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	<title>Comments on: BER for BPSK in ISI channel with Zero Forcing equalization</title>
	<atom:link href="http://www.dsplog.com/2009/11/29/ber-bpsk-isi-channel-zero-forcing-equalization/feed/" rel="self" type="application/rss+xml" />
	<link>http://www.dsplog.com/2009/11/29/ber-bpsk-isi-channel-zero-forcing-equalization/</link>
	<description>Signal Processing for Communication</description>
	<lastBuildDate>Fri, 30 Jul 2010 01:36:27 +0000</lastBuildDate>
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		<item>
		<title>By: Krishna Sankar</title>
		<link>http://www.dsplog.com/2009/11/29/ber-bpsk-isi-channel-zero-forcing-equalization/#comment-32251</link>
		<dc:creator>Krishna Sankar</dc:creator>
		<pubDate>Mon, 28 Jun 2010 01:17:16 +0000</pubDate>
		<guid isPermaLink="false">http://www.dsplog.com/?p=857#comment-32251</guid>
		<description>@vsk: In a MIMO ISI case, convolve each transmit stream with the channel seen from each transmit stream to receive antenna. 
For eg, if 
h11 - channel between transmit antenna 1 to receive antenna 1
h12 - channel between transmit antenna 2 to receive antenna 1
h21 - channel between transmit antenna 1 to receive antenna 2
h22 - channel between transmit antenna 2 to receive antenna 2

The received symbol on receive antenna 1
y1 = conv(h11,x1) + conv(h12,x2) + n1
y2 = conv(h21,x1) + conv(h22,x2) + n2
and x1, x2 are transmit symbols from antenna 1 and 2 respectively.

Do NOT sum all the impulse response and represent them as a single value.</description>
		<content:encoded><![CDATA[<p>@vsk: In a MIMO ISI case, convolve each transmit stream with the channel seen from each transmit stream to receive antenna.<br />
For eg, if<br />
h11 &#8211; channel between transmit antenna 1 to receive antenna 1<br />
h12 &#8211; channel between transmit antenna 2 to receive antenna 1<br />
h21 &#8211; channel between transmit antenna 1 to receive antenna 2<br />
h22 &#8211; channel between transmit antenna 2 to receive antenna 2</p>
<p>The received symbol on receive antenna 1<br />
y1 = conv(h11,x1) + conv(h12,x2) + n1<br />
y2 = conv(h21,x1) + conv(h22,x2) + n2<br />
and x1, x2 are transmit symbols from antenna 1 and 2 respectively.</p>
<p>Do NOT sum all the impulse response and represent them as a single value.</p>
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	<item>
		<title>By: vsk</title>
		<link>http://www.dsplog.com/2009/11/29/ber-bpsk-isi-channel-zero-forcing-equalization/#comment-32133</link>
		<dc:creator>vsk</dc:creator>
		<pubDate>Fri, 25 Jun 2010 21:16:23 +0000</pubDate>
		<guid isPermaLink="false">http://www.dsplog.com/?p=857#comment-32133</guid>
		<description>Hi Mr.Krishna,
For a MIMO system, how do I model an ISI channel? Meaning do I sum the impulse responses for the various paths from antenna i to antenna j and denote it as a single co efficient in the H matrix as h(ji)?
And so how do I perform ZF-SIC for the same case?</description>
		<content:encoded><![CDATA[<p>Hi Mr.Krishna,<br />
For a MIMO system, how do I model an ISI channel? Meaning do I sum the impulse responses for the various paths from antenna i to antenna j and denote it as a single co efficient in the H matrix as h(ji)?<br />
And so how do I perform ZF-SIC for the same case?</p>
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	</item>
	<item>
		<title>By: Krishna Sankar</title>
		<link>http://www.dsplog.com/2009/11/29/ber-bpsk-isi-channel-zero-forcing-equalization/#comment-26364</link>
		<dc:creator>Krishna Sankar</dc:creator>
		<pubDate>Sun, 18 Apr 2010 09:16:39 +0000</pubDate>
		<guid isPermaLink="false">http://www.dsplog.com/?p=857#comment-26364</guid>
		<description>@Ali: Try changing the creation of the Toeplitz matrix such that h3 comes in the diagonal term...</description>
		<content:encoded><![CDATA[<p>@Ali: Try changing the creation of the Toeplitz matrix such that h3 comes in the diagonal term&#8230;</p>
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	</item>
	<item>
		<title>By: Krishna Sankar</title>
		<link>http://www.dsplog.com/2009/11/29/ber-bpsk-isi-channel-zero-forcing-equalization/#comment-26360</link>
		<dc:creator>Krishna Sankar</dc:creator>
		<pubDate>Sun, 18 Apr 2010 09:11:24 +0000</pubDate>
		<guid isPermaLink="false">http://www.dsplog.com/?p=857#comment-26360</guid>
		<description>@Newbie: A channel whose taps do not vary with time is a time invariant channel :)</description>
		<content:encoded><![CDATA[<p>@Newbie: A channel whose taps do not vary with time is a time invariant channel <img src='http://www.dsplog.com/db-install/wp-includes/images/smilies/icon_smile.gif' alt=':)' class='wp-smiley' /> </p>
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	</item>
	<item>
		<title>By: Ali</title>
		<link>http://www.dsplog.com/2009/11/29/ber-bpsk-isi-channel-zero-forcing-equalization/#comment-25963</link>
		<dc:creator>Ali</dc:creator>
		<pubDate>Thu, 15 Apr 2010 16:33:18 +0000</pubDate>
		<guid isPermaLink="false">http://www.dsplog.com/?p=857#comment-25963</guid>
		<description>Hi i have a question regarding the ZF-equlization, what if the desired tap is at the last position?
h = [0.3 0.1 0.9]. I tried to change the code but i could not.</description>
		<content:encoded><![CDATA[<p>Hi i have a question regarding the ZF-equlization, what if the desired tap is at the last position?<br />
h = [0.3 0.1 0.9]. I tried to change the code but i could not.</p>
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	<item>
		<title>By: Newbie</title>
		<link>http://www.dsplog.com/2009/11/29/ber-bpsk-isi-channel-zero-forcing-equalization/#comment-25874</link>
		<dc:creator>Newbie</dc:creator>
		<pubDate>Wed, 14 Apr 2010 14:58:14 +0000</pubDate>
		<guid isPermaLink="false">http://www.dsplog.com/?p=857#comment-25874</guid>
		<description>Hiii Mr.Krishna

Thank you for ur post, that is help me so much. That is time invariant channel???</description>
		<content:encoded><![CDATA[<p>Hiii Mr.Krishna</p>
<p>Thank you for ur post, that is help me so much. That is time invariant channel???</p>
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	</item>
	<item>
		<title>By: Krishna Sankar</title>
		<link>http://www.dsplog.com/2009/11/29/ber-bpsk-isi-channel-zero-forcing-equalization/#comment-24721</link>
		<dc:creator>Krishna Sankar</dc:creator>
		<pubDate>Sat, 03 Apr 2010 23:50:28 +0000</pubDate>
		<guid isPermaLink="false">http://www.dsplog.com/?p=857#comment-24721</guid>
		<description>@Ananthi: Thanks</description>
		<content:encoded><![CDATA[<p>@Ananthi: Thanks</p>
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