Comments on: Linear to log conversion http://www.dsplog.com/2008/11/20/linear-to-log-conversion/ Signal Processing for Communication Thu, 04 Mar 2010 16:31:39 +0530 http://wordpress.org/?v=2.8.4 hourly 1 By: Krishna Sankar http://www.dsplog.com/2008/11/20/linear-to-log-conversion/#comment-16641 Krishna Sankar Sun, 06 Dec 2009 11:32:07 +0000 http://www.dsplog.com/?p=263#comment-16641 @Sibo: Well, did the idea in this post help you? @Sibo: Well, did the idea in this post help you?

]]> By: Sibo http://www.dsplog.com/2008/11/20/linear-to-log-conversion/#comment-15901 Sibo Mon, 23 Nov 2009 06:51:01 +0000 http://www.dsplog.com/?p=263#comment-15901 i need help i have to builld an audio power meter, right am stuk i need a linear to logarithm converter circuit i need help i have to builld an audio power meter, right am stuk i need a linear to logarithm converter circuit

]]> By: Krishna Pillai http://www.dsplog.com/2008/11/20/linear-to-log-conversion/#comment-3297 Krishna Pillai Wed, 03 Dec 2008 01:02:04 +0000 http://www.dsplog.com/?p=263#comment-3297 @sandeep: Oh, yes :) I corrected the equation in the post to j = (N/2^E -1)2^k. Thanks for the close review. @sandeep: Oh, yes :) I corrected the equation in the post to j = (N/2^E -1)2^k.
Thanks for the close review.

]]> By: sandeep http://www.dsplog.com/2008/11/20/linear-to-log-conversion/#comment-3287 sandeep Tue, 02 Dec 2008 04:27:27 +0000 http://www.dsplog.com/?p=263#comment-3287 Guess I was not clear. In your write-up you have written j = (M/2^E -1)2^k. Agee? Now in Matlab code it is j = (N/2^E -1)2^k. Agree? if yes then both doesnot match. Guess I was not clear. In your write-up you have written
j = (M/2^E -1)2^k. Agee? Now in Matlab code it is
j = (N/2^E -1)2^k. Agree? if yes then both doesnot match.

]]> By: Krishna Pillai http://www.dsplog.com/2008/11/20/linear-to-log-conversion/#comment-3279 Krishna Pillai Tue, 02 Dec 2008 01:20:37 +0000 http://www.dsplog.com/?p=263#comment-3279 @sandeep: No, it is indeed M. The index j is used for finding only the mantissa part. k need not be related to bitwidth of N. k just defines the depth of the LUT; higher the value of k, better the precision. Makes sense? @sandeep: No, it is indeed M. The index j is used for finding only the mantissa part.

k need not be related to bitwidth of N. k just defines the depth of the LUT; higher the value of k, better the precision.

Makes sense?

]]> By: sandeep http://www.dsplog.com/2008/11/20/linear-to-log-conversion/#comment-3265 sandeep Mon, 01 Dec 2008 09:25:28 +0000 http://www.dsplog.com/?p=263#comment-3265 Hi Nice article..Some minor correction In equation for j, there should N instead of M. Also i think choice of k should be related to bit width of N. Have you defined it? Regards Hi
Nice article..Some minor correction
In equation for j, there should N instead of M.
Also i think choice of k should be related to bit width of N. Have you defined it?
Regards

]]> By: Krishna Pillai http://www.dsplog.com/2008/11/20/linear-to-log-conversion/#comment-3172 Krishna Pillai Tue, 25 Nov 2008 01:01:55 +0000 http://www.dsplog.com/?p=263#comment-3172 @vasundhara: Sorry, I do not have the source code. Typically I only try to help the reader to debug the model rather than writing the code myself. Kindly do email if you have explicit queries. @vasundhara: Sorry, I do not have the source code. Typically I only try to help the reader to debug the model rather than writing the code myself. Kindly do email if you have explicit queries.

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