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	<title>Comments on: Rayleigh multipath channel model</title>
	<atom:link href="http://www.dsplog.com/2008/07/14/rayleigh-multipath-channel/feed/" rel="self" type="application/rss+xml" />
	<link>http://www.dsplog.com/2008/07/14/rayleigh-multipath-channel/</link>
	<description>Signal Processing for Communication</description>
	<lastBuildDate>Thu, 04 Mar 2010 16:31:39 +0530</lastBuildDate>
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		<item>
		<title>By: Bala</title>
		<link>http://www.dsplog.com/2008/07/14/rayleigh-multipath-channel/#comment-21756</link>
		<dc:creator>Bala</dc:creator>
		<pubDate>Sat, 27 Feb 2010 08:53:05 +0000</pubDate>
		<guid isPermaLink="false">http://www.dsplog.com/?p=194#comment-21756</guid>
		<description>Hi,

I am trying to related the number of Tap of Rayleigh fading with its RMS delay spread.

kmax = ceil (5*tau/Ts);
profile = exp(-(0:kmax)*Ts/tau);
profile = profile/(sum(profile));
channel = sqrt(profile/2).*(randn(size(profile))+j*randn(size(profile)));

I found this code somewhere online and does this help?

For OFDM the symbol duration, TS = 4us and im looking at tau(rms delay spread) = 75ns. In the end, i only get 2 Taps. Is this correct?</description>
		<content:encoded><![CDATA[<p>Hi,</p>
<p>I am trying to related the number of Tap of Rayleigh fading with its RMS delay spread.</p>
<p>kmax = ceil (5*tau/Ts);<br />
profile = exp(-(0:kmax)*Ts/tau);<br />
profile = profile/(sum(profile));<br />
channel = sqrt(profile/2).*(randn(size(profile))+j*randn(size(profile)));</p>
<p>I found this code somewhere online and does this help?</p>
<p>For OFDM the symbol duration, TS = 4us and im looking at tau(rms delay spread) = 75ns. In the end, i only get 2 Taps. Is this correct?</p>
]]></content:encoded>
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	<item>
		<title>By: Geethu</title>
		<link>http://www.dsplog.com/2008/07/14/rayleigh-multipath-channel/#comment-20010</link>
		<dc:creator>Geethu</dc:creator>
		<pubDate>Tue, 09 Feb 2010 18:33:34 +0000</pubDate>
		<guid isPermaLink="false">http://www.dsplog.com/?p=194#comment-20010</guid>
		<description>I would like to know if there is an option to import results from matlab to open WNS for simulation purpose. If yes how. Thanks in advance</description>
		<content:encoded><![CDATA[<p>I would like to know if there is an option to import results from matlab to open WNS for simulation purpose. If yes how. Thanks in advance</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: Ahmed</title>
		<link>http://www.dsplog.com/2008/07/14/rayleigh-multipath-channel/#comment-19944</link>
		<dc:creator>Ahmed</dc:creator>
		<pubDate>Mon, 08 Feb 2010 10:58:09 +0000</pubDate>
		<guid isPermaLink="false">http://www.dsplog.com/?p=194#comment-19944</guid>
		<description>Hi Krishna,
Thank you very very much
If the channel became Nakagami-m multipath fading channel,How to present this type of channel.
Thank you again</description>
		<content:encoded><![CDATA[<p>Hi Krishna,<br />
Thank you very very much<br />
If the channel became Nakagami-m multipath fading channel,How to present this type of channel.<br />
Thank you again</p>
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	</item>
	<item>
		<title>By: Jun</title>
		<link>http://www.dsplog.com/2008/07/14/rayleigh-multipath-channel/#comment-18955</link>
		<dc:creator>Jun</dc:creator>
		<pubDate>Mon, 01 Feb 2010 20:30:45 +0000</pubDate>
		<guid isPermaLink="false">http://www.dsplog.com/?p=194#comment-18955</guid>
		<description>Dear Krishna,
when i am doing the simulation of the rayleigh channel.I choose the formula  r(t)=sum[ an(t)*x(t-tau(t))].
My question is how can i generate the attenuation an(t)?

Best regards,</description>
		<content:encoded><![CDATA[<p>Dear Krishna,<br />
when i am doing the simulation of the rayleigh channel.I choose the formula  r(t)=sum[ an(t)*x(t-tau(t))].<br />
My question is how can i generate the attenuation an(t)?</p>
<p>Best regards,</p>
]]></content:encoded>
	</item>
	<item>
		<title>By: Ghani</title>
		<link>http://www.dsplog.com/2008/07/14/rayleigh-multipath-channel/#comment-18433</link>
		<dc:creator>Ghani</dc:creator>
		<pubDate>Sun, 24 Jan 2010 20:04:33 +0000</pubDate>
		<guid isPermaLink="false">http://www.dsplog.com/?p=194#comment-18433</guid>
		<description>Hello krishnan sir

Could you kindly send me some code where there are multiple users and each is assigned a signature waveform(DS-CDMA). I need this is study the BER of such system.

Awaiting ur reply.
Thanks in advance</description>
		<content:encoded><![CDATA[<p>Hello krishnan sir</p>
<p>Could you kindly send me some code where there are multiple users and each is assigned a signature waveform(DS-CDMA). I need this is study the BER of such system.</p>
<p>Awaiting ur reply.<br />
Thanks in advance</p>
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	</item>
	<item>
		<title>By: Pon Chitra</title>
		<link>http://www.dsplog.com/2008/07/14/rayleigh-multipath-channel/#comment-18386</link>
		<dc:creator>Pon Chitra</dc:creator>
		<pubDate>Sat, 23 Jan 2010 12:20:14 +0000</pubDate>
		<guid isPermaLink="false">http://www.dsplog.com/?p=194#comment-18386</guid>
		<description>Krishnan Sir, 
can u tell me how to do channel estimation for OFDM System with pilot symbol intoduced . The pilots are introduced in block type. The channel estimation has to be done by LS method.</description>
		<content:encoded><![CDATA[<p>Krishnan Sir,<br />
can u tell me how to do channel estimation for OFDM System with pilot symbol intoduced . The pilots are introduced in block type. The channel estimation has to be done by LS method.</p>
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	</item>
	<item>
		<title>By: A Mehboob</title>
		<link>http://www.dsplog.com/2008/07/14/rayleigh-multipath-channel/#comment-17935</link>
		<dc:creator>A Mehboob</dc:creator>
		<pubDate>Fri, 08 Jan 2010 16:33:06 +0000</pubDate>
		<guid isPermaLink="false">http://www.dsplog.com/?p=194#comment-17935</guid>
		<description>Dear Krishna
In your post you said theta(n)=2*pi*fc*Tao(n) is the phase of the nth path; what does it mean? is it the phase delay introduced by nth path? If so then how can we say that? I mean we know the overall delay introduced by all paths is basically the phase response but how can we say it to individual path?

Thanks
Anser</description>
		<content:encoded><![CDATA[<p>Dear Krishna<br />
In your post you said theta(n)=2*pi*fc*Tao(n) is the phase of the nth path; what does it mean? is it the phase delay introduced by nth path? If so then how can we say that? I mean we know the overall delay introduced by all paths is basically the phase response but how can we say it to individual path?</p>
<p>Thanks<br />
Anser</p>
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