probem in how write code for frequence selective fading.
Thank you .

Krishna Sankar October 8, 2009 at 5:41 am

@ahmed: In OFDM, though the channel is frequency selective, channel as seen by each subcarrier is flat. Hence the expression for flat fading holds good. Please refer to the post http://www.dsplog.com/2008/08/26/ofdm-rayleigh-channel-ber-bpsk/

Hung October 7, 2009 at 8:00 am

hello Krishna Pillai!
I’m a student in Ho Chi Minh City, Viet Nam. I’m searching about “the impact of real channel over MiMo system”. your code is useful. So, we assume that receiver is unknown h matrix and we must explore channel by channel estimation. Do you help me?
Hope you will response me!

Krishna Sankar October 8, 2009 at 5:35 am

@Hung: Yes, the receiver is trained to estimate the MIMO channel by sending known preamble.

Anvesh September 13, 2009 at 11:37 am

Thanks a lot, man.
Was very useful.

thenmozhi September 5, 2009 at 9:30 pm

can you send me the matlab coding for physical layer network coding modulation

Krishna Sankar September 9, 2009 at 5:43 am

@thenmozhi: Sorry, I do not have matlab code for physical layer network coding modulation

Tito August 27, 2009 at 5:28 pm

Hi Krishna,

I am working on Forward error correction codes. I have plotted the BER performance curve for Reed solomon codes using BPSK modulation over an AWGN channel from EbNo 0 – 1 . However, the curves are overlapping at the begining between EbNo values 0 and 1 and also in the middle.

Also the curves for convolutional codes overlap at the begining between 0 and 1. and also in the concatenated codes.

Could you please give me a detailed explanationc on the reason why the overlapping occurs and the significance.

The RS codes used were RS(255,191), RS(255,223), RS(255,239) and RS(255,247).
Thanks, hope to hear from you soon.

Krishna Sankar September 7, 2009 at 5:13 am

@Tito: Firstly, a clarification. When you mentioned about “curve-overlapping”, I guess you meant that – “with coding, the BER becomes poorer than no coding for very low values of Eb/N0″. Agree?

At-least with respect to convolutional codes, I think it can be attributed to the large number of errors in received coded bits, which makes the Viterbi algorithm go haywire.

Tito September 8, 2009 at 7:28 pm

Thanks that is exactly what i mean. Why does this occur.
And i also have an curve RS curve with and without an interleaver, these curves are overlapping at two points. Why does this occur.

I.Selvadenniz August 17, 2009 at 5:51 pm

hi,can any one help me to derive BER for physical layer network coding(PNC) modulation scheme…:-)

Krishna Sankar August 18, 2009 at 3:53 am

@Selvadenniz: Sorry, have not studied PNC coding.

tommy October 16, 2009 at 5:19 pm

hiii… you have BER for physical layer network coding(PNC) modulation scheme….

Krishna Sankar October 17, 2009 at 4:15 am

@tommy: Sorry, no

Alex August 14, 2009 at 5:00 am

Hi Pillai

I would like to ask you a simple question. I am trying to make a simple simulation using a matlab. It is about that one node using SF(spreading factor)=2, and another node using SF = 8 (orthogonal to each) are encoding the data and sending to one node (asynchronous network) with same power but from different distance at the same time. how can i simulate it? when decoding at the receiver, it uses same ovsf code as the node using SF = 8.

Krishna Sankar August 14, 2009 at 5:15 am

@Alex: Well, let me try to write the pseudo code for this case
y1 = x1*code1; % code with SF=2
y2 = x2*code2; % code with SF=8
n = noise; % AWGN noise, lets take mean=0, variance = 1
r1 = y1*scaling1; % scaling factor for first signal
r2 = y2*scaling2; % scaling factor for second signal
r = r1+r2+n; % receiver collects both signals corrupted by noise
x2Hat = r*code2 % receiver tries to correlate r with code2 to recover x2.

Makes sense?

sam August 1, 2009 at 1:51 pm

hi everybody
i need simulink’s (matlab) block for accunting BPSK BER

Diego July 31, 2009 at 5:54 am

Hi, my english is not very good looking, but…what is the noise variance for 16QAM and 64QAM?, AWGN channel.

Krishna Sankar August 5, 2009 at 5:39 am

@Diego: The noise variance is independent of the modulation scheme. However, I think you might be looking for error rate for different modulation schemes for a given value of noise variance. You may refer posts:
http://www.dsplog.com/2008/06/05/16qam-bit-error-gray-mapping/
http://www.dsplog.com/2008/03/29/comparing-16psk-vs-16qam-for-symbol-error-rate/
http://www.dsplog.com/2007/12/09/symbol-error-rate-for-16-qam/
http://www.dsplog.com/2008/07/08/compare-bpsk-qpsk-4pam-16qam-16psk-64qam-32psk/

sam July 30, 2009 at 2:29 pm

hi kirishna pillai
i need simulink’s (matlab) block for accunting BPSK BER
thanks

Krishna Sankar July 31, 2009 at 4:53 am

@sam: Sorry, I do not have Simulink.

gdkorde July 25, 2009 at 6:01 pm

plz help me for changing code rate and delay spread in bpsk modulation used in hiperlan/2

Krishna Pillai July 28, 2009 at 4:29 am

@gdkorde: Quick questions:
1/ What is the coding technique used ? Convolutional coding?
2/ What is the model of the multipath channel? Exponential model?

leth July 18, 2009 at 10:07 am

hi can you tell me how to make adaptive modulation ?

thanks

leth July 18, 2009 at 9:04 am

hi
i need matlab code for adaptive modulation from BPSK,QPSK,16QAM,64QAM

so if you have not such code, i hope to guide me how to make it , as you know for low SNR we use like BPSK and for high SNR use like 64QAM

so how to make this via matlab?

regards

Krishna Pillai July 19, 2009 at 8:58 am

@leth: I do not have a code combining BPSK/QPSK/QAM etc to do adaptive modulation. However, you may find individual posts describing these modulation schemes @ http://www.dsplog.com/2008/10/01/download-free-e-book/
As you said, one way to make an adaptive modulation scheme is to define a BER threshold (lets say 10^04) to switch from one modulation scheme to another.

Vijay July 7, 2009 at 11:05 am

Hi, I am want to plot the pdf for various SNR(Symbol Error) for various modulation schemes. Do you have matlab code for it.

The derivation in this link is SER Vs SNR, How to change the SER to PDF(of SNR)?

Krishna Pillai July 15, 2009 at 4:42 am

@Vijay: I have written an article on error rate for various modulation schemes in dspdesignline.com @
http://www.dspdesignline.com/howto/208801783;jsessionid=3ISGUXHINOVIAQSNDLRSKHSCJUNN2JVN?pgno=1

Further, you may also check out the post

BOUHAFS July 1, 2009 at 10:18 pm

please simulation for BER MIMO (2,2)

Krishna Pillai July 2, 2009 at 5:24 am

@BOUHAFS: Please refer to the post
http://www.dsplog.com/2008/10/24/mimo-zero-forcing/

Moon June 29, 2009 at 5:39 pm

i have some question
1. y = s + 10^(-Eb_N0_dB(ii)/20)*n;
2. theoryBer = 0.5*erfc(sqrt(10.^(Eb_N0_dB/10)))
i dont know why Eb_N0_dB(ii) has minus value…
and
At first term,^(-Eb_N0_dB(ii) is divided by 20 but, at second term Eb_N0_dB is divided by 10.
Why Eb_N0_dB is divided by diferrent value??
My question is very poor, nevertheless i will wait for your comment
Have a nice day

Krishna Pillai June 30, 2009 at 5:14 am

@Moon: My replies
1/ Before this scaling, the signal term s and the noise term n has the same variance of 1. The term -Eb_N0_dB reduces the noise variance
2/ The scaling is happening on the noise voltage signal, hence the factor of 1/20. In the theoretical equation, note that there is a square root term outside the 1/10 factor. This is equivalent to having 1/20 factor. Agree?

Srinivas June 27, 2009 at 10:25 pm

Can someone help me out with a Matlab code for this.
For ISI chanell with real coeffnts and BPSK modulation write a Viterbi algo decoder with decoding delay >0 (say ‘delta’)

plot BER vs SNR for varying ‘delta’s

Srinivas June 27, 2009 at 10:13 pm

Can anyone help me out with a matlab code for this.
For ISI channel with L real coeffnts and BPSK modulation write a Viterbi algo decoder with decoding delay >0

Krishna Pillai June 30, 2009 at 5:10 am

@Srinivas: I have not done MLSE equalization in multipath channel, but plan to do that in near future.

jo June 23, 2009 at 9:14 pm

i wanna know what does this statement exactly do
ipHat = real(y)>0;

is it equivalent to
if real(y)>0
real(y)=1
else
real(y)=0
end

thanks

Krishna Pillai June 25, 2009 at 5:48 am

@jo: Plz refer the reply provided to ahmed

ahmed June 23, 2009 at 8:41 pm

Hello
ipHat = real(y)>0;
what exactly it do
is it equivalent to
if real(y)>0
real(y)=1
else
real(y)=1
end

Thx

Krishna Pillai June 25, 2009 at 5:47 am

@ahmed: No, your explanation is not correct. As komari mentioned, it is equivalent to
if (real(y)>0)
ipHat = 1
else
ipHat = 0
end

Ali June 23, 2009 at 8:36 pm

Ok Thanks very much krishna

komari June 22, 2009 at 11:20 pm

please can you tell me what does this instruction do exactly

ipHat = real(y)>0;

is it equivalent to
if (real(y)>0)
ipHat = 1
else
ipHat = 0
end

Thanks

Krishna Pillai June 23, 2009 at 4:40 am

As you may be aware, Matlab provides lots of ‘quick one liner’ ways to do things.

Swetha June 18, 2009 at 10:24 am

Hi All,

Can any one guide me to good source…
How to calculate Bit error probability for given SNR, any modulation technique with error correcting codes(convolution coding).

Please give some information on this.

-Thanks
Swetha

Krishna Pillai June 21, 2009 at 12:48 pm

@Sweta: The book Digital Communications by John Proakis is a good reference

RAO June 13, 2009 at 12:30 am

I want to plot BER vs Eb/No for MPSK and MDPSK. Can u help me in this regard ?

Also do u have code for FSK coherent and non-coherent with corresponding BER vs Eb/No plot?

Your early response will b highly appreciated.

Olguin June 10, 2009 at 2:55 pm

first of all, thanks a lot for ur job, it´s really useful for all the DSP internet communty.

here my question, I´m carrying out some simulations on simulink. modulating BPSK, spreading w/ gold code, going through awgn, despreading and demodulating BPSK, and at the end I measure the BER.

using simple BPSK mod/demod provided in the communications block set, I´ve got a relative high BER (.5), then I found the so-called “Real BPSK mod/demod” which basically a “real-imag to complex”/”complex to real-imag” block is added to the BPSK mod/demod, and the resulting BER is around .1.

I´ve tried to find unsuccessfully an explanation to this on technical literature.

maybe you know something about that.

Krishna Pillai June 11, 2009 at 4:49 am

@Olguin: Well, having BER of 0.5 means there is some error in the simulation code. If you wish you refer the post on
(a) BPSK BER with matched filtering
http://www.dsplog.com/2009/05/08/ber-with-matched-filtering/

Hope that helps you to debug the code.

RAO June 9, 2009 at 8:12 pm

Hello.

I need matlab code for DPSK and also its BER.

regards,

Krishna Pillai June 10, 2009 at 5:26 am

@RAO: I have a post on Coherent Demodulation of DBPSK
http://www.dsplog.com/2007/09/30/coherent-demodulation-of-dbpsk/
Hope this helps.

RAO June 10, 2009 at 3:58 pm

thanks Krishna.

Actually i need matlab code for non-coherent detection of either bpsk or dpsk and also corresponding BER vs Eb/No plots.

regards,

RAO June 10, 2009 at 4:00 pm

sorry. in addition, i want noncoherent detection of bpsk or dpsk for both AWGN AND RAYLEIGH channel.

regards,

Krishna Pillai June 11, 2009 at 4:50 am

@RAO: Sorry, I have not tried simulating non-coherent detection dpsk.

RAO June 12, 2009 at 5:12 pm

I want to plot BER vs Eb/No for MPSK and MDPSK. Can u help me in this regard ?

Also do u have code for FSK coherent and non-coherent with corresponding BER vs Eb/No plot?

Mathew June 9, 2009 at 6:21 pm

I mean 16-apsk modulation sth like that http://commons.wikimedia.org/wiki/File:Const_16APSK.gif

Krishna Pillai June 10, 2009 at 5:25 am

@Mathew: Sorry, I have not tried simulating 16-APSK. Thanks to you, I just realized that it is used in DVB-S2. I will try to do a write up in future.

Mathew June 8, 2009 at 2:37 am

Have you got any code to 16-apsk?

Krishna Pillai June 8, 2009 at 6:02 am
Assad Abbasi June 6, 2009 at 1:03 am

Dear Krishna, thanks for your codes. I am plotting BER for BPSK and QPSK but i am not getting same BER curve. As it should be same for both. I know that the plot should be BER vs EbN0. But how to get EbN0 from SNR? In your codes you have written Eb_N0_dB, is this EbN0?? I think it is SNR. If this is EbN0, why am i not getting same curve for BPSK and QPSK… Please Help

Krishna Pillai June 7, 2009 at 2:31 pm

@Assad Abbasi: Well, as you said BER vs EB/N0 curve for both BPSK and QPSK should be comparable. In general,
Es/N0 = kEb/N0, where k = log2(M) and M is the constellation size.

I have discussed a post comparing BPSK, QPSK, QAM etc @ http://www.dsplog.com/2008/07/08/compare-bpsk-qpsk-4pam-16qam-16psk-64qam-32psk/
Hope this helps.

Eduardo Solano June 4, 2009 at 1:55 am

i have a question..
i have a program wich makes bpsk modulation and i need to show Bit error curve for BPSK modulation – theory, simulation (both) as you do here in this page at top.

ok but there is something that happens with simulation curve that appears a little bit more to the right side of teoric curve.

i wanna know a reason why does it happens.

Krishna Pillai June 7, 2009 at 2:11 pm

@Eduardo Solano: If the simulation curve is happening to the right of the theoretical curve, it typically means that you are adding more noise than what is required. Also make sure that you simulate for atleast 10^6 bits, such that you get statistically accurate results.

M S Sasidhar June 2, 2009 at 1:15 pm

hi every body can any one tell me the code for “signal to noise ratio using autocorrelation in time domain” using MATLAB

Krishna Pillai June 7, 2009 at 1:57 pm

@sasidhar: The question is not clear to me. Can you please provide some more details….

maya May 31, 2009 at 10:26 pm

thnx for ur response,,it means dat u need to have atleast 2 no of rcvd bits at da reciever 2 be compared..but my confusion is that how to use vblast when i am considering diversity mimo,where i have to use combing technique first?? can i implement vblast in dat case or not???

Krishna Pillai June 1, 2009 at 5:22 am

@maya: Well, try to write the equation in matrix form. For eg, consider a simple case where we have two transmit antennas and 3 receive antennas. The matrix dimensions will be of:
y = Hx + n, where
y – received symbols of dimension [nrx x 1]
H – channel matrix of dimension [nrx x ntx]
x – transmit symbols of dimension [ntx x 1]
n – noise of dimension [nrx x 1]

If we write the zero forcing equalizer for this equation, then we can find that
W = (H^H*H)-1*H^H

This equalization also performs the diversity combining via Maximal Ratio Combining way. Does this help?

maya May 29, 2009 at 5:38 pm

HEY sir can u plzz help me in getting the main concept of vblast detection scheme,,i am not geting how it estimates the data…

Krishna Pillai May 31, 2009 at 8:43 pm

@maya: Well, understanding V-BLAST with Zero Forcing equalization is the most simplest way. From our linear algebra days, we know that if we have two unknowns, we need atleast two equations to solve them.

Adapting them to MIMO V-BLAST, the two unknowns are the unknown transmitted data, and the two equations are provided by the two receive antennas. Just putting a simple example,
y1 = a*x1 +b*x2
y2 = c*x1 + d*x2
where
a,b,c,d are channel taps (which are known) and
x1, x2 are unknown transmit symbols.

The following post might be of bit more help.
http://www.dsplog.com/2008/10/24/mimo-zero-forcing/

Hope this helps.

aam_log May 28, 2009 at 7:26 pm

Dear krishna
I hope you are fine. I am in 5th semister of my bachelors of telecommunications. So I am new to this field and facing lots of difficulties. I find your site very impressive and have joined it recently. Can you kindly tell me why we normalize things? thnx

Krishna Pillai May 31, 2009 at 8:36 pm

@aam_log: Good luck for your studies. We normalize, because we want to have a fair comparison when trying out different approaches….

For eg, if we are comparing 100apples with 100grapes, we would want to know the price per kilogram, no?

Ideal May 27, 2009 at 12:57 pm

Dear Krishna
how can we simulat the angular delay profile. can you just give me simple example plz?

Krishna Pillai May 31, 2009 at 8:31 pm

@Ideal: Sorry, am not familiar with modeling angular profile.

kanchana May 15, 2009 at 1:09 pm

hello sir

i am doing my project in cdma can u tell me the purpose of rake receiver and details about maximum ratio combining

Krishna Pillai May 20, 2009 at 5:24 am

@kanchana: Well, I have not quite discussed about cdma in the blog till date. Hope to do so in future.
I beleive the intent of the rake receiver is to coherently combine information from all the multipath taps such that the bit-error rate is reduced. I have posted about maximal ratio combining for a 1 transmit 2 receive receive diversity case.
http://www.dsplog.com/2008/09/28/maximal-ratio-combining/
Though the context is different, I think you should be able to adapt that to suit your needs.

Good luck.

Student May 12, 2009 at 6:04 pm

Dear Krishna Pillai

Thank u. I am really happy and trying to do what u have suggested.

Student May 6, 2009 at 8:17 am

Dear Krishna Pillai :

Regards,

Krishna Pillai May 12, 2009 at 5:16 am

@Student: I just did. Hope you are happy with the response. Sorry for the delay in my reply. Good luck.

bowang May 5, 2009 at 7:07 pm

wah ini dia data yang aku cari-cari akhirnya menemukan yang namanya BPSK
thanks yaaaaaaaaaaaaaaaa…
sip sip sip sip

Krishna Pillai May 12, 2009 at 5:10 am

@bowang: good

Elias April 30, 2009 at 1:42 pm

Bonjour
Je cherche des programmes MATLAB pour la génération des codes LDPC Quasi Ciclique
Alors si vous avez des programmes ou des liens utiles prière de me les envoyer a ce mail
Je vous remercie

Krishna Pillai May 12, 2009 at 4:42 am

@Elias: Sorry, I have not discussed LDPC coding till date. Hopefully in the near future.

Student April 30, 2009 at 9:37 am

Dear Krishna Pillai
Thanks a lot for ur suggestion.When I domodulate following code it gives a simple sine wave.How can I demodulate it?
close all
b=[0 1 1 0 1 0 1 0 0 1];
fc=10;
n=1;
while n<=length(b)
if b(n)==0 %0 is -1
tx=(n-1)*0.1:0.1/100:n*0.1;
m=(-1)*sin(2*pi*fc*tx);
plot(tx,m,’LineWidth’,1.5);grid on;
else
tx=(n-1)*0.1:0.1/100:n*0.1;
m=(1)*sin(2*pi*fc*tx);
subplot(2,1,1)
plot(tx,m,’LineWidth’,1.5);grid on;
hold on;
end
n=n+1;
end
title(‘BPSK modulated Signal’)

How coherent detection can be applied on it?

Regards,

Krishna Pillai May 12, 2009 at 4:39 am

@Student: hmm..let me try to understand. For bit0 you are sending -ve sine wave, and for bit1 you are sending +ve sinewave right. At the receiver you cmay undo the effect of the sine wave by multiplying the received signal with the sine wave and taking the mean. Then perform hard decision decoding on that signal.
Does that help?

bwk April 29, 2009 at 6:46 pm

Hi,
I would need equations of bit error probability for this modulation technique: MSK, GMSK, QPSK, ASK. Do you know it?

Krishna Pillai April 30, 2009 at 5:46 am

@bwk: I have not tried simulating MSK/GMSK. Something to do in future. However, you may look at the posts:
a/. Symbol error rate for QPSK
http://www.dsplog.com/2007/11/06/symbol-error-rate-for-4-qam/
b/. Symbol error rate for 4-PAM
http://www.dsplog.com/2007/10/07/symbol-error-rate-for-pam/

Student April 29, 2009 at 5:30 pm

Dear Krishna Pillai
How can I correlate demodulated signal and binary code in BPSK ?I mean reteriving back of binary code.

Krishna Pillai April 30, 2009 at 5:44 am

@Student: At the receiver, using hard decision decoding you can find out whether the received symbol is +1 or -1. Then we can easily map to +1 to bit1 and -1 to bit0 respectively.

Oluwafemi April 16, 2009 at 9:05 pm

Please i dont know how i can acess the e book.
I am working on super orthogonal space time turbo codes in OFDM systems and will need this e book .Thank u

Krishna Pillai April 18, 2009 at 8:11 am

Student April 13, 2009 at 12:30 pm

Dear Krishna Pillai :
How can I change Amplitude Modulation to BPSK(y1 = ammod(x1,Fc1,Fs) to bpsk . I hope for a positive response.
clc
close all
clear all

t = 0:0.00001:0.001;

Fc1 = 1000;

Fs = 12000;
y1 = 1;
x1 = cos(2*pi*1000*t);

in_p = input(‘\nDo you want to enter user Y/N: ‘,’s');

if(in_p == ‘Y’ | in_p == ‘y’)
y1 = ammod(x1,Fc1,Fs);
end

Krishna Pillai April 16, 2009 at 5:40 am

@Student: Sorry, I do not have the functions ammod(). Maybe the post on symbol error rate computation using 4-PAM be of help.
http://www.dsplog.com/2007/10/07/symbol-error-rate-for-pam/

Einsein April 12, 2009 at 8:29 pm

Hello,

Do you know how you can build a zero-crossing detector or delay-and-multiply detector for the FSK.

Thanks.

Krishna Pillai April 16, 2009 at 5:35 am

@Einsein: I have written a post on BER computation for FSK using coherent demodulation. That may provide some pointers
http://www.dsplog.com/2007/08/30/bit-error-rate-for-frequency-shift-keying-with-coherent-demodulation/
Hope this helps.

R@y April 12, 2009 at 12:49 am

Hi, can you help with this issue,consider QPSK transmission over flat fading Rayleigh channels and a 1×2 system.The channels on the different diversity branches are assumed to have the same variance and the noise samples are assumed to be uncorrelated and circularly symmetric Gaussian variables with the same variance.
Consider three combining schemes: MRC, EGC and SC, for plot the BER versus the average signal-to-noise ratio (SNR).
I hope you can help me

Krishna Pillai April 16, 2009 at 5:27 am

@R@y: Using BPSK modulation, I have written articles for a 1 transmit, 2receive system in a flat fading uncorrelated Rayleigh channel.
http://www.dsplog.com/2008/09/19/equal-gain-combining/
http://www.dsplog.com/2008/09/28/maximal-ratio-combining/
Hope this helps.

Murali Kris April 8, 2009 at 7:26 am

Hi Krishna,

All your posts have been very helpful and easily understandable. I was looking for a code that has all the modulations(bpsk,qpsk,mpsk,ask,bfsk,msk etc…) in a single program and to compare their BER, PSD curves. please let me know if you have any.

Thanks

Krishna Pillai April 11, 2009 at 6:48 am

@Murali: No, I have not posted a single code putting all the BER curves in a single plot. However, I have discussed about multiple modulation schemes in dspdesignline.com
http://www.dsplog.com/2008/07/08/compare-bpsk-qpsk-4pam-16qam-16psk-64qam-32psk/
Hope this helps.

Shahrukh April 1, 2009 at 8:35 pm

pls sumbody help me out!!!…………:(….

Shahrukh March 30, 2009 at 10:53 pm

Can someone pls provide me the matlab code for the below mentioned project work:

A randomly generated bit stream should be transmitted through an AWGN channel using BPSK. THe received symbols should then be converted again to a bit stream. The received bit stream should be compared with the original one to determine the total number of errors and hence the bit error probability. The probability of error should be calculated for several values of EB/No.
Once the above system is succesfully simulated an additional block of channel coding should be incorporated in the system. A (15,11) Hamming code should be used for this purpose. Simulation of this should be performed to increase the performance of the system.

RESULT to be DISPLAYED:

1. Bit error probability versus EB/No graph of BPSK
2. Bit error probability versus Eb/No graph of BPSK using equation
3.Bit error probability versus Eb/No graph of BPSK system with channel coding/decoding

The written code shuld allow the user to perform simulation for any number of bits and for any range of Eb/No.

THANKS..

Krishna Pillai April 4, 2009 at 4:26 pm

@Shahrukh: My replies:
1. Example Matlab code is provided in this post
2. The equation for BER for BPSK for a given value of Eb/N0 is provided in this post
3. I have not tried simulating with Hamming code. However, you may check the article on convolutional coding
with Viterbi decoding
http://www.dsplog.com/2009/01/04/viterbi/

Hope this helps.

shoumi March 18, 2009 at 2:47 pm

hi
How can i calculate throughtput for a multi-hop wireless network using matlab. please give me some suggestion ragarding this….

thanks

Krishna Pillai March 21, 2009 at 9:10 am

@shoumi: Sorry, am not familiar with modelng multi-hop networks.

Krishna Pillai March 21, 2009 at 9:11 am

@shoumi: Sory, I have not worked on modeling multihop wireless networks.

Krishna Pillai March 21, 2009 at 9:12 am

@shoumi: Sorry, I have not worked on modeling multihop wireless networks.

mrKim November 13, 2012 at 8:33 am

Dear Shoumi

Did you find material about calculate throughtput for a multi-hop wireless network using matlab ? Please share me if you have. I need it very much
my email: nguyenkimhieuha@gmail.com

Thank you

Nafis March 18, 2009 at 4:09 am

Thanks for your codes.It’s helped me a lot.But I want to replace Eb/N0 as SNR how can I do it.Could you pls help me urgently.

Thanking you

Krishna Pillai March 21, 2009 at 9:07 am

@Nafis: For BPSK. Eb/N0 is same as SNR. Agree?

Matt K March 17, 2009 at 7:13 pm

Hi there, very useful site. I have a couple of questions regarding the BPSK:

1) Could you go in to a little more detail why you use complex noise vs. real. Although it doesn’t make a difference for BPSK, I’m assuming it actually will with other modulation methods. I didn’t see this in any of my textbooks.

2) In your code for the BPSK, you divide by 20. Shouldn’t that be 10? Given an SNR in dB, we get S/N0 = 10*log(SNR-dB / 10).
This gives N0 for a given signal power S.
The variance^2 = N0/2 and if we assume 0 mean, this gives us our AWGN, which is a random variable describing the noise amplitude. In my simulation, if I use 10 instead of 20, my results were way off, but 10 gives a perfect match with theory.

Thanks much,
Matt

Krishna Pillai March 21, 2009 at 9:04 am

@ Matt K: My replies
1). Yes, for BPSK the noise component on the imaginary arm is ignored. To make the noise model same as with other modulation schemes, I kept it as complex.
2). The division by 20 is to convert the dB to scale the voltage signal. In my simulation model, the noise term n is a Gaussian random variable with mean 0 and variance 1. Therefore, I am scaling the noise voltage by 10^(-Eb_N0_dB(ii)/20)*n. Thats why I used 20.
In general, it depends on how one creates the model. Different people have different coding style. However, its the end result which matters.

Hope this helps.

nyna March 13, 2009 at 6:54 pm

tq krishna…i understand it more than before..i really appreciate it..
however can i ask u bout the graph of BPSK between simulation and theoretical in term of BER vs SNR…
how the shape of graph become like that?

Krishna Pillai March 21, 2009 at 7:53 am

@nyna: The shape of the curve is determined by the probability of error which we have defined in the post.

Aditya March 13, 2009 at 11:48 am

Hey krishna,

I am new here. I find this site really very useful. Thanks for everything. I have a question reg BPSK sim. I did it with awgn function and I am not getting theo and sim graphs overlapping. Please answer this as soon as you get time . thanks

Krishna Pillai March 21, 2009 at 7:44 am

@Aditya: You should have got similiar curves with awgn() function too. Is the slope of the graphs matching. Then its quite likely some power normalization issue.

shoumi March 10, 2009 at 1:25 pm

hi

I wanna matlab simulation code for AODV routing protocol. Can you help me ….

Krishna Pillai March 21, 2009 at 7:01 am

@shoumi: Sorry, I have not worked on AODV protocol.

nyna March 8, 2009 at 7:08 pm

krishna can u help to understand more about the function of transmitter filter in BPSK and also how the ISI(intersymbol interference)will occur at transmitter filter??

Krishna Pillai March 8, 2009 at 7:52 pm

@nyna: In the transmitter, we will first be converting bits into analog voltage (+1/-1 in the case of BPSK). However, we cannot transmit them as is, as it will occupy lots of spectrum (which is not desirable). Hence we need to do filtering. However, when doing filtering, we introduce ISI (inter symbol inteference) i.e each symbol may interfere with the next symbol and so on.

So, the question is: can we do filtering without introducing ISI? The answer is YES. There are simple filters like rectangular, ideal filter like sinc and practical filters like raised cosine, which can do the job. You may read more about them @
http://www.dsplog.com/2008/04/14/transmit-pulse-shape-nyquist-sinc-rectangular/
http://www.dsplog.com/2008/04/22/raised-cosine-filter-for-transmit-pulse-shaping/
http://www.dsplog.com/2008/05/01/eye-diagram-plot-matlab-raised-cosine-filter/

Hope this helps.

bullah March 3, 2009 at 10:58 pm

hai..krishna..i want ask you the function of hamming code and bCh code..it because i already simulate the block using that coding…can you give me the formula for i’m calculate theory the bit error rate when using coding for i compare between theory and simulate…..also can you give me the graph ber vs Eb/No when coding..tq

Krishna Pillai March 5, 2009 at 5:35 am

@bullah: Sorry, I have not discussed hamming codes or BCH codes till date. You may look at the posts describing convolutional coding and Viterbi decoding @
http://www.dsplog.com/tag/viterbi

Hope this helps.

Einstein March 2, 2009 at 3:38 pm

I want to do a matlab simulation for the the GFSK. Plot the BER vs. EbNo.

Krishna Pillai March 5, 2009 at 5:08 am

@Einstein: Sorry, I do not have Matlab simulations with GFSK. However, you may check up the post on BER for FSK in AWGN @
http://www.dsplog.com/2007/08/30/bit-error-rate-for-frequency-shift-keying-with-coherent-demodulation/

Hope this helps.

pragya August 23, 2009 at 1:28 am

sir,
i want matlab programs for MCCDMA,whtever u hve on dis topic ,plz mail me as soon as possible,since MCCDMA is my thesis topic, but i m facing many prblms regarding matlab programs

thank u,
pragya

Krishna Sankar August 24, 2009 at 4:59 am

@pragya: Sorry, I have not written Matlab models on MC-CDMA.

mohamed March 2, 2009 at 3:21 pm

The term 10^(-Eb_N0_dB(ii)/20) is for scaling the noise power as per the defined bit to noise ratio, why divided it by 20 >>??to convert it to voltage

Krishna Pillai March 5, 2009 at 5:05 am

@mohamed: Yes, divided it by 20 is to convert to voltage.

santosh February 21, 2009 at 10:40 pm

mansi February 21, 2009 at 11:09 am

hi i have plotted the results for some coding
i just want is biterr with no coding

i.e. simply take msg, modulate add noise and demodulate

now find the biterr or symerr for oiginal msg and recovered msg

pls help as early as possible